aggle-rithm
Ardent Formulist
It seems everyone agrees that momentum is conserved in a 'closed' system. So what 'closed' system are we talking about? Upper part C alone? It is the allegedly moving assembly of elements, each with a mass, that, when displacing due to gravity, impacts lower part A, another assembly of elements with masses. Part C is evidently subject to external force - gravity - and its momentum is therefore increasing all the time during free fall until impact, BANG. So part C is not a 'closed' system.
At impact part A evidently applies new forces on part C - again modifying the momentum of part C.
Is part A a 'closed system'? Prior impact it was in static equilibrium and not moving at all. Its momentum was therefore zero. Why was part A not moving? Evidently becase it was attached to part E(arth)! Part E has almost infinite mass compared with parts A and C.
Are parts C and A together, after impact, a 'closed' system? Evidently not as part E applies an external force on it, i.e. on part A.
Are parts C, A and E a 'closed' system? Answer is no! Parts S(un) and M(oon) apply forces on it! A 'closed' system only exists to simplify, e.g. analysis of solid mechanics problems, where you just ignore external forces.
Anyone suggesting that part A is squeezed like a lemon between two bodies, parts C and E, due to gravity forces and conservation of momentum and pressed into a part B - rubble - has not understood basic physics.
You can obfuscate all you want, but the laws of physics will continue to operate as they always have, and not the way you wish them to.