Nope. What the English version of the book says is (my bolding):
Quote:
If we assume that the distribution of protons in nuclei is approximately the same as the distribution of neutrons (there is good evidence for this assumption)
1- please make the scanning of the page,
and post it here, as I did
2- what is the quantative differente between the
same distribution and
approximately the same distribution ?
So it doesn't make any statement there about how the nucleons are paired.
Of course not, since Eisberg and Resnick have not direct experimental finding that deuterons are formed.
But it's an unavoidable conclusion, because:
1- If protons and neutrons have the same (or approximately) distribution, then protons and neutrons are very close.
2- So, due to the strong force, protons and neutrons have to interact, because as the diameter of the nucleus is so short then the distance between must to be or the order of the range of strong force.
3- A proton and neutron attracted by strong foce take the form of a deuteron.
There is no need to be a genius to get the conclusions above.
Furthermore the average spatial distributions can be the same and not be anything like deuteron pairing since that also requires temporal correlations.
Your conclusion is wrong, as we realize it from the argument exposed by me above.
There are experimental evidences (as mentioned by Eisberg and Resnick) that protons and neutrons take the same (or approximatelly) the same distribution, and such distribution imply the 3 conclusions of mine above.
Your opinion is not of interest, since it is disagree to experimental evidences mentioned by Eisberg and Resnick
Finally, if that wasn't enough, the distribution being referred to include those of gold and bismuth. All gold and bismuth isotopes have far more neutrons than protons. So how were you intending pairing them all up?
What's the problem?
This occurs not only in gold and bismuth. All heavy nuclei have far more neutrons than protons.
But protons and neutrons form deuterons within the nuclei when neutrons are available to get a partnership with protons.
The excess of neutrons A-Z continues as neutrons within the nucleus.
If you actually read what the whole passage is trying to explain, it is simply saying that the charge and matter density distributions (which are a function of radius) are (approximately) the same excepting a scaling factor related to the proton/neutron ratio of the nucleus.
Of course I did read it.
However, you stated in later post that protons and neutrons do not form deuterons within the nucleus, and you claimed that there is not experimental evidence supporting such assumption.
And I proved you're wrong, because the experimental evidence do exists, as mentioned by Eisberg and Resnick, denying your words.