sol invictus
Philosopher
- Joined
- Oct 21, 2007
- Messages
- 8,613
No, the forces of drag created by the prop, equal the drive, to produce zero velocity. If idealised, that would apply to the real vehicle. It could not move.
Huh?
The real vehicle has a drag that is proportional to the velocity. At low speeds it is low, but as the velocity rises, so does the drag. When the drag equals the drive,that is the terminal velocity of the device.
No, real vehicles do not have a drag that's proportional to velocity. Drag generally goes as velocity squared. But you're correct about terminal velocity.
If you still think the treadmill represents performance at windspeed, drive at windspeed, release it, and see what happens. It will not run along side as suggested.
These guys have made many videos to demonstrate that it does do that - or rather that it accelerates. And the treadmill experiments prove it even more cleanly.
In the van model turn the treadmill around. It fails to react. Turn off the drive motor, no visible difference (though prop no longer turns)
Stop the van, reverse the van, go beyond windspeed. The treadmill provides exactly the same information in all cases.
At least 9/11 claims have some air of plausibility.
I don't know what you're talking about.
For the last time, the treadmill - so long as you don't fall off the end or interact with the edges - is completely identical to a steady wind. Fixed position on the treadmill is moving at wind speed, moving with the treadmill is moving at ground speed (i.e. at rest with respect to the ground). It's an utterly trivial consequence of relativity, one which even high school physics students should understand.

