Akhenaten
Heretic Pharaoh
Pixel,
- Correct.
Jabba incorrect.
And so it goes.
Do you actually have an explanation for this balderdash or are you just making it up as you go?
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Pixel,
- Correct.
Akhenaten,Why has the expression "not playing with a full deck" become lodged in my consciousness?
So the scientific consensus predicts lots of "decks full of aces" now as a result of events unfolding according to the laws of nature, and lots of "decks full of aces" is exactly what we have. So how is this evidence against the scientific consensus?Pixel,
- Correct.
Akhenaten,
- Sorry.
- But that was too good a straight line to ignore... Maybe, you aren't playing with a full deck?
So the scientific consensus predicts lots of "decks full of aces" now as a result of events unfolding according to the laws of nature, and lots of "decks full of aces" is exactly what we have. So how is this evidence against the scientific consensus?
Your conclusion doesn't even attempt to follow your premises.Agatha,
- I contend that such poses serious reservations to the current, consensus, scientific position that each "self" is the result of entirely specific physical events and will exist for one finite life at most. Given that hypothesis, you shouldn't be here -- and especially, you shouldn't be here now.
- I can see now that a deck full of aces is misleading. I should have used a deck full of fives, or a deck full of eights -- or whatever.
- It's the cards all carrying the same number that would begin to suggest that this was not a normal deck. Them being all aces is basically irrelevant.
the probability of drawing any four cards from a fair deck if the card is replaced and the pack shuffled after each drawing remains at (1/52)^4
But in the scenario he's describing, he's simply getting four cards in a row with the same face value. In which case, the odds of this happening are (1./13)^4 or 1 in 28,561,
But in the scenario he's describing, he's simply getting four cards in a row with the same face value. In which case, the odds of this happening are (1./13)^4 or 1 in 28,561,
I believe he specified 4 different aces...
I believe he specified 4 different aces...
What he actually said was:
You sit down at the table and turn over the first card. It's an ace of spades. You place the ace back in the deck, shuffle the cards and once again, turn over the first card. This time, it's the ace of diamonds. Hmm. So, you try the same thing again. This time, you get the ace of spades again.
That's only three different aces, he got the ace of spades twice.
What he actually said was:
That's only three different aces, he got the ace of spades twice.
You are correct, and I have missed that all along. as I calculate, all that would do is change the stipulated hand...not the odds. Not so? 1/52^4?
You are correct, and I have missed that all along. as I calculate, all that would do is change the stipulated hand...not the odds. Not so? 1/52^4?
I took that to mean any combination of aces, not the specific combination in the example.
And even if he meant that exact same hand in that exact same order, it might be (1/54)^4 if the jokers are still in the pack.![]()
I took that to mean any combination of aces, not the specific combination in the example.
And even if he meant that exact same hand in that exact same order, it might be (1/54)^4 if the jokers are still in the pack.![]()
I notice he's not rushing to clarify precisely what he meant...
I was bored one day and created a bunch of them, this album.Thanks! They should put it in the list of smilies.
Already been done by John Wyndham in Trouble With Lichen, and no doubt other authors too.Toontown,
- Interesting point.
- I used to write unpublished science fiction short stories. An unwritten idea I had was about "civilization" after science proves immortality.
Already been done by John Wyndham in Trouble With Lichen, and no doubt other authors too.