doronshadmi
Penultimate Amazing
- Joined
- Mar 15, 2008
- Messages
- 13,320
At least mathematicians have reasoning. Goodbye.
Wrong dafydd, if X does not get its own reasoning, X does not have a reasoning.
At least mathematicians have reasoning. Goodbye.
If you don't get A, no order of its expression makes it understandable to you, especially if getting A is independent of any particular order of its expression (exactly as X,Y,Z order has no impact on (Z AND X AND Y) = (Y AND X AND Z) = (X AND Y AND Z) ... ect. expression).You could put those words in any order and they would still make as much sense.
Wrong dafydd, if X does not get its own reasoning, X does not have a reasoning.
doronshadmi said:The claim that any post in this thread must be a response to some other poster, is ridiculous.
So X has no reasoning unless it enables to get out of its box in order to borrw some reasoning from Y.X borrowed some reasoning from Y.
So X has no reasoning unless it enables to get out of its box in order to borrw some reasoning from Y.
But X can't do it because its paradigm is context-dependent-only reasoning, as can be seen all along this thread.
Let's look at these phrases given by some traditional mathematician:
""
- Doron presents something claiming it to be traditional mathematical notation.
- Doron defends it by claiming it isn't traditional mathematics notation.
This is wrong since I defend my claims by using only Traditional Maths because <0,1>^k form is a Traditional Mathematics expression.
The dualistic nature of a given axiomatic system is the mutual independence state among its axiom, or in other words, there is no hierarchy of dependency among axioms, so P(S) is not rise form S, as some traditional mathematician wrongly claims (not all traditional mathematicians have reasoning as can be seen, for example, in http://www.internationalskeptics.com/forums/showpost.php?p=8138972&postcount=908).Content dependent paradigm reasoning is contextually dependent upon contextual paradigms and unitary axioms of a dualistic nature. I'm surprised you didn't spot that.
I'd like to know it, please guide me.I prefer Contemporary Jazz maths.
The dualistic nature of a given axiomatic system is the mutual independence state among its axiom, or in other words, there is no hierarchy of dependency among axioms, so P(S) is not rise form S, as some traditional mathematician wrongly claims.
...<0,1>^k form is a Traditional Mathematics expression.
Where, in that sentence, do you read that?
I am only accusing you of posting so that the thread gets bumped into the current listing.
Edit: And that is something I think quite sad.
Wrong, axioms are mutually independent self evident truths (no empirical (in)formation is needed) of a given axiomatic system.P(S) is axiomatically uber-dependent upon S
doronshadmi said:Wrong, axioms are mutually independent self evident truths (no empirical (in)formation is needed) of a given axiomatic system.
mutually independent... neato!
Look how poor is the reasoning of some traditional mathematicians, they can't get simple thing like:
<0,1>^1 expression = 2^1 expression
<0,1>^2 expression = 2^2 expression
<0,1>^3 expression = 2^3 expression
...
etc. ad infinitum, as shown in http://www.internationalskeptics.com/forums/showpost.php?p=8137722&postcount=890.
Wrong, axioms are mutually independent self evident truths (no empirical (in)formation is needed) of a given axiomatic system.