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Down wind faster than the wind

Brian_M,
That was exactly the idea I had in mind. Now that you have kindly done the drawings, (#1465) we can proceed.

You seem to treat the gears as separate in order to work out the leverage, but don't seem to recognise that they are a gear set? They are on the same axle.

When separated, one axle rotates at twice the rpm of the other. When you put them on the same axle they sweep the same angle, so the 'distance gain' falls away.

1. One turn of the bottom wheel moves that axle forward d = 2pi*r, at force F.

2. The force to drive that same wheel from the central gear, is therefore 2F.

3. One turn of the top wheel requires 2F, to turn the bottom wheel twice.
2F produces 2V
 
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No, John, The "velocities" are only the same is a very limited sense. Cart/wind velocity is local, wheres as the wind may be measured elsewhere. Measurement is critical. Inferring the speed from the relative velocities of cart and wind is not acceptable. I can make a faster cart if I can redirect the local airflow and measure it there. Hey, twice WS!
Did you mean to put 'Hey, twice BS!'?

On Monday I find I have no money in my wallet.
On Friday I find have no money in my wallet.
By looking at my wallet can I tell which of those days it is?
It could be that I do have money on the days between, with large transactions either way, or no money, any day.
I'd say it was some day after paying your bet money.

The velocity must not be inferred.
No. Indeed. The velocity (which is always and everywhere relative to something) must be measured. You measure the windspeed relative to the carpark and zoom off to see if the max speed you measure your machine at is more than that or if you need to tweak something, or you measure the speed of a treadmill, and put a cart on it, and see if it falls off the front or if you need to tweak something. I don't think anyone is suggesting any inference.

So, clearly John, I think the cart/wind zero velocity idea to be unreliable.
It's not an unreliable idea, it is a measurable condition that you have yourself already defined two different identical ways.

I would exclude it, but others hold it in value, so my remark was a compromise.
It seems much more likely that your remark was a fudge to try to steer somewhere between losing face and losing money. You make less and less clear statements the smaller that gap becomes.

I know that CW prop = CW wheels. If that means nothing to you, then you do not understand the treadmill argument at all.
CW prop may indeed equal CW wheels - I haven't bothered checking. CW prop could also equal CCW wheels, if, as I said last time, you change the gearing. Are you aware that if you put some gears together in a row, each turning the next, they turn in opposite directions? Do you realise that if you want your output rotation the other way, you can just add another cog in the line? Do you realise that the same switch can be performed by slipping the propshaft from one of the driving wheels to another, or by putting the gear on the other side of a driving wheel? Do you realise that it is feasible to make a propeller with the opposite angle or bias, as you like to call it, and make it push or pull even while it still goes CW? Do you realise that there are props that can slide gracefully from one angle to another and thus create thrust in either direction? Furthermore, do you realise that the idea of the wheels going CW or CCW is, as I said last time, an utterly meaningless condition unless you specify which side of the vehicle you are looking at? Do you realise that if you see a car go past and it's wheels are going CW, you can run across the road (do look first, won't you) and they'll be going CCW?

I do not value the treadmill. Dan O does, and wants to use it. I do not. I had idea how treadmill may be used to the satisfaction of both sides. Information gained denies the idea, but perhaps I was thinking of something else. Perhaps you can tell me what that was.
Perhaps I can tell you what you were thinking? What are you on?

On the treadmill, the amount of work done by the motor, is essentially the amount of energy dissipated by the propeller. Rotation does not affect that load, but the direction of the thrust.
Rotation indeed, as you say, affects the direction of thrust. There. That's a great start. You're getting the hang of aerodynamics now.

By your own reasoning you now understand why the treadmill is not what is claimed.
How so? What reasoning of mine? Do you mean a while back, where I pointed out some differences between the treadmill and a land test and agreed with a few others that they aren't likely to affect things at all but, contrary to spork, that strictly speaking one might say that the treadmill demo does not satisfy the wording of the claim? Or something related to your previous sentence, a convention most people follow when trying to convey meaning? You see, if it is that you are not satisfied with the equivalence doctrine or its use in this instance, then I guess you have to say that. You have to say that you won't accept a treadmill demo and then those interested in demonstrating it to you can decide whether to shrug and say they're not bothered what you think, or find another way to demonstrate it. I'd suggest they shrug, since you're just trolling anyway and, as spork said, aren't going to agree to any test.

