MM,
Yup.
As opposed to "near free fall".
A critical concept with which you have had extraordinary difficulty.
Except that it only "looks just like a controlled demolition" to rank amateurs.
There were a bunch of CD professionals hanging around WTC7 when it collapsed (from Protec). They have clearly stated that, to them, "it looked nothing like a CD".
And then, when engineers examined the velocity & acceleration profiles of the external wall in detail, surprise, surprise, it does not look like a CD.
Now, you have taken down with explosives precisely zero buildings, I trust. (Feel free to correct me if I wrong about that.) The CD pros have taken down 100s of buildings. You disagree with their assessment. Fine. Please explain to me why we should take your word over theirs.
Except for three little facts:
1. it wasn't really in free fall.
2. CD's don't really fall in free fall.
3. CD professionals say "it wasn't a CD".
… other than that ...
Nope. NIST didn't say that. Better read the NIST assertions again.
You ain't doing very well here, MM.
___
Now, since you're having so much trouble with velocity versus acceleration, let me provide you with a quick synopsis. And where your thought process is derailing.
All of the below statements are true.
You have been saying that, if an objects velocity is zero, then its acceleration must be zero. That's wrong.
1. An object can have any velocity (negative, zero or positive) and its acceleration can be any value (negative, zero or positive). In any combination. (v+, a+), (v+, a-), (v+, a0), (v-, a-), (v0, a+), [your fave:] (v0, a0), (v0, a-), etc.
2. You allude to the statement that "if an objects velocity is zero (and imply to yourself without saying it "and it stays zero"), then its acceleration is zero."
This statement is correct. But the unspoken part "and it stays zero" translates into "its acceleration is zero". If the velocity stays at any value whatsoever, then its acceleration equals zero.
You're essentially saying "if its acceleration is zero, then its acceleration is zero".
This is true.
It's just not very useful or perceptive.
Glad to help.
tk
Cannot be in "pure freefall" as compared to some other form of freefall?
Yup.
As opposed to "near free fall".
A critical concept with which you have had extraordinary difficulty.
So it is back to the; "the collapse looks just like a controlled demolition but since we won't accept any proof that it was", it can't be, argument.
Except that it only "looks just like a controlled demolition" to rank amateurs.
There were a bunch of CD professionals hanging around WTC7 when it collapsed (from Protec). They have clearly stated that, to them, "it looked nothing like a CD".
And then, when engineers examined the velocity & acceleration profiles of the external wall in detail, surprise, surprise, it does not look like a CD.
Now, you have taken down with explosives precisely zero buildings, I trust. (Feel free to correct me if I wrong about that.) The CD pros have taken down 100s of buildings. You disagree with their assessment. Fine. Please explain to me why we should take your word over theirs.
CD clearly explains the observed freefall collapse.
Except for three little facts:
1. it wasn't really in free fall.
2. CD's don't really fall in free fall.
3. CD professionals say "it wasn't a CD".
… other than that ...
http://img263.imageshack.us/img263/9872/set3sccompositeua1.png
The NIST calculation of Stage 2 freefall was based on the observation of "the entire upper half of the the north wall" doing what you now claim was not pure freefall.
Nope. NIST didn't say that. Better read the NIST assertions again.
You ain't doing very well here, MM.
___
Now, since you're having so much trouble with velocity versus acceleration, let me provide you with a quick synopsis. And where your thought process is derailing.
All of the below statements are true.
You have been saying that, if an objects velocity is zero, then its acceleration must be zero. That's wrong.
1. An object can have any velocity (negative, zero or positive) and its acceleration can be any value (negative, zero or positive). In any combination. (v+, a+), (v+, a-), (v+, a0), (v-, a-), (v0, a+), [your fave:] (v0, a0), (v0, a-), etc.
2. You allude to the statement that "if an objects velocity is zero (and imply to yourself without saying it "and it stays zero"), then its acceleration is zero."
This statement is correct. But the unspoken part "and it stays zero" translates into "its acceleration is zero". If the velocity stays at any value whatsoever, then its acceleration equals zero.
You're essentially saying "if its acceleration is zero, then its acceleration is zero".
This is true.
It's just not very useful or perceptive.
Glad to help.
tk