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Deeper than primes

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If B is the limit of X, then X cannot be at B
EDIT:

Wrong.

Take for example [A,B] or (A,B).

A=point 0
B=point 1
X=____
C= arbitrary point along X AND between A and B

In this case 1 is a limit of 0 C 1 AND X is at B, exactly because X is not a collection of points.
 
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EDIT:


The Man you are using a reasoning that has no ability to deal with things that save their ids with respect to each other under co-existence.

Again Dorn these are just “ids” that you ascribe, so can save them as much as you want.


As a result you are unable to understand the non-local id of a thing that exists at more than one location, and the local id of a thing that exists at no more than one location, under their co-existence.

Nope, I got no problem with “a thing that exists at more than one location, and” some other “thing that exists at no more than one location”. Its your “non-local/local” “id”s with all the nonsense baggage you try to just ascribe with them that gets you into trouble.


You simply use the word "order" even if there is no order, so even if one follows your reasoning, the next element of a given collection is not necessarily determined by any particular order exactly as the cardinality of some infinite set is not impacted by the order of its members (cardinality is not ordinality and vice versa).

The “cardinality of some infinite set, or any set, is not impacted by the order of its members”, I certainly won’t argue otherwise but “the next element of a given collection” is an aspect of ordering. You do understand what an ordinal number is, don’t you? Hint; look to the root of the word ‘ordinal’ if you are still missing it.

By understanding the arbitrariness of the next member of some infinite set and the fact that multiplicity is the result of the co-existence of the local with the non-local, we have the needed logical basis to conclude that any given amount of local elements can't completely cover a non-local element under the co-existence, and any given amount of non-local elements can completely reducible into local elements.

Once again your stated ‘conclusion’ simply doesn’t follow from your purported “logical basis” .

The non-transformation of the local and the non-local into each other under their co-existence, guarantees the existence of multiplicity in the first place, and prevents the existence of the final non-local or local element in any given infinite collection (or in other words, the completeness of any given infinite collection, where the permanent existence of the next non-local or local elements, is an inherent property of its existence).

You are still thinking (apparently deliberately) of lists instead of sets. All the members of a set don’t need a “final non-local or local element“ to be all the members of that set.

As for non-locality and locality, let's demonstrate again their ids under co-existence by using the minimal needed elements, which are points and line-segments:

OK, I doubt this will go well for you though, but let’s just see how it pans out.

A line segment X is located at endpoint A AND at endpoint B.

So far so good, at least two points define a line segment.

Let endpoint B be a limit of X, such that X is at B AND at any arbitrary closer point C to B, which is located along X AND it is between endpoint A and endpoint B.

You’re still doing fine, at least in a continuous space there is always another point between any two. Heck, you might actually be learning something here, Doron. Congratulations.

No matter how close is C to B, C is not B only if X is irreducible to B OR C.

“irreducible”? “X” isn’t “C”, “B” or “A”. Those are points while your “X” was a line segment by your own, well, “id”s. Similarly your “A”, “B” and “C” are still just points that you have defined as being different so your ‘irreducibility’ has nothing to do with one not being the other, you have defined them such that they can’t be each other. You might be. starting to lose your own “id”s here, but again let's just see.

No point along X, whether it is endpoint A endpoint B or arbitrary point C, is at more than one location along X.

A point is only one location, so again no argument there.

The co-existence of line segment X, endpoint A, endpoint B and arbitrary point C (C is taken as a placeholder of any point between endpoint A and endpoint B, along X) under a one framework, guarantees the existence of the Real line.

Of course line segments and points ‘co-exist’, in fact it is a requirement that they do such. Remember at least two points define a line segment and the number of co-ordinates needed to identify a particular point in some space defines the dimensions of that space (again please look up the root of the word ‘ordinate’). You have surprised me, Doron ,you might actually be learning some basic geometry. Again congratulations. Other than that, what was your point?
 
epix, 0, in this case, is the amount of the elements in the basket and not the size of the basket.

You do not distinguish between size and amount.
You said that the smallest element is zero and you further indicated that the basket=0 due to 5 elements - 5 elements = 0 elements.
5 - 5 = 0 is an empty basket, in this case.
You said in the beginning that 0 is the smallest element. So what is the smallest element when the basket is empty and now, according to your latest evaluation, is no longer the smallest element? An orange?
 
Again Dorn these are just “ids” that you ascribe, so can save them as much as you want.




Nope, I got no problem with “a thing that exists at more than one location, and” some other “thing that exists at no more than one location”. Its your “non-local/local” “id”s with all the nonsense baggage you try to just ascribe with them that gets you into trouble.




