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Deeper than primes

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No, they are unrelated. You can believe in something with or without understanding of it. "With" is preferable, but not required.
Wrong.

If you really know X you do not believe in it anymore because it becomes an actual fact for you.
No, you are the one who is incorrect. If you really know about something, you are more aware than anyone how much you knowledge is based on evidence, and you are aware how much it could change with additional evidence. That is what knowledge gives: an understanding of the conditionalities. I could give you many examples and I will if you show me some evidence that you would listen.

Belief hold as long X is not really known to you, and as a result the best you can is only believe in X.
That might be true of people who believe things based purely on faith, but not those who believe things based on evidence. People who believe things based on evidence are always willing to adjust their beliefs if evidence is added or changed.

For example, I am a geologist and the theory of plate tectonics has been developed within my lifetime. My beliefs in geology have changed because of evidence, though my basic belief in uniformitarianism (look it up) have been modified only slightly to accomodate this new evidence.

And my example is not unique. It is common, even ubiquitous among those who believe based on evidence. So I encourage you to modify your statements about belief. I hope it is only because you seem to be using a non-standard definition of "belief". If not, you are just simply and demonstrably wrong.
 
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Try to open the box, start by taking the baby steps as found in http://www.internationalskeptics.com/forums/showpost.php?p=7089263&postcount=15087 .

Another evasion. Please try to address the issue this time. Here it is again:

You claimed |S| = |P(S)| for any set S, finite or infinite. You also claimed there to be a bijection between the elements of any set S and its power set.

Either retract these bogus claims, or perform the impossible by providing a bijection between the elements of the null set and its power set.
 
Try to open the box, start by taking the baby steps as found in http://www.internationalskeptics.com/forums/showpost.php?p=7089263&postcount=15087 .
I think you should recant and retract your claims. There was a guy who didn't and then . . .
Refusals to recant

An Italian prelate pronounced the sentence of condemnation upon Hus and his writings. Hus protested, saying that even at this hour he did not wish anything, but to be convinced from Holy Scripture. He fell upon his knees and asked God with a low voice to forgive all his enemies. Then followed his degradation — he was enrobed in priestly vestments and again asked to recant; again he refused. With curses his ornaments were taken from him, his priestly tonsure was destroyed, and the sentence was pronounced that the Church had deprived him of all rights and delivered him to the secular powers. Then a high paper hat was put upon his head, with the inscription "Haeresiarcha" (meaning the leader of a heretical movement). Hus was led away to the stake under a strong guard of armed men. At the place of execution he knelt down, spread out his hands, and prayed aloud. Some of the people asked that a confessor should be given to him, but one priest exclaimed that a heretic should neither be heard nor given a confessor.

upaleni_mistra_jana_husa.jpg


Or do you wish to be "delivered to the secular powers" too? LOL.
 
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But you need to extend your helping hand . . .

There are two electrical outlets in the kitchen.

[qimg]http://www.electricianpdq.com/images/outlet2prong.jpg[/qimg]

There are also four appliences there.

[qimg]http://www.tjbhomes.com/specmodels/2849_aspen_lake_drive/images/appliance_selections_kitchen_large.jpg[/qimg]

All I need to know is if you can plug in all apliences and make them all going without using this thing:

[qimg]http://www.wholesaletip.com/image/34/4-outlet-electric-ac-power-bar-strip-splitter-with-switch-250v-34672_1.jpg[/qimg]

Just answer if you can do it or not. Just aswer YES or NO. That would be a great help.

YES I can.
 
I already did. There is really no way to come up with y=f(x) that would represent the power set while mapping from R to R.

I meant what you wrote about red being surjective, blue injective and green bijective.
 
Is there any problem?

Yes. Red is not surjective from R to R and green is neither surjective nor injective from R to R, which means it doesn't fulfill any of the two required conditions for being bijective.

You might have just mixed up the colors, that's why I said you might want to rethink that.
 
Yes. Red is not surjective from R to R and green is neither surjective nor injective from R to R, which means it doesn't fulfill any of the two required conditions for being bijective.

You might have just mixed up the colors, that's why I said you might want to rethink that.
Why is it so that the function rendered in red is not surjective?
 
It doesn't take all possible values in R.
I think it's all covered , coz y=f(x)=sin(x) is continuous within the range shown. Look again: The x-axis is set A, and the y-axis is set B. So each point on the x-axis/set A maps to a point on the y-axis/set B according to y=f(x)=sin(x).

I don't know exactly what you mean by "possible values in R," but that could be the source of your different view.
 
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Another evasion. Please try to address the issue this time. Here it is again:

You claimed |S| = |P(S)| for any set S, finite or infinite. You also claimed there to be a bijection between the elements of any set S and its power set.

Either retract these bogus claims, or perform the impossible by providing a bijection between the elements of the null set and its power set.
Another evasion jsfisher. Please try again to open the box, start by taking the baby steps as found in http://www.internationalskeptics.com/forums/showpost.php?p=7089263&postcount=15087
 
No, you are the one who is incorrect.
You don't get the Unity, which is the source of any possible change, which is itself naturally unchanged, otherwise it can't be considered as the source of all changes.