Since there are supposed to be perfectly valid mathematical proofs, I don't know why a demo is really needed. But my personal experience is that, having been tricked by my intuition in the first instance, I now feel I have a sold intuitive grasp of the process, by reading, learning and thinking about it, and my reasoning does not show that the treadmill is "not what is claimed", in the sense you seem to be suggesting here. It is not exactly what is claimed, but all reasonable engineers and physicists agree that it is near enough a perfect 'boost', changing all significant velocities by the same amount, to validate the land-test situation, which is less controllable.

I pointed out those differences because I'm a bit pedantic. They are relevant in a strict sense, but their influence on the equivalence is, IMO, negligible. The trouble with you is that if a really careful treadmill test showed it to be true, you'd dismiss it. If some times later, several land tests proved it was true again, you'd dismiss it for some other reasons. There will always be some energy, thrust, rotation, momentum, work, force, power or ju-ju that you'll insist was wrong. You'd sit on one and ride at 3 times the speed of the wind directly downwind, get off and swear it doesn't actually prove that it works.

Also, on the real cart, CCW causes the wheels to move CCW, halting its forward progress. That you do not see the potential in that asymmetry, reflects badly upon your criticism.
Forget all about clocks. Clocks have nothing to do with it.

Yes, earthbound bias.
Ok. I will say this again one last time. All measurements of velocity are relative (to the velocity of the observer, or some origin). That means that the treadmill equivalence is not just a modelling trick, but a true analogue of the road conditions other than those negligible effects I wrote of. All relevant speeds can be measured quite simply and very accurately. Furthermore, even the effects of the limitations of scale can be measured and shown to be negligible or otherwise.

Ask JREF if they are prepared to accept "Pixieview". A cart can move relative to the wind and ground and not be at windspeed. If a cart makes it upwind. What is the windspeed w.r.t cart? If it slips just a little backwards, then that is like going downwind at windspeed, so it must be zero? You can ask yourself how the speeds are defined in this case. Paradoxical, at times.
Maybe you really are serious. Maybe you really don't get it. If you do get it, it's a convincing bit of trolling, I have to admit. I can't tell which it is. Ah, yes, I think I most certainly can....

In 4-vector space conservation holds, as do Newton's laws. What is the integral of the "boots" over, say, 10 propeller turns?
If I'm not very much mistaken, you mever mentioned anything about 4-vectors until someone who understands them introduced the term. As you've done before with other technical terms, you post a moment later using the new words you've learned, pretending you know more about them (possibly having just googled them and gawped at a page of stuff for a few minutes). Then you tag a bit on, twisting the idea to your own ends. Do you even know whether What is the integral of the boosts over 10 propeller turns? has any meaning?

The cart works because of the back-trenching of a gamut of foibles. If we take the mean of those foibles and back-trench them hard enough with respect to the rotation of the flange-arm (which is going CCCW, don't forget (East-West, UTC)), then the energy-matter-space-time continues measurably faster than the following wind, even up to steady-state electronics.
 
The cart works because of the back-trenching of a gamut of foibles. If we take the mean of those foibles and back-trench them hard enough with respect to the rotation of the flange-arm (which is going CCCW, don't forget (East-West, UTC)), then the energy-matter-space-time continues measurably faster than the following wind, even up to steady-state electronics.

John,

as for the whole post, well said. As for the above quote, you made my day!

Greetings,

Chris
 
Relative to the treadmill, the wheel speed is 5 mph faster than the wind; relative to the road, the wheel speed is 5 mph faster than the wind. So where's the difference?

By wheel speed, do you mean the overall speed of the cart?


If the cart is on the road going 10 mph in the same direction as a 5 mph wind, then the cart has a 5 mph headwind.

This is the same situation as the cart moving at 5 mph along a treadmill belt moving 5 mph the opposite way, in a room with still air. It's travelling 10 mph relative to the belt, and the still air acts as a 5 mph headwind.

Putting a fan at the end of the treadmill to 'give' it a 5mph headwind means that the air is now moving at the same speed as the belt of the treadmill, which is the same as sitting the cart on the ground on a windless day. It just won't work.