The “cardinality of some infinite set, or any set, is not impacted by the order of its members”, I certainly won’t argue otherwise but “the next element of a given collection” is an aspect of ordering. You do understand what an ordinal number is, don’t you? Hint; look to the root of the word ‘ordinal’ if you are still missing it.



Once again your stated ‘conclusion’ simply doesn’t follow from your purported “logical basis” .



You are still thinking (apparently deliberately) of lists instead of sets. All the members of a set don’t need a “final non-local or local element“ to be all the members of that set.



OK, I doubt this will go well for you though, but let’s just see how it pans out.



So far so good, at least two points define a line segment.



You’re still doing fine, at least in a continuous space there is always another point between any two. Heck, you might actually be learning something here, Doron. Congratulations.



“irreducible”? “X” isn’t “C”, “B” or “A”. Those are points while your “X” was a line segment by your own, well, “id”s. Similarly your “A”, “B” and “C” are still just points that you have defined as being different so your ‘irreducibility’ has nothing to do with one not being the other, you have defined them such that they can’t be each other. You might be. starting to lose your own “id”s here, but again let's just see.



A point is only one location, so again no argument there.



Of course line segments and points ‘co-exist’, in fact it is a requirement that they do such. Remember at least two points define a line segment and the number of co-ordinates needed to identify a particular point in some space defines the dimensions of that space (again please look up the root of the word ‘ordinate’). You have surprised me, Doron ,you might actually be learning some basic geometry. Again congratulations. Other than that, what was your point?
EDIT:

The point is that you are using the concept of collection without the understanding of what enables the existence of this concept, in the first place.

Your reply demonstrates once again that your used reasoning is not capable to grasp the difference between smaller (has the property of being simultaneously in more than one location) and smallest (has the property of being in no more than one location) and how their co-existence is the basis of any non-empty collection, whether it is set, list, etc.
 
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You said that the smallest element is zero and you further indicated that the basket=0 due to 5 elements - 5 elements = 0 elements.

You said in the beginning that 0 is the smallest element. So what is the smallest element when the basket is empty and now, according to your latest evaluation, is no longer the smallest element? An orange?
EDIT:

Let us do it this way.

A point has the smallest length 0 and it has nothing to do with the 0 amount of 5 apples - 5 apples.

_____ is not the smallest length 0 but it has a lot to do with the 0 amount of 5 apples - 5 apples along it.
 
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The Man said:
Similarly your “A”, “B” and “C” are still just points that you have defined as being different
EDIT:

Please use your reasoning in order to define them in such a way that they are in the same location AND still they are multiple.
 
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The Man said:
You’re still doing fine, at least in a continuous space there is always another point between any two. Heck, you might actually be learning something here, Doron. Congratulations.
EDIT:

If what you call "continuous space" is defined only by points, then you simply ignore the fact that without a space (which exists between any arbitrary closer 0 spaces) that is greater than any 0 space, the 0 spaces are collapsed into a single 0 space, and no multiplicity of 0 spaces exists.
 
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Tha Man said:
and the number of co-ordinates needed to identify a particular point in some space defines the dimensions of that space
The number of coordinates that are used to define a given point, does not change the fact that it exists in no more than one location at any given space.

This is not the case with a line segment, which exists in more than one location at any given space > 0.
 
EDIT:

Wrong.

Take for example [A,B] or (A,B).

A=point 0
B=point 1
X=____
C= arbitrary point along X AND between A and B

In this case 1 is a limit of 0 C 1 AND X is at B, exactly because X is not a collection of points.
You are about to hit the bottom . . .

There is no X = ______ ; there is only |A - B| = X = 1.

There is no 0 C 1; there is only (0 < C < 1).

X is not at B, coz X is a distance and not a point, and there is no location between A and B where C couldn't be placed. A line segment is not made of points; two points define a line segment and additional points, like that C, can redefine it.

If you want to re-investigate the non-geometric property of a line segment, then you need look at it as |A - B| = x: x in R.

Some sets have infinite cardinality. The set N of natural numbers, for instance, is infinite. Some infinite cardinalities are greater than others. For instance, the set of real numbers has greater cardinality than the set of natural numbers. However, it can be shown that the cardinality of (which is to say, the number of points on) a straight line is the same as the cardinality of any segment of that line, of the entire plane, and indeed of any finite-dimensional Euclidean space.
 
EDIT:

Let us do it this way.

A point has the smallest length 0 and it has nothing to do with the 0 amount of 5 apples - 5 apples.

_____ is not the smallest length 0 but it has a lot to do with the 0 amount of 5 apples - 5 apples along it.

That's it! You just hit the bottom BANG! LOL.

