doronshadmi
Penultimate Amazing
- Joined
- Mar 15, 2008
- Messages
- 13,320
Please follow the thread by starting from http://www.internationalskeptics.com/forums/showpost.php?p=10617284&postcount=314.What question?
Thank you.
Please follow the thread by starting from http://www.internationalskeptics.com/forums/showpost.php?p=10617284&postcount=314.What question?
Please follow the thread by starting from http://www.internationalskeptics.com/forums/showpost.php?p=10617284&postcount=314.What question?
Thank you.
Again I ask: What question?
For everyone's convenience, you could make a single, unedited post that begins with "I wish to consider the following question: ..." and goes no further than just phrasing the question.
The question is at the end of http://www.internationalskeptics.com/forums/showpost.php?p=10617284&postcount=314 and it is inseparable part of this post.
"Where's the proof that 0.9999... = 1" is the question? Seriously, that's it?
That's completely separable, by the way. See? I did it right there.
By following after the standard definition (as seen in http://www.internationalskeptics.com/forums/showpost.php?p=10617284&postcount=314)
...what is your answer to this question?
Please provide a link to such place.The proof can be found in lots of places.
I'm sorry you are having trouble following these things. Focus on the "Infinite geometric series" section of the first article and the "Proof of convergence" of the second.
∞ does not rigorously define infinity, so since "Infinite geometric series" and "Proof of convergence" use it, they do not define any rigorous proof.
I take that back.
It does not change the fact that a rigorous proof must be based on infinity as defined by transfinite cardinality for example: aleph0 < aleph1 < aleph2 < ... etc.
∞ does not provide the necessary rigorous terms.
It does not change the fact that a rigorous proof must be based on infinity as defined by transfinite cardinality for example: aleph0 < aleph1 < aleph2 < ... etc.
∞ does not provide the necessary rigorous terms exactly because it does not distinguish between aleph0, aleph1, aleph2, ... etc.
No, I improve it by omitting the "|N|+1=|N|" stuff and its wrong related conclusion, which according to it 0.999...10 = 1 without using 0.000...110.
But now I have realized that it can't be done without adding 0.000...110 to 0.999...10
You do know that 0.9999... is equal to 1.0. In fact, there is no such number as 0.00...1.
Check this out:
x = 0.999...
10x = 9.999...
10x = 9+0.999...
10x = 9 + x
9x = 9
x = 1
In fact we have a wiki page for you. 0.999...WP
It even gives you several examples!!!
You do know that 0.9999... is equal to 1.0. In fact, there is no such number as 0.00...1.
Check this out:
x = 0.999...
10x = 9.999...
10x = 9+0.999...
10x = 9 + x
9x = 9
x = 1
In fact we have a wiki page for you. 0.999...WP
It even gives you several examples!!!
There is no rigorous proof by using inaccurate form like ∞ for infinity.where would the proof break down if your objection did have substance.
Infinity itself (notated by ∞ inaccurate form) actually enters into the argument, exactly as seen in "Infinite geometric series" section of Geometric progressionWP or in "Proof of convergence" section of Geometric seriesWP.Put another way, what purpose does the infinity used in the proof serve, since at no point does infinity itself in any of its possible forms ever actually enter into the argument.
There is no rigorous proof by using inaccurate form like ∞ for infinity.