scenario
Let's imagine a super-massive wheel as big as a galaxy (or even bigger if necessary), with fixed spokes/radials joining the circumference to the center.
Now, let's consider 3 points within that wheel upon a single radial. One point on the circumference(z), one point at center(x), and one point
somewhere inbetween the other two, but much closer to the center(x) than the circumference(z).
Imagine the wheel is positioned so that gravitational considerations are approximately equal anywhere within the wheel. Hence, given that the wheel is stationary (at the start), we can say that an observer at each of our three points will be having an almost identical experience of time to one another. I.e., their clocks will all run the same and show the same time if they meet up.
... Now, the wheel begins to rotate so that the observer at position (z) on the circumference eventually accelerates to an extremely high velocity (c/2 for example). The other two observers, of course, are not moving very fast at all.
Question:-
All three observers share the same solid radial. The positions of other galaxies wrt that radial must be the same for all three observers, in reality. I.e., the galactic nightsky must appear to be in the same position for all three observers. If not, then howso? And if so, then in what sense do they all experience time differently?
I've posted this in philosophy because I might make philosophical claims which the science mob won't understand. Rather, they'll refuse to understand.
Let's imagine a super-massive wheel as big as a galaxy (or even bigger if necessary), with fixed spokes/radials joining the circumference to the center.
Now, let's consider 3 points within that wheel upon a single radial. One point on the circumference(z), one point at center(x), and one point
Imagine the wheel is positioned so that gravitational considerations are approximately equal anywhere within the wheel. Hence, given that the wheel is stationary (at the start), we can say that an observer at each of our three points will be having an almost identical experience of time to one another. I.e., their clocks will all run the same and show the same time if they meet up.
... Now, the wheel begins to rotate so that the observer at position (z) on the circumference eventually accelerates to an extremely high velocity (c/2 for example). The other two observers, of course, are not moving very fast at all.
Question:-
All three observers share the same solid radial. The positions of other galaxies wrt that radial must be the same for all three observers, in reality. I.e., the galactic nightsky must appear to be in the same position for all three observers. If not, then howso? And if so, then in what sense do they all experience time differently?
I've posted this in philosophy because I might make philosophical claims which the science mob won't understand. Rather, they'll refuse to understand.