... I am inexpertly confident ...
Now... that is a keeper... well done... QED!!!

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... I am inexpertly confident ...

No you did not... I don't believe you.
That bothers me not at all. My statement was true, and I am confident others can perform the exact same feat without any instruction from me.
Wudang... just like jimbob... and you and others... is concerned about the Math.random() being used to shuffle and pick the "cards" from the "deck of cards".
Now... that is a keeper... well done... QED!!!
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No it was not... and as you said others can prove you wrong every single time.
Do you know how?
By running Coin Flipper V4.1 and seeing for themselves how it will prove you wrong about the "convergence" handwaving and wishful thinking as can be irrefragably demonstrated with the EMPIRICAL DATA
I do have "concerns", if that is the right word, for some of the more inane aspects of your code.
Let's say that one picks the 20th card from the right side of a shuffled and spread out deck of cards every time.
That is not just deterministic... it is not even random
But the deck is shuffled before one picks the 20th card from the right.
Now the deck is not even random numbers... it is the same deck of cards... no?
Do you think anyone can determine whether a red (diamonds/hearts) or black (clubs/spades) card will be drawn??
So
- We have the same deck of cards... no random numbers or changing at all.
- We have the same card position picked every single time... not random or not even unknown... fully determined
- But the cards deck is shuffled before every pick... from the same deck... from the same position
Is the resulting pick (red or black) random?
Is it deterministic? If you say yes... then by whom or what?
Yes I did... many times... I did not say I gave the code at your command... I said I described the code... do you know the difference.
Are you inexpertly confident though?
Maybe you can use some of that confident inexpertise to hazard some answers for the questions in the card post... it might make you see confidently how your inexpertly confident concerns are baseless and unwarranted.
If asked to describe A Tale of Two Cities, I hope you can do better than reading us the first line of the book.

That bothers me not at all. My statement was true, and I am confident others can perform the exact same feat without any instruction from me.
Indeed,
using something like this, for example.
https://stattrek.com/online-calculator/binomial?utm_content=cmp-true
Thanks so very very much. Now I feel really good for the rest of the day...
WOW...
Comparing my code to the Tale Of Two Cities is beyond praise... it is accolades indeed...
These graphs show that as the number of flips per run increases, the relative frequency of heads indeed converges to 50%. In the second chart where there are 1,000,000 flips per run, the deviation is less than 0.1%. The first chart shows a deviation as high as 1% when there are only 10,000 tosses per run.[IMGW=700]http://godisadeadbeatdad.com/CoinFlipperImages/TRNG_Graph_RunData.png[/IMGW]
[IMGW=700]http://godisadeadbeatdad.com/CoinFlipperImages/Crypto_Graph_RunData.png[/IMGW]
These graphs show that as the number of flips per run increases, the relative frequency of heads indeed converges to 50%. In the second chart where there are 1,000,000 flips per run, the deviation is less than 0.1%. The first chart shows a deviation as high as 1% when there are only 10,000 tosses per run.
A single coin toss produces an unpredictable result. But we can predict the approximate results of ten thousand coin tosses. Now, is this random?
"But we can predict the approximate results of ten thousand coin tosses. Now, is this random?"
Crypto Data for 10 Runs @ 10,000 flips/run & Edge Probability 0%
==========================================
Running Averages
--------------------------------
# Heads% Tails% Edges%
--------------------------------
1 0.07000000 -0.07000000 0.0000
2 0.20500000 -0.20500000 0.0000
3 0.28333333 -0.28333333 0.0000
4 0.26000000 -0.26000000 0.0000
5 0.15600000 -0.15600000 0.0000
6 0.05666667 -0.05666667 0.0000
7 0.00285714 -0.00285714 0.0000
8 0.06375000 -0.06375000 0.0000
9 0.08666667 -0.08666667 0.0000
10 0.09100000 -0.09100000 0.0000
================================================
Runs Data
--------------------------------
# Heads% Tails% Edges%
--------------------------------
1 50.0700 49.9300 0.0000
2 50.3400 49.6600 0.0000
3 50.4400 49.5600 0.0000
4 50.1900 49.8100 0.0000
5 49.7400 50.2600 0.0000
6 49.5600 50.4400 0.0000
7 49.6800 50.3200 0.0000
8 50.4900 49.5100 0.0000
9 50.2700 49.7300 0.0000
10 50.1300 49.8700 0.0000
================================================
I have asked repeatedly for anyone to determine this
n = f(p,ε) for p=1 and ε=0
Which are the values necessary for the claim that a coin toss of n coins will result in a determinable guess of the number of heads with no random error.... i.e. deterministic.
Repeating the same bit of nonsense does not make your statement any more profound. It is still nonsense. You do not get to customize definitions to your own personal liking. Doing so doesn't prove you right; it shows you to be desperately wrong. p<1 and 0<ε. The inequality constraints are important.
The claim made in the opening post was, "we can predict the approximate results of ten thousand coin tosses." Stop trying to move the goal posts.
We can predict the approximate results with known confidence, or state how many coin tosses we would need to better an arbitrary confidence and accuracy.
And when you take this to actual physical systems relying on very large numbers, say pressure gauges, or even computer circuitry, we have very good accuracy as percentages.