When the cart is on a treadmill in still air, travelling along the belt at windspeed results in the cart staying in one place. Adding a fan to give it an extra 5 mph headwind means that in order to stay in one place, it will have to be able to travel at least 5 mph faster than windspeed, which is a big call.
 
I've had difficulty with these, Brian, because of the conveyor belt's direction of travel, which appears to oppose the direction of the side of the upper wheel it is in contact with.


Yes, that's exactly what's going on. The belt is pushing the whole cart to the right by applying force to the top wheel. If the top wheel were allowed to turn freely, it would turn clockwise. But it's not free, it's geared to the bottom wheel.

Applying a force of x to the right on the top of the top wheel causes the bottom wheels to try and push the cart to the left with a force of x/2. As the force pushing the cart to the right (x) is greater than the force pushing the cart to the left (x/2) then the cart moves to the right.

If the cart is moving to the right, the bottom wheels are turning clockwise, which causes the top wheel to turn anti-clockwise, the opposite direction the way the belt was trying to turn it.

I imagine this is my failure to understand the diagram. It seems there's something odd going on here. I can imagine dropping the belt so that it turns the bottom of the wheel, or the top of the inner wheel of the set below


One reason there is a wheel on the top is so the belt doesn't have to be lowered to turn the bottom of the little wheel. It's the same thing, really. If you lowered the belt to under the little wheel, the belt would be pushing the little wheel anti-clockwise, but the wheel would be turning clockwise.

Another reason the wheel is on top is because it represents a propeller. If you replaced the backwards turning wheel with a backwards thrusting propeller, the cart would be pushed by the wind instead. Using a wheel and conveyer belt is just easier to picture, especially in two dimensions.

I didn't understand the DDWFTTW device, until I realised that the propeller was turning in the opposite direction the wind was trying to turn it, just like the wheel is turning in the opposite direction the belt is trying to turn it.
 
I know that CW prop = CW wheels.


Don't you know that wheels always turn CW? If it looks like they're turning CCW, you're just looking at them from the wrong side. :D

Seriously though, shouldn't you indicate if you mean CW from the left, or CW from the right?

And as for which way the prop has to turn, wouldn't that depend on which way it was attatched? Attatch it one way, and turning it clockwise would push the air out behind the cart. Attatch it the other way, and turning it clockwise would push the air out ahead of the cart.

The prop can turn in any direction you want it to, as long as it pushes air out the back of the cart when the wheels are turned so that the cart moves forwards.
 
You seem to treat the gears as separate in order to work out the leverage, but don't seem to recognise that they are a gear set? They are on the same axle.

The gear and wheel sharing the same axle act as a single lever. The radius of the wheel acts as the length of the lever on one side of the fulcrum, and the radius of the gear acts as the length of the lever on the other side of the fulcrum. The axle itself is the fulcrum.


1. One turn of the bottom wheel moves that axle forward d = 2pi*r, at force F.

Um, yes. Rotating the bottom wheel moves the axle, and the entire cart, by a distance equal to the circumference of the wheel.

2. The force to drive that same wheel from the central gear, is therefore 2F.

If the centeral gear has half the diameter of the wheel, then yes, it takes twice the force to turn the wheel.

3. One turn of the top wheel requires 2F, to turn the bottom wheel twice. 2F produces 2V

In other words, the bottom wheel is turning at twice the speed with half the force of the top wheel, exactly as I've been saying all along.

So when the belt pushes the top wheel to the right, the bottom wheel tries to push the cart to the left, but with only half the force. If twice the force is applied to push the cart to the right than the cart is pushing itself to the left, then the cart must move to the right (with half the force the belt is applying to the top wheel).

If the cart is moving to the right, then instead of the belt turning the top wheel, the bottom wheel is turning the top wheel.

Since the bottom wheel is turning at twice the speed with half the force of the top wheel, that means the top wheel is turning at half the speed and twice the force of the bottom wheel.

Since it is pushing back against the belt, this pushes the cart forward faster than the belt is moving.

You do agree that this cart will consistently travel faster than the belt, don't you?
 
Did you mean to put 'Hey, twice BS!'?
I can arrange for my reference to be a local airstream moving relative to me. By calculation espoused in this thread, I can infer that I am traveling at twice windspeed. I can do the same to create situations where the differential is zero, but the cart is standing still. That weakens the claim that such a differential is an indicator of windspeed. Why should I accept that assumption, and not it is actually in still air, which I say it is. You did ask. If you press a minor point in the interests of pedantry, then you can expect to learn only the most trivial or matters.

