Re: Re: Re: Do you do simple math "out loud" in your head?
Rolfe said:
Neat trick. That's one I always have trouble with. Care to share?
Rolfe.
Rolfe,
Sure thing. I break the formula down this way:
F = 9/5C + 32
9/5 is 1/5 shy of 2, so the first move is to simply double C. To which 32 can be added quickly. The final trick is to recognize that 1/5 is 2/10. 10ths can be handled quickly, because that's just a decimal shift, right? So, put it all together:
double C, add 32, subtract 2/10s:
100C -> 200F-> 232F-> 212F
I know the explanation is a bit long, but it beats the heck out of the long way:
9 times 100, then divide by 5, then add 32.
The "double and add" step becomes very quick with some practice, so I usually do that pretty much at once.
-10C -> 12F -> 14F
(When working with negative readings, you have to remember that the subtract 2/10s step is done later for convenience, but is actually a correction for the first doubling step.)
The basic ideas here are three
o doubling is simple
o thinking in 10ths is simple
o doubling and then subtracting 2/10s is the same as multiplying by 9/5s
Does that make sense or does it sound overly complicated?