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[Merged] Immortality & Bayesian Statistics

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Jabba

Philosopher
Jabba
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Feb 23, 2012
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- I think that I can essentially prove immortality using Bayesian statistics.
- If this belongs in a different thread, or has already been done, please let me know. Otherwise, I'll present my case here.
--- Jabba
 
Jabba said:
- I think that I can essentially prove immortality using Bayesian statistics.
- If this belongs in a different thread, or has already been done, please let me know. Otherwise, I'll present my case here.
--- Jabba
Click to expand...

I could probably construct a logically sound argument that city buses do not exist.

Would you then walk in front of one?
 
Jabba said:
- I think that I can essentially prove immortality using Bayesian statistics.
- If this belongs in a different thread, or has already been done, please let me know. Otherwise, I'll present my case here.
--- Jabba
Click to expand...

Prior evidence of anybody being immortal = 0
Evidence that we are bound to die , if only because of the way DNA reproduce during cell division = pretty much all we know on biology
Evidence that the universe will die a "heat death" and be unable to support life = plenty

*twiddle thumb* now I am waiting impatiently for your mathematical proof of immortality.
 
Good to see that your posting habits haven't changed, Jabba. You create a brand new thread and in the OP, rather than saying what you created the thread to say, you tell everybody that you will, at some indeterminate point in the future, post something connected to what it is that you want to say.

I wait your next post, in which you give us a bullet-pointed list as to why you're not saying what you want to say, but will any day now, honest, with baited breath.
 
Jabba said:
- I think that I can essentially prove immortality using Bayesian statistics.
- If this belongs in a different thread, or has already been done, please let me know. Otherwise, I'll present my case here.--- Jabba
Click to expand...


I hope you're not going to pretend this is some kind of courtroom in this thread too.

Statisticians will not be happy.
 
Go on then, Jabba, present your proof.

I don't know if you've noticed that nobody actually *is* immortal, though.
 
Even money on the Wandering Jew, he will be around until the second coming, therefore immortal.
 
It wouldn't surprise me, Dafydd. Mind you, the thread was started over an hour ago and Jabba hasn't posted what ought to have been the opening post yet.
 
Agatha said:
It wouldn't surprise me, Dafydd. Mind you, the thread was started over an hour ago and Jabba hasn't posted what ought to have been the opening post yet.
Click to expand...

Don't worry, he will be back to tell us that he will be telling us that he will be posting the proof, sometime. This is just to distract our attention from his failed shroud thread.
 
Jabba said:
- I think that I can essentially prove immortality using Bayesian statistics.
- If this belongs in a different thread, or has already been done, please let me know. Otherwise, I'll present my case here.
--- Jabba
Click to expand...


The one at

Jabba said:
Resume,
- Obviously, this will only meet with derision, but I can't resist pointing it out anyway -- I'm actually a certified Statistician, and LOVE probability. Take a look at
...messiahornot.com/ACT2Scene1.ph,
...messiahornot.com/Act2Scene2.ph and
...messiahornot.com/Virtually1.php
-- if you dare.
--- Jabba
Click to expand...


You could start by answering the question I asked in the shroud thread:

Humots said:
By the way, if you are actually using Bayes' Theorem in your argument, shouldn't the initial formula for your probability be (assuming P(NR) + P(R) = 1.0)

P(NR|me & k) = P(me & k|NR)P(NR) / (P(me & k|NR)P(NR) + P(me & k|R)P(R))?
Click to expand...


If so, how do you get from that expression to the one in your argument:

P(NR|me & k) = P(me|NR)P(NR|k) / (P(me|NR)P(NR|k) + P(me|R)P(R|k))

Also, can you tell us a bit about being a certified Statistician? Like what courses are required, and what organization does the certifying?
 
Humots said:
The one at




You could start by answering the question I asked in the shroud thread:




If so, how do you get from that expression to the one in your argument:

P(NR|me & k) = P(me|NR)P(NR|k) / (P(me|NR)P(NR|k) + P(me|R)P(R|k))

Also, can you tell us a bit about being a certified Statistician? Like what courses are required, and what organization does the certifying?
Click to expand...

Silence, while frantic googling takes place.
 
I will give it a shot:

I'z= B

You'z= A

Them'z=C

We'z=O

Us'z = N

Bacon is delicious hence people are immortal
 
Fantastic, Jabba.
I'm looking forward to seeing your definition of immortality.
 
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