doronshadmi
Penultimate Amazing
- Joined
- Mar 15, 2008
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http://www.internationalskeptics.com/forums/showpost.php?p=5414957&postcount=7495In the above post you claim The Man said, "the negation of 0 is 0" without linking to the original message. Please provide proof that The Man said it.
In other words, The Man's negation is the particular case of opposites, and in the case of 0, this particular case does not hold.The Man said:As already shown the negation of 0 is 0. “~” is a mutually dependent relation, your “comparison (notated by -->)” is superfluous.
Again.
If the entire universe is 0 , then ~0 is what is between {}.
If 0 is one of the given things of a given universe, then ~0 is "anything but" 0.
In both cases the output is different than the input.
http://www.internationalskeptics.com/forums/showpost.php?p=5398677&postcount=7392
The Man said:You do understand that the negation of nothing or zero value is still zero value or nothing, quite distinct from zero value not being equal to some value, don’t you? The primary reason is that the sum of some value with it’s negation always equals zero or nothing.
The Man simply can't distinguish between ~ and - , where ~X is necessarily different than X and -X is not necessarily different than X.
Given X, ~X is "necessarily different than X".
Given X, -X is ~"necessarily different than X".
For example:
-Nothing ---> Nothing
-0 --> 0
~Nothing ---> Somthing
~0 ---> for example, 1 or what is between {}
In both cases ---> is used as a comparison between the input and the output.
EDIT:
Another example:
X = "necessarily different"
Given "necessarily different", ~"necessarily different" is "necessarily different than necessarily different".
Given "necessarily different", -"necessarily different" is ~"necessarily different than necessarily different".
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