Actually there are folks who really are not into math but for some reason they need to know something, such as

Q: Does a point have the two dimensions of length and width?

A:
No, a point has no length, width, or height and thus has no dimensions. It is defined by a set of coordinates, but itself has no dimensions.
A line has length but no width or height, and thus has 1 dimension.
a plane has length and width, but no height, and thus has 2 dimensions.
a space has length, width and height, and thus has 3 dimensions.
http://wiki.answers.com/Q/Does_a_point_have_the_two_dimensions_of_length_and_width

On the other hand, it doesn't mean that you can't do some jolly-good redefinitions and "correct the mistake" of others. You can knock yourself off no holds barred. Just make sure it's not boring. Funfunfun . . .
 
epix said:
X is not at B, coz X is a distance and not a point, and there is no location between A and B where C couldn't be placed.
X is at least 1-dim and if a segment of 1-dim is defined by at least two 0-dims A and B, it means that they are in co-existence w.r.t each other, such that X is at A AND B, where (A at X but not at B) OR (B at X but not at A).
 
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That's it! You just hit the bottom BANG! LOL.

Actually there are folks who really are not into math but for some reason they need to know something, such as


http://wiki.answers.com/Q/Does_a_point_have_the_two_dimensions_of_length_and_width

On the other hand, it doesn't mean that you can't do some jolly-good redefinitions and "correct the mistake" of others. You can knock yourself off no holds barred. Just make sure it's not boring. Funfunfun . . .

http://www.internationalskeptics.com/forums/showpost.php?p=7148831&postcount=15328
 
X is at least 1-dim and if a segment of 1-dim is defined by at least two 0-dims A and B, it means that they are in co-existence w.r.t each other, such that X is at A AND B, where (A at X but not at B) OR (B at X but not at A).
You are just a few steps away from discovering that if P≠Q, then P<Q XOR P>Q.

After that, there is absolutely nothing standing between you and the breakthrough in solving x + 1 = 2.

And after that . . .

http://en.wikipedia.org/wiki/Fields_Medal
 
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You must cycle and cycle........
th_portal.gif
until the God of Luminous Recognition tells you to stop and follow him to the Source of Wisdom. There are only two parameters

areabrown.png


but that's not the obstacle for computing the brown area in the center.

You must go back to the basics and cleanse yourself to be free of stains and smears that you were soiled with whilst feeding the Beast of Unusual Desire and Demonic Inclination.
350.gif
 
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It is a progress that is closed under your boxes thinking style, or in other words, no progress.

We were all hoping that you realizing you were wrong and admitting it, as you did, would mean you were making progress. Most humans learn from their mistakes.

However, you'd know best, I suppose, so if you say you haven't made any progress in that regard, the rest of us are not in a position to argue.
 
EDIT:

The point is that you are using the concept of collection without the understanding of what enables the existence of this concept, in the first place.

Your reply demonstrates once again that your used reasoning is not capable to grasp the difference between smaller (has the property of being simultaneously in more than one location) and smallest (has the property of being in no more than one location) and how their co-existence is the basis of any non-empty collection, whether it is set, list, etc.

Nope, " the concept of collection" is just, well, a concept. Now a physical collection, like my collection of ELP albums and CD's has certain physical constraints, much like a list. However, the concept of a collection is abstract as is the concept of a set (thus not a list). This is the aspect and differentiation you still seem to fail to recognize.

Again, the interval (1,2) in the natural numbers (also used as ordinal numbers) results in an "empty collection", the empty set. However, in the real numbers that same interval results in a "non-empty collection" that has an infinite number of members. The only one here that has demonstrated an inability to grasp such basic concepts is still just you.


Oh, by the way, you don't have to put "EDIT:" when you make a new post. What you have to do is just to signify such edits on a post you have already made which you have (for whatever reason) changed.
 
The number of coordinates that are used to define a given point, does not change the fact that it exists in no more than one location at any given space.

No one, that I can recall, said that a singular point exists in "more than one location at any given space". So your argument must still be with just yourself.


This is not the case with a line segment, which exists in more than one location at any given space > 0.

Heck, that must be why a line segment is represented by a collection of points or locations in some space. Dang that self-consistency of geometry!!
 
EDIT:

If what you call "continuous space" is defined only by points, then you simply ignore the fact that without a space (which exists between any arbitrary closer 0 spaces) that is greater than any 0 space, the 0 spaces are collapsed into a single 0 space, and no multiplicity of 0 spaces exists.

Again, look up the definition of a continuous space if you want to learn how it is defined. Again, you seem to just want a space without some points. Which technically makes such a space discrete. Look up the definition of a discrete space as well if the difference still confuses you.
 
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