The W24 x 55 beams were 53 foot (636 inch) long and that section has a moment of inertia of 29.1 in.^4 in its weak axis. Per the AISC, the modulus of elasticity of structural steel at 600 degrees C is 11,310,000 psi.
The equation for buckling force is
(Pi^2 x modulus of elasticity x moment of inertia) / unsupported length ^2
So, to buckle those beams with their shear studs broken and their temperature at 600 degrees C, the force would be
(3.14^2 x 11,310,000 x 29.1) / (636^2) = 8,030 lbs.
ASTM A325 bolts between 1/2" and 1" have a guaranteed minimum yield strength of 92,000 psi. See
http://en.wikipedia.org/wiki/ASTM_A325
In a forensic analysis the rule is to multiply the guaranteed minimum by 1.1 so the yield strength would be 101,200 psi.
At 600 degrees C steel has lost about half its strength so that puts the yield strength at 50,600 psi. In shear the yield strength is 57.7% of tension and compression. So that puts the bolt shear yield strength at about 29,196 psi at a 600 degree C temperature.
The bolts were 7/8" diameter and had a shear area of 0.601 in.^2 so to shear each bolt would require
29,196 psi x 0.601 in^2 = 17,546 lbs.
To shear the six bolts at each connection would require 105,276 lbs.