Moderated Iron sun with Aether batteries...

[nescafe]

Don't get me started. Electricity is *KNOWN AND DEMONSTRATED* to ionize matter. Your dark energy elves and inflation bunnies are always a no show in the lab.

We are talking about the Sun, not the observable Universe. Dark energy and inflation are irrelevant when talking about objects as small and gravitationally bound as the Sun (or the solar system as a whole, the Milky Way, or the Local Cluster).

 

[ben m]

I have figured out a way to make it transparent. All I have to do is ionize it to a specific energy state. A steady flow of current will do, but the numbers have to work out in terms of thermodynamics, densities, temperatures, all of which can be different depending on which layer we're talking about.

That's also the secret to my perpetual-motion machine. I have figured out a way to make it run forever, all I have to do is make the balls HEAVIER when they're falling and LIGHTER when they're ascending! I haven't figured out the numbers yet.

 

[GeeMack]

It's really a simple wager and if the photosphere is "opaque" and the lines originate above the photosphere they can't lose.

Which organization of professional astrophysicists shall we hold responsible for judging the success of your prediction?

 

[Michael Mozina]

Round and round we go. You get to define the boundaries of the photosphere. You will claim to see something below that boundary. And then people will remind you that you are ignoring solar geometry amongst a host of other omissions, and that "below the photosphere" is nonsensical anyways because it is defined as the region in which plasma becomes opaque. If you are seeing an emission, you aren't seeing below the photosphere, whatever the depth.

This is a fool's bet, and, unfortunately for you, GeeMack is no fool.

Now, shouldn't you be getting busy gathering actual evidence for your claims?

Hoy! What else would you suggest?

Consider what a "running difference" image is for a second. It's an image that shows the changes in activity over time. If all that activity starts outside the photosphere , then the the ring of the "running differences" must necessarily be above the photosphere, top, bottom right and left, like an exterior shell.

If however all of those emissions start under the surface of the photosphere, then the "shell" should appear inside the photosphere.

GM claims to be the king of RD images. What does he have to lose but his pride and his hair, and how is that not a suckers bet if all the activity (and differences) *MUST* occur *above* the photosphere?

 

[W.D.Clinger]

Look folks, you have to commit to something. We could go on forever and ever and ever if you aren't willing to bet something, if only a public change of opinion on the topic. I'm willing to bet. I'm willing to make some predictions related to the SDO images. I'm willing to bet on the neon issue as well. If you're not prepared to bet something, what's the point of continuing the conversation at all?

I'm willing to bet there's no point to continuing this conversation.

 

[Perpetual Student]

I haven't given up trying to answer sol's question. I'm trying to figure out a logical way to answer it based on real physical evidence that I can cite that are based on solar spectrum characteristics. I can't figure out how to do that. If I had some clue as to why the 94A images are unique, I might be able to figure out a way to do it. Birkeland already gave his own answers that you can find in that NY Times article. If you want any old number, I'd start with his numbers.

 

[Michael Mozina]

Which organization of professional astrophysicists shall we hold responsible for judging the success of your prediction?

I will accept any image from any of the stated SDO organizations, but the inside/outside part will be 13 or so pixel obvious. Your shell should appear to be about 1200KM over the photosphere, whereas I predict will be about 4800KM under the transparent neon photosphere.

Inside or outside?

 

[Michael Mozina]

I have already provided you with Birkeland's "best guess" from the New York Times. Why do I personally have to pull a math bunny out of my hat?

 

[ben m]

If all that activity starts outside the photosphere , then the the ring of the "running differences" must necessarily be above the photosphere, top, bottom right and left, like an exterior shell.

If however all of those emissions start under the surface of the photosphere, then the "shell" should appear inside the photosphere.

Inside? Do you mean "inwards of in the 2D image"?

And: no, that's not diagnostic of anything. Coronal emissions also produce features inwards of the 2D edge, remember? Hellooooo?

