Aepervius
Non credunt, semper verificare
Once you've drawn an ace from a normal pack of cards the probability of drawing a second ace is 3/51, not 1/13. The 3rd ace is 2/50 (1/25) and 4th ace is 1/49.
Colour me unimpressed with your statistical abilities.
To be fair it seems he start out of 50 card deck (what sort of deck is that) and so it would be more like probability the first card is an ace is 4/50 second is 3/49 which is indeed 1/13.
But it is a very weird card deck with 50 cards (not divisible by 4, so it is 48 + 2 joker, but then that means 12 cards per colour, or 1-10 + valet + queen and no king I know card deck with *four* heads (Valet, knight , queen , king) but none stopping at queen or not having 1-10.
ETA: I misread this is even MORE confusing than that, he is having a deck full of ace and other deck which are normals. Which is a weird way to try to make a demonstration. But still the probability of a normal deck is 4/52 , 3/51, 2/50, 1/49 to get an ace. In a deck of ace only , you have naturally 13/52 (1/4) chance to get an ace of a certain color at first draw, then 12/52 chance to get the same color again.
So the chance to draw the ace suit without repetition in the first case is :
4/52*3/51*2/50*1/49= 4!*(52-4)!/52!=C(52,4) if i am not incorrect it is the probability to draw 4 specific card combination (any)
For the second deck with only aces you have
13*12*11*10/(52*51*50*49) ETA: forgot to lower the number of card after each draw
Anyway: it is the usual stupid creationist argument of trying to pretend we are obviously not the product of chance therefore god
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