SnakeTongue
Graduate Poster
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- Aug 16, 2010
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Snaketongue said:36 bodies (1.20m 35Kg) / 2.0m^3 = 18 bodies per cubic meter
09 bodies (1.20m 15Kg) / 0.5m^3 = 18 bodies per cubic meter
Referring to the bold sentences.
Why would bodies with a lower mass result in the same density of bodies per m^3?
Bodies aren't teddybears where you can add or subtract mass in the belly, but where the space the teddybears inhabit remains the same.
Human Bodies which weigh more use more space and thus fewer are able to be in 1 m^3.
In that paradoxical situation, which I do not endorse, “body” is an imaginary unit of measurement with an unknown scale. This allows a “body” with variable mass to share the exact same space in any hypothetical situation. The element “body” in 0.5m^3 becomes exactly equivalent to the element “body” in 2.0m^3.
Of course this is not valid. As you have stated, the volume of a body can change, which means it is variable. Therefore a “body” unit it is not fixed over any common unit. To determine how many bodies a space could hold it is necessary to estimate the volume of the body using a common unit. The volume of each particular body is proportional to mass, height, depth and breadth.
So, the above paradox is what I have been refuting in the Holocaust Controversies calculations:
(...) Alex Bay 106 calculated the space that would be occupied by a human being having the measurements of proportions of Leonardo Da Vinci's "Vetruvian Man", and concluded that 91,000 corpses with the proportions of the "Vetruvian Man" and an assumed height of 68 inches (1.73 meters) could have fit into 8,502 cubic meters of grave space - 10.7 (11) per cubic meter. (...)
(...) The ideal weight of a person 1.73 meters high would be 66 kg for men and 62 kg for women. Taking the lower value, 10.7 human bodies with the measurements and weight of an ideal adult person 1.73 meters high would have a weight of 10.7 x 62 = 663.40 kg (...)
(...) for malnourished Polish ghetto Jews (...), the average would be 663.4 ÷ 34 = 19.51 (20) corpses per cubic meter. 107
(...) The ideal weight of a person 1.73 meters high would be 66 kg for men and 62 kg for women. Taking the lower value, 10.7 human bodies with the measurements and weight of an ideal adult person 1.73 meters high would have a weight of 10.7 x 62 = 663.40 kg (...)
(...) for malnourished Polish ghetto Jews (...), the average would be 663.4 ÷ 34 = 19.51 (20) corpses per cubic meter. 107
Notice that “body” is only “body” in the first and second calculation. Then, in the third calculation the “body” unit suddenly disappears and it is replaced by mass. Height and volume are left aside. This begs the question: is the result “Ventruvian man” or “Polish ghetto Jew”? How does the density of several “Ventruvian man” suddenly become the density of several “Polish ghetto Jews” without any change in the height, but only in the mass? A 1.73 meter “Ventruvian man” filling a cubic meter is still a 1.73m “Ventruvian man” filling a cubic meter. Moreover, whatever mass is assigned to the “Ventruvian man”, the model will always have the same volume. So, in the first calculation the “body” receives an imaginary mass, but its volume remains the same. In the second calculation the imaginary mass becomes the density of the space occupied by a “body”. Then, in the third and final calculation, the density of the “body” with fixed volume is transformed into a new “body” with different volume. In other words, the volume is fixed and does not change with the mass in one calculation, then mass is fixed and changes the volume in another calculation!