Moderated Iron sun with Aether batteries...

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Come on. I'm not looking for the anything other than a ballpark figure on the circumference of the RD sphere at 171A?

Sometimes repetition is the only thing that works. Same answer as before---the prediction you're asking for is a stupid one which doesn't test the model. I explained why and you ignored it. Let's try again:

Michael, please answer a few simple questions.

a) Did I or did I not explain where an optically-thin corona layer will show up in 2D projection? Was there something wrong with that explanation?

b) Did I or did I not explain where a self-semi-opaque corona layer will show up in 2D projection? Was there something wrong with that explanation?

c) Did I or did I not explain where a externally-absorbed corona layer will show up in 2D projection? Was there something wrong with that explanation?

I will stand by my baseball and cat-tail predictions, by the way.
 
Dear Mr. Spock,

Since you were so kind to give GM a hand on his last project about how far GM thinks I can see into the atmosphere, and you obviously have the angle stuff down pat, could you please be so kind as to help him again with his RD image project? He seems to be the resident expert on things related to RD images so the two of you should be able to work out something.

I'm not looking for anything fancy, just a simple "ballpark" will do. I'm specifically interested in 171A, and I'll be happy with 1200KM either direction. Anything close will do, so long as we have some way to distinguish between the two theories. I just want to know what you think the circumference of the RD sphere will be.


You want to know the circumference of the Sun? About 4.37 million kilometers. No need to get your misunderstanding of running difference images in the mix. That's just confusing the issue.
 
Come on. I'm not looking for the anything other than a ballpark figure on the circumference of the RD sphere at 171A?

Michael, no one is going to answer your question. Do you know why?

According to the SSM, the 171A radiation originates somewhere in the chromosphere or above. So the sphere where it originates does indeed have a larger radius than the photosphere does.

But what you seem to be incapable of comprehending is that the radius of the circle one sees in a 2D image, RD or not, cannot be simply converted into the radius of that sphere. To do that conversion requires a very detailed knowledge of the corona and chromosphere, which no one here has (and possibly no one has, I don't know).

So we can't answer your question, both because it's nonsense and because even the slightly more sensible version of it (what's the radius of the bright ring on the 171A image, for example) requires knowledge none of us have access to.
 
Come on. I'm not looking for the anything other than a ballpark figure on the circumference of the RD sphere at 171A?


There is no such thing as a "figure on the circumference of the RD sphere at 171A". That's a string of words, yes, and they are pretty much all English, yes, but the way they're strung together makes the combination meaningless.
 
http://www.solarviews.com/eng/tracepr2.htm

The moss consists of hot gas at about two million degrees Fahrenheit which emits extreme ultraviolet light observed by the TRACE instrument. It occurs in large patches, about 6,000 - 12,000 miles in extent, and appears between 1,000 - 1,500 miles above the Sun's visible surface, sometimes reaching more than 3,000 miles high. It looks "spongy" because the patches are composed of small bright elements interlaced with dark voids in the TRACE images. These voids are caused by jets of cooler gas from the Sun's lower atmosphere, the chromosphere, which is at about 10,000 degrees Fahrenheit. The bright moss elements move around and can vary in brightness over very short periods of time -- 30 seconds or less.

Emphasis mine. Does that help?
 
There is no such thing as a "figure on the circumference of the RD sphere at 171A". That's a string of words, yes, and they are pretty much all English, yes, but the way they're strung together makes the combination meaningless.
20050527-0713.JPG


20050527-0713.JPG

20050527-1313.JPG


Those are three separate RD images (from NASA). You can't see a sphere and a figure out a circumference?
 


Now you're talking about a phenomenon that is occurring some 1500 to 2500 kilometers above the photosphere. So in light of your previous unintelligible ramblings about something you imagine you see, through 80,000 kilometers of opaque plasma, that supposedly exists 4800 kilometers into the photosphere, does that help? Not a lick. It's nonsense. Totally and completely unrelated nonsense.
 

No, that doesn't "help". Knowing that the cloud is a 3D sphere at Rsun+1500km does not tell you what its 2D projection looks like. Its 2D projection might end at Rsun+1500km if this material is very optically thin. Or it might end centerwards of Rsun if there's another shell of absorber (even a very thin one) slightly further out. Or it might trickle out to Rsun (but not brighten much on the way) if it's optically thick. Understand?
 
Ok, start with a diameter then. Anything will do. Please, just come up with a way to differentiate between standard theory and the predictions I have made. I'm not looking for anything fancy.
 
Those are three separate RD images (from NASA). You can't see a sphere and a figure out a circumference?

I do not see a sphere. I see a disk. A disk is the projection of a 3D sphere onto 2D, and such projections are complicated by viewing angle and absorption issues. Do any of these words ring a bell?

"2D" is an interesting word, I wonder if it has ever come up on this thread before ...
 
[qimg]http://www.thesurfaceofthesun.com/images/20050527-0713.JPG[/qimg]

[qimg]http://www.thesurfaceofthesun.com/images/20050527-0713.JPG[/qimg]
[qimg]http://www.thesurfaceofthesun.com/images/20050527-1313.JPG[/qimg]

Those are three separate RD images (from NASA). You can't see a sphere and a figure out a circumference?


A sphere is a three dimensional object. Those running difference graphs are two dimensional renderings of mathematical calculations based on comparisons between sequences of thermal data gathered over a period of time.

And the circumference of the Sun is still about 4.37 million kilometers.
 
I do not see a sphere. I see a disk. A disk is the projection of a 3D sphere onto 2D, and such projections are complicated by viewing angle and absorption issues. Do any of these words ring a bell?

"2D" is an interesting word, I wonder if it has ever come up on this thread before ...

All I want is the diameter of the disk according to standard theory. Is that really too much to ask?
 
Ok, start with a diameter then. Anything will do. Please, just come up with a way to differentiate between standard theory and the predictions I have made. I'm not looking for anything fancy.

Glad to! Standard theory predicts that the Sun is a 6000K blackbody with absorption lines. Your theory predicts that the Sun is a 2000K blackbody with NO absorption lines, overlaid by a (ETA: much brighter) >100,000K emission line plasma showing neon and silicon lines predominantly in the far UV. That's a great test of the two models.
 
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A sphere is a three dimensional object. Those running difference graphs are two dimensional renderings of mathematical calculations based on comparisons between sequences of thermal data gathered over a period of time.

And the circumference of the Sun is still about 4.37 million kilometers.

Please work with Mr. Spock and decide a diameter, and then please state that number relative to surface of the photosphere and which side of the photosphere it's on, inside or outside.
 
All I want is the diameter of the disk according to standard theory. Is that really too much to ask?


The diameter of the Sun is about 1,391,000 kilometers, or in miles that's about 864,000. Is it too much to ask that you Google these things yourself?
 
The diameter of the Sun is about 1,391,000 kilometers, or in miles that's about 864,000. Is it too much to ask that you Google these things yourself?

So you are now publicly prepared to wager your hair on that lower figure, + 1200KM? Just to be generous I'll give you anything above (larger than) the photosphere. Deal?
 
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