Well, the forces do not always balance out so equally. For large nuclei like, oh, Ununoctium, electromagnetism wins out. For small nuclei like hydrogen, the nuclear force wins.
EM starts to overwhelm the color force at about the size of thorium nuclei.
I'm not a physicist, but I know that the nuclear force does not follow a 1/r^2 curve the way electromagnetism does (and even electromagnetism doesn't follow that at very close range). So the "winner" is going to depend greatly on the exact distances we're talking about, which itself is going to depend greatly on how big the nucleus is and how it's arranged.
If you posit it's constant across the nucleus, and will just cover thorium, then it has to fall off at the seventh power of the distance. Neither of those is quite exactly correct, but it's close enough. Inside most nuclei except the heaviest, the color force so far overwhelms the EM force that EM might as well not exist for all the effect it has. Outside the nucleus, it's the opposite situation: the color force can't reach that far.
Part of the reason is because its symmetry is three-fold; there are nine possible combinations, but you only need eight gluons to cover them all, because the last one is just the combination of all eight. Another part of the reason is that it's subject to confinement because it's so powerful that if you try to pull two quarks apart from inside a meson, two more quarks will form from the energy you're putting into the field by pulling on them and promptly combine with the two you're trying to pull apart and turn
them into mesons; so if you try to pull the quarks in a meson apart, you wind up with two mesons and a lot of wasted effort. Repeat until you get a clue and stop trying to beat the house odds.
I'd posit that it's why, after a certain point, extra neutrons will make a nucleus less stable.
Nope, it's not just neutrons, and you've got it backwards: it seems as if the more protons there are, the bigger an excess of neutrons you need to hold them together. So for example U-238 has 92 protons and 146 neutrons in it- an excess of 54, or more than 50% of the protons present. Go down to iron, and you get three isotopes: 56, 57, and 58; and one very nearly stable at 54, an alpha emitter with a half-life of more than 1E22 years, several million times the present age of the universe. Note that these need only 30 to 32 neutrons, for an excess of only four to six, some fifteen to twenty-five percent; and in fact, the nearly-stable iron-54 requires an excess of only two, less than 7%.
U-238's nearly stable; its half-life is over 4 billion years. Add one neutron, it becomes unstable and decays by beta emission with a few-day half-life into Neptunium-239, and a very short time later that decays by beta emission into Plutonium-239, which is fissile like U-235 is. Get up to about element 108 or 110, which have those numbers of protons of course, you get to a point where no matter how many neutrons you stuff in there the half life is like nanoseconds. Might be a bit higher than that, 112 or some such, but not much.
The nuclear force falls off faster than the electromagnetic, and therefore a bigger nucleus is not held together so strongly as a small one. That's just a guess (and I realize there are many complicating factors) but I think the basic gist of it is true.
- Dr. Trintignant
Well, basically, yes- but remember that that seventh-power falloff indicates a seventh-power buildup, too- and that means that just inside the outside edge of the nucleus, the color force's ratio to the EM force is higher than EM's to gravity. And if you want to know how weak gravity is, it can't even pull a little bitty magnet off a fridge with the WHOLE FREAKIN EARTH. If gravity were as strong as EM, you would die from a momentary exposure to the tides from the gravity of a baseball flying by within sight.
In fact, it's even worse than that. You did some math down there, I see. You made a mistake, or else Wikipedia gave you a wrong starting point. One of the things you might want to look up is the ratios of the forces; the ratio between EM and gravity can be found by comparing the gravitational constant with its equivalent for the EM force, which is called the "fine structure constant," and they're two of the constants that currently have no explanation in the Standard Model. That ratio is about 137:1.752E-45. That's about
forty-seven orders of magnitude. I'm sure you can see that not merely your body but the entire Earth would be at great hazard from a baseball if gravity were as strong as EM. Gravity only gets as strong as it does because there's no antigravity.
Now, the thing about the color force that makes it asymptotic is that its beta function is negative; that means that its coupling constant varies a great deal with a tiny change in distance, unlike gravity and EM, both of which have essentially stable coupling constants outside the nucleus (EM starts to self-interact at nuclear distances and gets complicated like the color force is, and nobody knows what gravity does- to know that we need a quantum mechanics for gravity, which we don't have). So that's at least part of the problem; you need the beta function to figure out how to describe how the coupling constant varies, so you can figure out what value to use for it at different distances and characterize how it falls off.
Good luck; I'm too lazy to get that involved.