Not show SR and GR ARE flawed but are LIKELY flawed and how and why.
Ok, SR and GR pro-port to predict physical phenomenon. I will expect to see how experimental data does not match predictions.
1 - Anything physical must be physical in every frame.
Ok. I don't see how this relates to SR or GR. Also, this doesn't mention experimental data or internal contractions of either theory, but I'm following along.
2 - Under #1 above that means any clock with a dilated tick rate due to having gone under an acceleration (frame switching)
Acceleration and frame switching are not the same thing.
IS ticking slower than a resting clock.
This isn't what SR (or GR) says. Its like saying that F=ma indicates that things accelerate. Sure under the F=ma equivalence, things accelerate, but the context under which they accelerate is the entire basis of the relation.
3 - That physical condition must be retained when switching frame views.
Again, that isn't quite what SR says. It just indicates a set of coordinate system translations to be performed when switching inertial reference frames when dealing with coordinates in euclidean space with a separate time dimension. SR with Mankowski space doesn't need them.
That is velocity is a computed value of the ratio of change in physical distance per change in measured time or v - ds/dt.
No, that isn't how velocity is computed. That is how average velocity is computed. Additionally, you are using a term I'm not familiar with "physical distance". How does "physical distance" differ from "distance".
4 - Given t1 = 1, t2 = 0.5t1 and ds=1 then:
v1 = ds/t1 = 1 / 1 = 1
v2 = ds / t2 = 1 / 0.5 = 2
You haven't given any context. Are you making a calculation from some inertial frame of reference while something passes by at some velocity (crossing distance 1 in 1 time period)? So v1 indicates the velocity of that body in the first inertial frame of reference. Are you trying to compute in the second equation the velocity that the probe measures itself crossing the markers that are 1 distance unit apart in the first inertial reference frame? If so, your math is wrong. You translated the time coordinate, but not the space coordinate. Its a rotation, you are trading time "distances" for space "distances". Here, let me fix it for you
v2 = ds2 / t2 = 0.5 / 0.5 = 1
5 - When comparative tick rates are properly retained can trip time be correct is if ds remains unchanged and observer 2 computes a different relative velocity.
Why? Additionally, this idea of different observers calculating different relative velocities gives rise to the necessity of a preferred inertial reference frame. One in which any other reference frame moving relative to that preferred reference frame will calculate a higher velocity than the vice versa. This would be extremely easy to prove experimentally as the laws of physics would seem to differ when moving at different velocities relative to the preferred reference frame. Can you provide us with such as experiment that will turn physics on its head? Oh, wait, I forgot, you are attempting to show how SR or GR are internally inconsistent or disagree with some current experimental data. How are you showing this again?