The heat output and copper production say something nuclear is happening.
For the sake of argument, let's pretend I agree. I have already objected to any interpretation of the crappy measurements and their sloppy and unreliable interpretation as "heat output". I have no data on the measurements that have been interpreted as copper production.
Do you feel so comfortable with 'basic physics' that you can assume that existing knowledge is reason to reject the possibility of a nuclear reaction?
The association between nuclear reactions and gamma rays is extremely basic physics. The reason there's energy available
at all in (e.g. 62Ni+p = 63Ni) is that the protons/neutrons in 63Ni have a special low-energy arrangement whose mass is lower than any other arrangement of 28 protons and 35 neutrons. The statement "the energy is released" means the protons and neutrons have to
get to the special arrangement, and on the way they have to get rid of the excess energy that distinguishes one state from the next.
This list of states is unique; it's discrete; it's determined by quantum mechanics. The spacing between the steps is of order ~200 keV. The last step is 669.9 keV. There is
no way to get to the 63Ni ground state, from any higher state, without emitting a "packet" of 669.9 keV (or more) in the discrete leap from a higher state to the ground state. Anything less---"I'll take a 669,900 steps of 1 eV each"---violates quantum mechanics.
Why a 669.9 keV
gamma ray, you might ask? Why not something less detectable? Sorry, there is nothing less detectable. There is no such thing as a 669.9 keV phonon. If it's neutrinos or something you have undone the "generate heat" part of the business. Low-energy photons, etc., would have to violate quantum mechanics as I have said.
Can you explain why one specific nucleus of a radiosotope undergoes fission while adjacent nuclei of the same material do not? If nuclear reactions are well understood, then it should be possible to predict which nucleus will react.
Yes, nuclear physics is very well understood. Some details of shell structure are hard to compute accurately, but the principles are basically perfectly secure. Fusion thressholds are not merely "well understood", they're directly observed. You can shoot a p beam, of any energy you like, at a 62Ni target. At energies below the Coulomb barrier, nothing happens. At energies above the Coulomb barrier, you start seeing fusion, including these excited-state gamma rays.
My position is that the reaction will be shown to be real or not over the next year or so.
Not if the only way they study it is by wrapping a brick in lead, plugging in nonfunctional instrumentation into it, and giving a press conference about it.