Your awareness is floating upon the surface of changes, without being aware of the unchanged Unity that can't be known by believing in Unity.

Your examples are at the level of the naturally manifested and changed, where at this surface level belief is always involved simple because any given evidence is naturally changed.

By directly aware of Unity, no belief is involved anymore.
 
I think it's all covered , coz y=f(x)=sin(x) is continuous within the range shown.

Yes, it's continuous, but it only takes values in the [-1,1] interval. Hence, not surjective from R to R, only from R to [-1,1]. This is not an opinion, this comes from the definition of surjectivity.
 
You do not distinguish between the ever smaller element that exists between any pair of some closer smallest elements.

Wrong, your “ever smaller element” is just your personal ascription that you try to associate with the fact that in a continuous space there is always another point between any two points (and thus smaller line segments between the endpoints of any line segment). While your “smallest elements” are just your personal ascription that you try to associate with the fact that points are zero dimensional and thus have no extents.

Your difficultly remains, Doron, that you just don’t distinguish between your own flippant personal ascriptions and the well established concepts you try to associate them with.


The different names of the smallest elements is possible because of the co-existence of the smallest AND the ever smaller, and it is known by the name "collection".

“different names”? What different names? Again, location is an aspect of ordering not just ‘naming’. Oh and “collection” need not even involve line segments or points, as some simply don’t.


Actually, without the ever smaller element, the smallest elements can't be related to each other.

Sure they can, spaces do not need to be continuous, as some simply aren’t.

So the relative locations of the smallest elements are the result of the ever smaller AND the smallest.

Nope, as noted above and before your “ever smaller” requires a continuous space and as not all spaces are continuous not all locations (relative or absolute) require a continuous space.

You can add relative to the list of the concepts that you (yet) do not comprehend, by your smallest-only reasoning.

Again stop trying to simply posit aspects of your own failed reasoning onto others.


An orange is already a result of the co-existence of the ever smaller element, which exists at once at least at two smallest elements' locations.

No smallest element exists at once at more than one location, which is a property that an ever smaller element has.

So your “ever smaller element” requires at least two of your “smallest elements” for what you consider to be its defining “property”. That should tell you something, if you’re listening to, well, yourself.


This distribution is a result of the co-existence of the ever smaller AND the smallest.

Distributions also don’t need to be continuous, while your “ever smaller” requires a continuous space along with, by your own assertion, at least two of your “smallest elements'”


Yet no smallest element has the property of being at once at both given locations, which a property that the ever smaller element has.

A “property” you claim above requires at least two of your “smallest elements”

You still the not grasp the co-existence of the ever smaller AND the smallest.

You still, apparently deliberately, don’t grasp that your “ever smaller”, explicitly and by your own assertions, requires at least two of your “smallest” for just what you consider its defining “property”. So your “co-existence of the ever smaller AND the smallest” is just redundant and superfluous nonsense on your part.

That is a challenge that your reasoning simply ignore.

Really? Well evidently you’re the only one failing to meet your own challenge. Perhaps because you just fail to challenge yourself or your own “notions”.


By my own determination only an ever smaller element has the property of being at once at lest at two locations of the smallest elements, where no smallest element has this property.

So once again the defining “property” of your ever smaller element requires at least two of your “smallest element” by your “own determination”.

The continuum is a property of an ever smaller element. No smallest element has this property.

Actually as noted above and before a continuous space is a requirement for what you refer to as your “ever smaller element”.


Your local-only view, which gets only the smallest elements of some collection, ignores the ever smaller elements between them, with actually have the property of the continuum.

Again stop simply trying to posit aspects of your own failed reasoning onto others.

You still to not get the co-existence of the continuum, which is the property of the ever smaller element, and the discrete, which is the property of the smallest element.

You still don’t get that a continuous space is a requirement for what you refer to as your “ever smaller element” as well as , by your own “own determination”, at least to of your “ever smaller element”.

You can wait as much as you like, it does not change the fact that your location-only reasoning does not help you the comprehend the co-existence of the continuum, which is the property of the ever smaller element, and the discrete, which is the property of the smallest element.

Again stop simply trying to posit aspects of your own failed reasoning onto others.

As far as waiting goes, evidently we are going to have a very long wait before you can agree with just yourself or even be bothered to look up what defines a continuous or discrete space.
 
Another evasion jsfisher. Please try again to open the box, start by taking the baby steps as found in http://www.internationalskeptics.com/forums/showpost.php?p=7089263&postcount=15087

I know you are not so stupid as to not understand that those posts you continue to reference don't address the issue:

You claimed |S| = |P(S)| for any set S, finite or infinite. You also claimed there to be a bijection between the elements of any set S and its power set.

Either retract these bogus claims, or perform the impossible by providing a bijection between the elements of the null set and its power set.
 
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