If the front part got torn apart and failed to slow down the plane, how could it punch that hole?
Numbers just for elucidation. I've got no particular interest in gathering up all the info required to do the calculations.
Let's say that the lower portion of the fuselage has sufficient mass in the first 10' to penetrate an UNDAMAGED outer wall, the upper portion of the fuselage would require about 50' to penetrate the same.
Once the nose (& especially the heavier bottom part of the fuselage) splits the outer columns, then the columns are no longer "undamaged". Once the columns have been split, it becomes very easy (i.e., consumes little work) for the columns to be pealed back and/or fractured by both the upper & lower halves of the fuselage.
In the process, the plane gets sliced up too. It is NOT "one or the other" that gets damaged. It's both.
Not all tools are designed for slicing, planes included.
The plane is designed very well to GET sliced.
The walls of the towers, and the thin concrete floors, are designed very well to DO the slicing.
The message that you missed is that it takes much less energy to slice up a plane than it does to compact it.
tfk said:
You can't see the deceleration of the front, shredded parts of the plane on the video because, surprise, there is a wall between the shredded parts and the camera.
It's about the deceleration of the whole plane, Pinkie
Yes, and the answer is that the disassembled, fractured, flying-around debris that used to be the front part of the plane HAS been decelerated. And it's trajectory diverted into 1000 different directions. But you can't see that debris or its velocities in the video, because they are INSIDE the building.
And the back portion of the plane has not slowed down significantly, because the thin wall of the plane cannot carry a lot of axial load.
a = F/m.
If F is small, and m is large, then a is small.
The back portion of the plane doesn't decelerate very much at all, even tho the front, sliced up portions do.
why not... if it was strong enough to demolish steel
Because its a thin wall tube, and the forces applied at the interface of the wall have significant inward components. The tube splits & buckles at that interface, and the forces transmitted axially down the cylinder are close to zero.
me thinks you are all over the place, Pinkie.
You don't understand impacts. You don't understand strength of structures.
Smart ass remarks incline anyone who is trying to teach you about this to toss in the towel on that effort & just point fingers & laugh at your ignorance instead.
Pinkie.
Which way do you want to go?