 

[Skwinty]

Apologies if someone posted this already, but holy crap!

http://science.nasa.gov/media/medialibrary/2010/04/27/AIA_20100419_1200_2100_304_211_171_hihres.mov

Very spectacular!!

Notice Asia and the Japanese Islands floating by?

 

[D'rok]

I will accept any image from any of the stated SDO organizations, but the inside/outside part will be 13 or so pixel obvious. Your shell should appear to be about 1200KM over the photosphere, whereas I predict will be about 4800KM under the transparent neon photosphere.

Inside or outside?

<facepalm>

 

[D'rok]

Very spectacular!!

Notice Asia and the Japanese Islands floating by?

How could I miss them? You can tell by the pixels!

 

[GeeMack]

Which organization of professional astrophysicists shall we hold responsible for judging the success of your prediction?

I will accept any image from any of the stated SDO organizations, but the inside/outside part will be 13 or so pixel obvious. Your shell should appear to be about 1200KM over the photosphere, whereas I predict will be about 4800KM under the transparent neon photosphere.

Inside or outside?

I said...

Which organization of professional astrophysicists shall we hold responsible for judging the success of your prediction?

 

[Michael Mozina]

The image has to be published. A news article JPG image will do provide it is otherwise at full resolution.

Do I smell fear or what? It's going to be damn obvious if the shell is inside the smooth edge we see in the still image. If the circumference is greater than that point, you win.

 

[D'rok]

Hoy! What else would you suggest?

This:

Please respond to this post, Michael.

 

[phunk]

Hoy! What else would you suggest?

Consider what a "running difference" image is for a second. It's an image that shows the changes in activity over time. If all that activity starts outside the photosphere , then the the ring of the "running differences" must necessarily be above the photosphere, top, bottom right and left, like an exterior shell.

"Outside the photosphere" is not a ring, it's a sphere! That means you will see things "inside" the limb of the sun, because they are between the camera and the sun.

 

[Michael Mozina]

"Outside the photosphere" is not a ring, it's a sphere!

You know what I mean.

That means you will see things "inside" the limb of the sun, because they are between the camera and the sun.

I am specifically trying to remove any "camera yada yada yada" from the conversation by using a RD image. If as the mainstream suggests, all the emissions begin above the surface of the photosphere, then the shell created by the RD image has to have larger diameter than the photosphere. If however the light starts under the surface of the photosphere, the shell that will be outlined will be smaller in diameter than the photosphere. We should be able to resolve all that "camera yada yada" based on the diameter of the RD shell.

I admit it would be hard to see the shell outline if it's in the orange area where it's supposed to be, but according to Birkeland's solar model, and Kosovichev's heliosiesmology data, and now SDO images, it's 13 pixels smaller than the diameter of the photosphere.

 

[DeiRenDopa]

Apologies if someone posted this already, but holy crap!

http://science.nasa.gov/media/medialibrary/2010/04/27/AIA_20100419_1200_2100_304_211_171_hihres.mov

I am particularly amazed at the tall, thin volcano silhouetted against the limb, about a third of the way up from the bottom edge. You can see it being eroded by the iron/silicon/neon clouds and winds, and getting ready to blow its top.

Then there's the destruction of the two Hometrees, by the alien spacecraft that is hovering, motionless, above and to the right of them (you can only see this as a thin outline of its top; the bulk of the spaceship is rendered invisible by a particularly ingenious application of unobtainium nanoparticles) ...

 

[GeeMack]

Do I smell fear or what? It's going to be damn obvious if the shell is inside the smooth edge we see in the still image. If the circumference is greater than that point, you win.

Michael, you're betting a head shaving that that you can see 4800 kilometers into the photosphere in an SDO image. My question is, which organization of professional astrophysicists shall we hold responsible for judging the success of your prediction?

 

[Michael Mozina]

Michael, you're betting a head shaving that that you can see 4800 kilometers into the photosphere in an SDO image. My question is, which organization of professional astrophysicists shall we hold responsible for judging the success of your prediction?

You can't handle the truth. You're wussing out.