Ilooklike ACrowley
Scholar
- Joined
- Jan 1, 2012
- Messages
- 82
If you are simply trying to calculate how "unlucky" your husband is then you do not need to follow the rules of poker. But you do need to know what cards are out of play. For example in the AK v 37.
On the face of it that is a bad beat pure and simple. That's poker.
However if you were able to see the folded hands... and lets assume [as it says the game was online] that it is an eight handed table.
Player 1. Your Hubby is Big Blind with AK
Player 2. Joe has K2 - UTG - Folds
Player 3. Bill has A6 - Folds
Player 4. Mary has K9 - Folds
Player 5. Has the 37 - [low stacked] shoves all in
Player 6. Fred has K10 - folds
Player 7. Lyn has A4 - folds
Player 8. Carlos has A5 - folds
Your husband calls the all in.
He is a 94% dog in that hand.
Now that's me being vicious and setting it up like that.
However using the same method but with random cards selected by the Poker Calculator [I'm using The Hendon Mob Poker Calculator to do this, but I'm sure it's the same as the Cardplayer one.]
I got this scenario:
Player 1. Your Hubby AK
Player 2. Joe has A8
Player 3. Bill has 9 10
Player 4. Mary has 43
Player 5. Has the 37
Player 6. Fred has 46
Player 7. Lyn has AK
Player 8. Carlos has Q8
In that situation your husband is 12% to win and 37 is 10% to win.
The poker calculator only goes up to 8 players but you can see why I say it's important how many players are at the table. And why your calculations will be flawed unless you take into account all the cards. The probability that poker players deal with by necessity has to rule out of the entire deck. Hence a player knows his outs.
Now I then ran ten simulations with an eight handed game. Giving your husband AK and random hands to other players as selected by the computer.
AK percentage chance of winning were:
1 - 12%
2 - 7%
3 - 21%
4 - 3%
5 - 11%
6 - 18%
7 - 26%
8 - 16%
9 - 16%
10 - 21%
That means on average in an eight handed game AK is expected to win 15% of the time.
Same routine but this time with 5 players.
1 - 45%
2 - 33%
3 - 24%
4 - 28%
5 - 42%
6 - 29%
7 - 30%
8 - 29%
9 - 15%
10 - 28%
That means on average in a five handed game AK is expected to win 30% of the time.
Now of course you begin to see why it all makes a difference - although of course my sample is too small I dare say it's a logical assumption to make that the more cards dealt [to players] the smaller the chances are of AK being the best hand by the end of play.
On the face of it that is a bad beat pure and simple. That's poker.
However if you were able to see the folded hands... and lets assume [as it says the game was online] that it is an eight handed table.
Player 1. Your Hubby is Big Blind with AK
Player 2. Joe has K2 - UTG - Folds
Player 3. Bill has A6 - Folds
Player 4. Mary has K9 - Folds
Player 5. Has the 37 - [low stacked] shoves all in
Player 6. Fred has K10 - folds
Player 7. Lyn has A4 - folds
Player 8. Carlos has A5 - folds
Your husband calls the all in.
He is a 94% dog in that hand.
Now that's me being vicious and setting it up like that.
However using the same method but with random cards selected by the Poker Calculator [I'm using The Hendon Mob Poker Calculator to do this, but I'm sure it's the same as the Cardplayer one.]
I got this scenario:
Player 1. Your Hubby AK
Player 2. Joe has A8
Player 3. Bill has 9 10
Player 4. Mary has 43
Player 5. Has the 37
Player 6. Fred has 46
Player 7. Lyn has AK
Player 8. Carlos has Q8
In that situation your husband is 12% to win and 37 is 10% to win.
The poker calculator only goes up to 8 players but you can see why I say it's important how many players are at the table. And why your calculations will be flawed unless you take into account all the cards. The probability that poker players deal with by necessity has to rule out of the entire deck. Hence a player knows his outs.
Now I then ran ten simulations with an eight handed game. Giving your husband AK and random hands to other players as selected by the computer.
AK percentage chance of winning were:
1 - 12%
2 - 7%
3 - 21%
4 - 3%
5 - 11%
6 - 18%
7 - 26%
8 - 16%
9 - 16%
10 - 21%
That means on average in an eight handed game AK is expected to win 15% of the time.
Same routine but this time with 5 players.
1 - 45%
2 - 33%
3 - 24%
4 - 28%
5 - 42%
6 - 29%
7 - 30%
8 - 29%
9 - 15%
10 - 28%
That means on average in a five handed game AK is expected to win 30% of the time.
Now of course you begin to see why it all makes a difference - although of course my sample is too small I dare say it's a logical assumption to make that the more cards dealt [to players] the smaller the chances are of AK being the best hand by the end of play.