I'd say it was some day after paying your bet money.
It would be funny if you said that.
The same logic of the money is used to back the treadmill. If there are no records, then you cannot tell if it is Monday or Friday. The treadmill shows no such history, so it can well be the still air that equates to Monday. That's all that meant. Again, the price of pedantry.

No. Indeed. The velocity (which is always and everywhere relative to something) must be measured. You measure the windspeed relative to the carpark and zoom off to see if the max speed you measure your machine at is more than that or if you need to tweak something, or you measure the speed of a treadmill, and put a cart on it, and see if it falls off the front or if you need to tweak something. I don't think anyone is suggesting any inference.
The velocity of the cart on the treadmill is inferred.

It's not an unreliable idea, it is a measurable condition that you have yourself already defined two different identical ways.
Well, yes. One is an inference and not a direct empirical measurement, and so disqualified. The other is a matter of mensuration. That is why the matter is being discussed. How is that to be done? You seem to see everything as a trial.

It seems much more likely that your remark was a fudge to try to steer somewhere between losing face and losing money. You make less and less clear statements the smaller that gap becomes.
Talk to the hand.

CW prop may indeed equal CW wheels - I haven't bothered checking. CW prop could also equal CCW wheels, if, as I said last time, you change the gearing. Are you aware that if you put some gears together in a row, each turning the next, they turn in opposite directions? Do you realise that if you want your output rotation the other way, you can just add another cog in the line? Do you realise that the same switch can be performed by slipping the propshaft from one of the driving wheels to another, or by putting the gear on the other side of a driving wheel? Do you realise that it is feasible to make a propeller with the opposite angle or bias, as you like to call it, and make it push or pull even while it still goes CW? Do you realise that there are props that can slide gracefully from one angle to another and thus create thrust in either direction? Furthermore, do you realise that the idea of the wheels going CW or CCW is, as I said last time, an utterly meaningless condition unless you specify which side of the vehicle you are looking at? Do you realise that if you see a car go past and it's wheels are going CW, you can run across the road (do look first, won't you) and they'll be going CCW?

Rotation indeed, as you say, affects the direction of thrust. There. That's a great start. You're getting the hang of aerodynamics now.

Perhaps I can tell you what you were thinking? What are you on?

That's telling. I gave you my answers. You make up your own

How so? What reasoning of mine? Do you mean a while back, where I pointed out some differences between the treadmill and a land test and agreed with a few others that they aren't likely to affect things at all but, contrary to spork, that strictly speaking one might say that the treadmill demo does not satisfy the wording of the claim? Or something related to your previous sentence, a convention most people follow when trying to convey meaning? You see, if it is that you are not satisfied with the equivalence doctrine or its use in this instance, then I guess you have to say that. You have to say that you won't accept a treadmill demo and then those interested in demonstrating it to you can decide whether to shrug and say they're not bothered what you think, or find another way to demonstrate it. I'd suggest they shrug, since you're just trolling anyway and, as spork said, aren't going to agree to any test.
Your remarks on thrust and where the propeller power goes and how it doesn't matter 'n' all. That should lead you to conclude that the treadmill is a force balance. I was wrong, there. Your own reasoning didn't lead you to that conclusion.

Since there are supposed to be perfectly valid mathematical proofs, I don't know why a demo is really needed. But my personal experience is that, having been tricked by my intuition in the first instance, I now feel I have a sold intuitive grasp of the process, by reading, learning and thinking about it, and my reasoning does not show that the treadmill is "not what is claimed", in the sense you seem to be suggesting here. It is not exactly what is claimed, but all reasonable engineers and physicists agree that it is near enough a perfect 'boost', changing all significant velocities by the same amount, to validate the land-test situation, which is less controllable.
Translate. I have not seen, nor would I understand, the proofs. I have been convinced upon my own cognizance. Why not you?
If you insist on telling me what I have already told you is not the case, then don't bother to respond.

