Bjarne on: Dark Energy, only an illusion.

Status
Not open for further replies.
I did not expect you would understand. I mean you even do not understand that water is heavier than air. How should you understand basic gravity?
But water as a gas is lighter than air, we don't expect you to understand that.

Paul

:) :) :)
 
But water as a gas is lighter than air, we don't expect you to understand that.

Paul

:) :) :)

Clouds caries water
When the upwards wind (etc.) not is strong enough that water will fall the hole way to the ground....
This is why water falls when the upwards moving wind / heat / and moisture/ of a hurricane gets weaker.
At the same time a cow could possible fall.
Because - also cows are heavier than air.
 
I did not expect you would understand. I mean you even do not understand that water is heavier than air. How should you understand basic gravity?
Bjarne, I can ignore your general insolence; after all it only reflects badly on yourself, but stop lying. I have never claimed that water is not heavier than air.

(Water vapor, on the other hand......);) :rolleyes:

And from your reply, I assume you could not answer my question.

Hans
 
Clouds caries water
When the upwards wind (etc.) not is strong enough that water will fall the hole way to the ground....
This is why water falls when the upwards moving wind / heat / and moisture/ of a hurricane gets weaker.
At the same time a cow could possible fall.
Because - also cows are heavier than air.
We have already seen that weather systems is another thing you don't understand. No need to re-iterate. :rolleyes:

Hans :nope:
 
Bjarne, I can ignore your general insolence; after all it only reflects badly on yourself, but stop lying.

I was claiming clouds was carrying water and hence heavier than the surrounding air.
You have denied that.
And this is still a fact.

Where do you expect the COG to be in the building if we assume the lower section (25 meter) is averagely 3 times so heavy as the upper section.
 
Last edited:
Wrong: Same mass and a point halfway beterrn the planets = the same force from each planet:
F = MmG/r^2
​
and so the same ADG.

The equation you now speak about is mass attraction > FORCE -> F = MmG/r^2 This have nothing to do with the discussion.
To calculate ADG - g = MG/r^2
If for example the Earth did have the same mass but the size only would be the half, then you would fall 4 times faster near the surface.
 
This do have something to do with the discussion. Perhaps you've heard of Newton's Law of Universal Gravitation?

I have hear about both Newton's Law of Universal Gravitation, and Mother Cows Law of Universal Gravitation.
 
The equation you now speak about is mass attraction > FORCE -> F = MmG/r^2 This have nothing to do with the discussion.
To calculate ADG - g = MG/r^2
If for example the Earth did have the same mass but the size only would be the half, then you would fall 4 times faster near the surface.
Obvuoiusly.
That is not the situation you describe: 2 planets of equal mass (their sizes do not matter) means that the force of gravity and thus the ADG is zero at a point halfway between them.
F = GMm/r^2
but M = m in your example so
F = GM^2/r^2
and the ADG from each planet is
F/M = GM/r^2
At a point halfway between the planed the ADG is equal and opposite. So no ADG.

​
So when you stated
If the these 2 planet would have the same mass, the ADG would now be 4 times stronger downwards due to that the small planet simply is SMALLER - (half size, but same mass)
You were wrong.
 
I was claiming clouds was carrying water and hence heavier than the surrounding air.
You have denied that.
And this is still a fact.

That is not the same as saying water is heavier than air. The clouds are not heavier than the surrounding air. If they were, they would fall down.


Hans
 
Obvuoiusly.
That is not the situation you describe: 2 planets of equal mass (their sizes do not matter) means that the force of gravity and thus the ADG is zero at a point halfway between them.

If the earth would only be the half size and the mass the same, ADG here would be 4 times faster

That is not the same as saying water is heavier than air. The clouds are not heavier than the surrounding air. If they were, they would fall down.

Imaging a little cloud, 2 % bigger than a cow, and inside that cloud is a cow. - Is that cloud still lighter than the surrounding air ?
 
I have hear about both Newton's Law of Universal Gravitation, and Mother Cows Law of Universal Gravitation.
And you're claiming that Newton didn't know what he was talking about but your bovine confidante does?
 
If the earth would only be the half size and the mass the same, ADG here would be 4 times faster
No it wouldn't.

If you think that's true show us the maths.


Imaging a little cloud, 2 % bigger than a cow, and inside that cloud is a cow. - Is that cloud still lighter than the surrounding air ?
Yes the cloud is. Unfortunately for the cow, however it got there, it is not and will soon be very much an ex cow.
 
If the earth would only be the half size and the mass the same, ADG here would be 4 times faster
That is wrong: The size of the Earth has no effect on the ADG:
ADG = F/m= GM/r^2
​
It only depends on the mass M and distance r from the center of the Earth. If neither changes then ADG does not change.

Maybe you think that r is the distance from the surface of the Earth. You are wrong.

P.S.
Newton showed 300 years ago that the gravitational force (and so ADG) from a sphere is equivalent to the gravitational force (and so ADG) from a point at the center of the sphere with the same mass.
 
I feel sorry for the tax-payer in New Zealand.
After 17 years at a University THIS is what they get;

Bjarne
If the earth would only be the half size and the mass the same, ADG here would be 4 times faster
RC
That is wrong: The size of the Earth has no effect on the ADG:

Notice the word above > “here”
I guess all the cows here on the planet would understand this as "here" – means at the surface of the Earth.

( Except these cows that are in the heavy clouds, of course, )

G = GM/r^2
5,97E24*6,67E-11/6.378E8 = 9,79 m/s
5,97E24*6,67E-11/3.189E8 = 39,15 m/s
 
Last edited:
I feel sorry for the tax-payer in New Zealand.
After 17 years at a University THIS is what they get;
I feel sorry for the tax-payer in Demmark. The education system there has produced a person who is so ignorant that he cannot tell the difference between the number 17 and the number 7 (the actual number of years I spent at university) :rolleyes:!

Notice the word above > “here”
You are right: I did not notice you swapping the subject from your image to just the Earth. The ADG in that image is zero because the point is half way between two planes with the same mass.

Obviously if the Earth was half the size, things on the surface would be twice as close to the center and the ADG would be 4 times greater. This is really basic physics.

So what is your point?
 
Obviously if the Earth was half the size, things on the surface would be twice as close to the center and the ADG would be 4 times greater. This is really basic physics.
Excactly

So what is your point?
The point is there are no point
 
Status
Not open for further replies.

ISF - Join now!

Every member here is approved by hand. No bots, no spam, just people who care about evidence and honest debate.

Membership is free!

Create your free account

Back
Top Bottom