The use of the bag invalidated Dave Thomas' test to see if loose rubble produces a dynamic load ...
And this is exactly why I've said in the past that, in spite of the fact that some university handed you a diploma after completing 4 years of coursework, I have a serious problem calling you a mechanical engineer.
The one, the only, reason for doing that experiment is to demonstrate the difference between static & dynamic load to people who have absolutely no background, experience with, or feel for mechanics.
Being in the set of people "who have absolutely no background, experience with or feel for mechanics" excludes one (IMHO) from the set of "mechanical engineers".
As Carlitos says, there is no "if" here.
Each individual component has the capacity to deliver a far higher dynamic load than its static weight. No "ifs" allowed.
The STATIC load that the compacted layer can deliver can be determined by looking at the inverse problem: how much force would it take a compactor (i.e., a mechanical crusher) to crush an equivalent structure to its equivalent compaction factor. (Plus the structure's static weight, of course.)
As the debris compacts in the zone between the upper & lower portions, it will deliver its impact more & more like a solid, single structure.
It's pretty clear to me that the amount of compaction that is required for the upper falling mass to destroy the lower, massively weakened upper floor is very small. And one can get an approximation for that number (averaged), from the actual descent acceleration of the upper structure, as about 1/3rd the weight of the upper structure.
I believe that the vast majority of the compaction of the debris happened, not during the descent, but when the debris was finally constrained by the ground, and the upper descending block could finally deliver all of its dynamic load onto the as yet lightly compressed zone, turning it into the highly compressed material seen after the fact.