I pointed out those differences because I'm a bit pedantic. They are relevant in a strict sense, but their influence on the equivalence is, IMO, negligible. The trouble with you is that if a really careful treadmill test showed it to be true, you'd dismiss it. If some times later, several land tests proved it was true again, you'd dismiss it for some other reasons. There will always be some energy, thrust, rotation, momentum, work, force, power or ju-ju that you'll insist was wrong. You'd sit on one and ride at 3 times the speed of the wind directly downwind, get off and swear it doesn't actually prove that it works.
Don't waste your time with this sort of thing, John.
I have already given answers to these remarks. If they are no acceptable, then I do not feel the need to meet your repeated demands.
The treadmill is a force balance device. It has nothing to do with windspeed travel. If you insist that your ideas of equivalence are correct, then so be it.

Ok. I will say this again one last time. All measurements of velocity are relative (to the velocity of the observer, or some origin). That means that the treadmill equivalence is not just a modelling trick, but a true analogue of the road conditions other than those negligible effects I wrote of. All relevant speeds can be measured quite simply and very accurately. Furthermore, even the effects of the limitations of scale can be measured and shown to be negligible or otherwise.

Maybe you really are serious. Maybe you really don't get it. If you do get it, it's a convincing bit of trolling, I have to admit. I can't tell which it is. Ah, yes, I think I most certainly can....

If I'm not very much mistaken, you mever mentioned anything about 4-vectors until someone who understands them introduced the term. As you've done before with other technical terms, you post a moment later using the new words you've learned, pretending you know more about them (possibly having just googled them and gawped at a page of stuff for a few minutes). Then you tag a bit on, twisting the idea to your own ends. Do you even know whether What is the integral of the boosts over 10 propeller turns? has any meaning?

Oh yes I do. But that is not the point. I have seen some of the ideas.
They have nothing to do with the treadmill's performance. I know that, but you don't.

The cart works because of the back-trenching of a gamut of foibles. If we take the mean of those foibles and back-trench them hard enough with respect to the rotation of the flange-arm (which is going CCCW, don't forget (East-West, UTC)), then the energy-matter-space-time continues measurably faster than the following wind, even up to steady-state electronics.

Now, why don't you Google all of that stuff. When you realise that you made it all up, try and find out why the integral matters. Any number of turns.
 
Don't you know that wheels always turn CW? If it looks like they're turning CCW, you're just looking at them from the wrong side. :D

Seriously though, shouldn't you indicate if you mean CW from the left, or CW from the right?
And as for which way the prop has to turn, wouldn't that depend on which way it was attatched? Attatch it one way, and turning it clockwise would push the air out behind the cart. Attatch it the other way, and turning it clockwise would push the air out ahead of the cart.

The prop can turn in any direction you want it to, as long as it pushes air out the back of the cart when the wheels are turned so that the cart moves forwards.

Yes. That is how it is on the belt. You are both second-guessing what I wanted to know. There was is nothing to discuss, only verifying something. I can't use the idea because the device is already doing the maximum. On the cart it is otherwise, because the situation is different in real wind. I linked the two, for a purposes that I did not express, and as I have said, they are no longer relevant.
 
I’ve been ciritcal of the treadmill demonstrations provided as the treadmill is too short to perform adequate testing. Myself and others have suspected that the cart was using stored kinetic energy and that this was being lost too gradually to be shown on a treadmill. The turntable design I suggested provides an endless “treadmill” and I have been disappointed that nobody has built one despite most saying it was a good idea. Not to be beaten I have stolen time I don’t have and have quickly built a turntable and cart (and it works!!!).

What I wanted to test was whether the thrust of the fan could continuously exceed the the rolling resistance of the wheel (mine only has one drive wheel). The construction is crude and there is still lots of fine tuning to do but early tests have been conclusive enough for me to say the answer to this question is 99.99999999% YES!

When the cart is “hovering” and the turntable is sped up the cart travels against the motion of the turntable. I didn’t think it would.

The cart is slightly unbalanced and I found it bounced around too much so I attached a pair of visegrips to it’s fame to give it more weight to stop the bouncing. It still moves against the turntable motion even with this extra weight.

Spork and Co - BUILD A TURNTABLE it will be worth the effort and will answer a lot of sceptical concerns. My turntable is only 4ft in diameter and it woks fine. I cut a disc from particle board with a centre circle removed and fitted it to a bicycle wheel.

I may post a photo on later but I don’t want to film it until I've got it working better. Unfortunately this may not be until next weekend.
 
