Kwalish Kid
Muse
- Joined
- Feb 24, 2010
- Messages
- 509
A great dark ages suggestion.
[...]
If they're shown something like this:
[qimg]http://media-2.web.britannica.com/eb-media/79/26979-004-CF3F4DA2.gif[/qimg]
I suspect that most people won't have any trouble "seeing" that 1/2+1/4+1/8+... = 1, and that the reaction of "but... infinity!" will be far less common. You can see the entire thing at once; the contrary reaction is irrelevant.
Yet this question is exactly alike. In fact the above is a geometric proof that the binary .111~ = 1. Cases like these are called geometric series, and one can make make a pretty picture for the decimal case of 9/10 + 9/100 + 9/1000 + ... just as well, although it won't be as nicely symmetrical as this one.
[...]
This is great. Thanks for this.
Could I make a request to you or anyone who is able and willing?
I would like to see a graphical representation, despite it's possible asymmetry of 9/10 + 9/100 + 9/1000 + ...
Does someone have the ability to do this in a logical and clean looking way, visually? I would love to see it
I guess what I'm really asking, is, geometrically, what is the most logical way of drawing this out on a sheet of paper?
Take a piece of coarsely ruled graph paper, and draw a line around a 10x10 square. Let that square represent 1.0.I guess what I'm really asking, is, geometrically, what is the most logical way of drawing this out on a sheet of paper?
Take a piece of coarsely ruled graph paper, and draw a line around a 10x10 square. Let that square represent 1.0.
Let the top 9 rows of that 10x10 square represent 0.9. Cross them out, because our 0.9 has accounted for them. That leaves the bottom row, with 10 grid squares.
Let the first 9 grid squares of that bottom row represent 0.09. Cross them out too, because our 0.99=0.9+0.09 has accounted for them. That leaves one grid square in the bottom right corner.
Using a microscope, a ruler, and a very fine-tipped pen, mark a 10x10 grid on that remaining grid square. Repeating the process above will account for 0.9999=0.9+0.09+0.009+0.0009 of the original square. Now mark an even finer grid on the one remaining hundredth of the original bottom right square.
This process can be repeated as long as desired. If we regard the process of going from a 10x10 square to a 1x1 square as one step of the process, then each step adds two more digits to the right of the decimal point. Every point within the interior of the original square will be crossed out by some finite step of this process. (The bottom right point won't ever be crossed out by any finite step, but its singleton set has measure zero so we can disregard it.)
Take a piece of coarsely ruled graph paper, and draw a line around a 10x10 square. Let that square represent 1.0.
Let the top 9 rows of that 10x10 square represent 0.9. Cross them out, because our 0.9 has accounted for them. That leaves the bottom row, with 10 grid squares.
Let the first 9 grid squares of that bottom row represent 0.09. Cross them out too, because our 0.99=0.9+0.09 has accounted for them. That leaves one grid square in the bottom right corner.
Using a microscope, a ruler, and a very fine-tipped pen, mark a 10x10 grid on that remaining grid square. Repeating the process above will account for 0.9999=0.9+0.09+0.009+0.0009 of the original square. Now mark an even finer grid on the one remaining hundredth of the original bottom right square.
This process can be repeated as long as desired. If we regard the process of going from a 10x10 square to a 1x1 square as one step of the process, then each step adds two more digits to the right of the decimal point. Every point within the interior of the original square will be crossed out by some finite step of this process. (The bottom right point won't ever be crossed out by any finite step, but its singleton set has measure zero so we can disregard it.)
No matter how many times this process is repeated, the total are = 1
Uh ... I thought that you had to do this an infinite number of times? As long as you give me any finite number of times, i could tell you exactly how much smaller than 1 your result would be. Right?
(But then, these graphs don't really help my understanding all that much, because I still have to wrap my head around the idea of doing something an infinite number of times.)
Don't think of infinity, think of trends.
People might disagree.Here is a simple demonstration:
Consider that 1/9 = .111...
People might disagree.
I've seen someone state that if you divide 1 by 3, you get 0.33, 0.33 and 0.34
Oh, I get it don't worry. I just don't think the image is helpful to me, personally - so my comments should be taken carefully and with a large grain of salt.
In many different ways. This guy stated in his introduction post that he isn't very good at math and physics, and then proceeded to spout nonsense in every single physics thread on that forum. I tried correcting him a few times, but he stood by his nonsense; he wouldn't learn.Those people are wrong!
Consider what we mean by .333... when we say it equals 1/3. We are taking the ratio of two natural numbers (in this case 1/3) and translating it to a series of fractions where the denominators are ascending powers of ten. First .3 means 3/10. Then .33 means 3/10 + 3/100. Continuing this way, .333 means 3/10 + 3/100 + 3/1,000. Each time we add a fraction in the form 3/10^n we get closer to 1/3. But the expression .333... means we never stop; i. e. we keep adding fractions an infinite number of times, so .333... = 1/3. If that is not convincing enough try to find a number that is between 1/3 and .333...!