The gear and wheel sharing the same axle act as a single lever. The radius of the wheel acts as the length of the lever on one side of the fulcrum, and the radius of the gear acts as the length of the lever on the other side of the fulcrum. The axle itself is the fulcrum.

Um, yes. Rotating the bottom wheel moves the axle, and the entire cart, by a distance equal to the circumference of the wheel.
Yes

If the centeral gear has half the diameter of the wheel, then yes, it takes twice the force to turn the wheel.
Yes.

In other words, the bottom wheel is turning at twice the speed with half the force of the top wheel, exactly as I've been saying all along.
Yes?
You have
Top Bottom
V = X 2X
F = Y Y/2
If have:
Top Bottom
V = X 2X
F = 2Y Y

So you have the same. The result is the same as a 1:1 cart, as I have said? So when you say "with half the force" you mean that you are only applying half the force to get half the acceleration?
You do agree that this cart will consistently travel faster than the belt, don't you?
Yes, that has never been disputed. Only that being twice the velocity, it will take twice the force. So you seem to agree. OK...
 
Nice work Ynot.

Of course I'd be the last to say "I told you so". ;)

JB

I’ve been ciritcal of the treadmill demonstrations provided as the treadmill is too short to perform adequate testing. Myself and others have suspected that the cart was using stored kinetic energy and that this was being lost too gradually to be shown on a treadmill. The turntable design I suggested provides an endless “treadmill” and I have been disappointed that nobody has built one despite most saying it was a good idea. Not to be beaten I have stolen time I don’t have and have quickly built a turntable and cart (and it works!!!).

What I wanted to test was whether the thrust of the fan could continuously exceed the the rolling resistance of the wheel (mine only has one drive wheel). The construction is crude and there is still lots of fine tuning to do but early tests have been conclusive enough for me to say the answer to this question is 99.99999999% YES!

When the cart is “hovering” and the turntable is sped up the cart travels against the motion of the turntable. I didn’t think it would.

The cart is slightly unbalanced and I found it bounced around too much so I attached a pair of visegrips to it’s fame to give it more weight to stop the bouncing. It still moves against the turntable motion even with this extra weight.

Spork and Co - BUILD A TURNTABLE it will be worth the effort and will answer a lot of sceptical concerns. My turntable is only 4ft in diameter and it woks fine. I cut a disc from particle board with a centre circle removed and fitted it to a bicycle wheel.

I may post a photo on later but I don’t want to film it until I've got it working better. Unfortunately this may not be until next weekend.
 
<snip>
When the cart is “hovering” and the turntable is sped up the cart travels against the motion of the turntable. I didn’t think it would.

Ynot, what happens when you try it without the propellor?
 
Here’s a photo. Thought I would leave the visegrips on for effect.

picture.php
 
I know why you ask that question and one of the many tests I want to do is replace the propellers with a flywheel.

Thanks, Ynot

JB
It doesn't freakin work, that's what happens.
No. It will start to gain speed, and perhaps match the turntable. Flywheel even more so. Forces from a propeller only have to add to that, to do even better.
 
No. It will start to gain speed, and perhaps match the turntable.

stipulation for the following examples: Ynot's turntable rotates CW (from above) likely at around 75rpms -- that would be ~10mph.

A: on the turntable, Ynot's prop cart runs at least 11mph *CCW* relative to the turntable, which means it running in the opposite direction of the turntable, faster than the turntable.

B: with a flywheel on the cart in place of the propeller, the cart will quickly settle into a fixed position on the steadily spinning turntable and rotate *with* the turntable CW at the same speed as the turntable.

And in summary: with the flywheel in place of the prop -- it doesn't freakin' work ... PERIOD!!


Again,

A: the prop-cart runs 11mph *opposite* on the 10mph turntable.

B: the flywheel-cart will not 'run' at all steady state, but rather will sit like a bump on a log on top of the turntable and rotate with it.

JB
 
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ynot, nice work on the turntable. We want to see video!

Question to all: can any of you honestly even parse humbers words into sentences anymore? I dip into a post of his now and then just to get my fair share of abuse - but when my brain starts jellifying I have my spotter pull me out. I mean it's like some form of super-concentrated, pseudo-engineering spewage that's produced with liberal use of a random number generator - sort of like the verbal equivalent of white noise at the of 50% distortion level. In fact I think it may be an art form that I simply don't get.
 

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