Merged Theory links Newtonian/Quantum the amazing Frank Znidarsic

[JCM]

Hello Forum
I have come across the research of a scientist named Frank Znidarsic and wondered what others think about its focus. His work in Bose-Einstein condensates, advancement of the super-conductive work of Eugene Podkletnov, and the transition of an orbital electron to a different electronic shell of an atom is very intriguing. The research shows the path of the quantum transition has actually been revealed. Might any Physics/Mathematics PhDs in the forum take a look at the papers pdf linked below. The first is of particular interest.
Quantization of Energy
http://www.mediafire.com/?hfv0z326e2fp0h3
The Duality of Matter and Waves
http://www.mediafire.com/?mmv0tlixkbo2ew8
The Control of the Natural Forces
http://www.mediafire.com/?7yr67ncka846v77
The Elastic Limit of Space and the Quantum Condition
http://www.mediafire.com/?4nig5ybc545dcoh

So 1.094 megahertz-meters is the speed of the quantum transition.

 

[JCM]

Thumb equation calculates Planck's constant with the frequency of an emitted photon

So anyone with a knowledge of Quantum Mechanics care to take me up on a gentleman's bet? I bet I can calculate Planck's constant, by ONLY knowing the frequency of an emitted photon; NOT knowing the energy level of the photon at all, on an equation that can fit on my THUMB.
Try me?

 

[JCM]

Seriously

Actually I can do MORE than that. I can do the same thing using a DIFFERENT equation on my other THUMB. I can also calculate the frequency of an emitted photon WITHOUT using planck's constant AT ALL. Not only that I can calculate the energy level of the emitted photon,calculate the radius of a hydrogen atom ,calculate the probability of transition, and finally calculate the Compton frequency of an electron all WITHOUT using planck's constant AT ALL and of course with a THUMB equation.

All is this is done ONLY knowing the speed of transition.

 

[This is The End]

OK, go!

 

[TubbaBlubba]

"The control of the natural forces leading to cold fusion and anti-gravity".


This sounds familiar. Is this the guy who exactly "calculated Planck's constant" by studying the aforementioned purported phenomena?

 

[TubbaBlubba]

No, you can't.

 

[JCM]

Firsts things first I am going to produce both Planck's constant and the energy level of the emitted photon. All I need to know to do this is the frequency of an emitted photon and the speed of the quantum transition which of course is 1.094 Mhz-Meters.

Equation #1

V _t = Speed of transition = 1.094 Mhz-Meters
F = Frequency of the emitted photon = known by experimental measurement
lambda = wavelength of photon during transition

The eq. is stating that the speed of transition is equal to the frequency of the emitted photon (how many times it is oscillating between its electrostatic and magnetic fields per second multiplied by how far the oscillation goes each time aka the distance traveled each time it oscillates)

Displacement X frequency = speed. The wavelength of the photon in the transitional state is analogous to the displacement. Since we measure the frequency of the emitted photon (experimentally) (f) and we know the speed (1.094Mhz-Meters) (V) we switch the eq. around to get the wavelength.

Equation #2

The wavelength calculated isn't the wavelength of the emitted photon though this is the wavelength of the photon smushed together (compressed) in side the transitional state. The wavelength is compacted. This compression of the wavelength during the quantum transition is what gives a photon its particle like properties. Why is this transitional wavelength important? We take it and put it in the form of a flat plate capacitor.

To do this let me explain eq. 3

Equation #3 In any electrical engineering text

e ₀ = the permittivity of free space = the vacuum's ability to take on a field = the electric constant
A= Area of each plate capacitor
D= Distance between each plate capacitor
C= capacitance = volume over charge (1 electron = 1 charge) = measure of an electric charge relative to a volume

The pressure of the charge is called the voltage. As the volume increases the capacitance increases. As the capacitance decreases the pressure increases aka the volume gets smaller. Higher field pressure = higher voltage

In eq. 3 we are using two dimensional field capacitors which are just square in dimension and the distance between them makes it three dimensions.

In this case we will use the product of eq. 2 (transition wavelength of the photon) for all three dimensions

which produces

Equation #4

which can be reduced to

Equation #5

plugged with eq. 2

We get then

Equation # 6

With eq. 6 we know the capacitance of the transitional state

Equation #7 in any electrical engineering textbook

Q=Charge
This equation states energy contained in a system equals the charge of the system squared divided by two times the capacitance

Substituting eq. 6 capacitance into eq. 7

We get eq. 8

Equation #8

And my friends
BOOYAH!

What's in the brackets!>??!?!?!>?!>!!>?@>?
But wait I thought all of this was IMPOSSIBLE?

 

[Dave Rogers]

So anyone with a knowledge of Quantum Mechanics care to take me up on a gentleman's bet? I bet I can calculate Planck's constant, by ONLY knowing the frequency of an emitted photon; NOT knowing the energy level of the photon at all, on an equation that can fit on my THUMB.
Try me?

OK, go ahead. A photon is emitted with a frequency of 193THz. Calculate Planck's constant, showing your working and demonstrating that no other information has been used. When you've finished, I'll see if I can show you what other information you've used without knowing it.

ETA: Oh, I see what the trick is. You're defining a speed of transition which is linearly dependent on Planck's constant, then assigning a value to it that's derived from Planck's constant. So what you're saying is that, provided you know Planck's constant, you can derive Planck's constant. Unless you can come up with some better derivation of your Vt = 1.097MHz m than "of course", colour me unimpressed.

Fitting the equation on your thumb isn't that impressive, incidentally. With a relatively commonplace e-beam writing system, I could get the entire text of the Wikipedia article on Planck's constant on my thumb.

Dave

 

[JCM]

Sorry dave but there is more to this

Planck's constant from a purely classical approach? But wait there is more my dears.

Planck's constant = h

And you get Einsteins Photo-Electric Equation

This means Planck's constant is completely irrelevant and is just a function of the speed of transition. Planck's constant doesn't mean anything. That's what Planck was looking for his whole life.

The Quantum divide has been bridged

The frequency of the emitted photon does not match the frequency of anything within the static atomic state. It doesn't match the Compton frequency of the electron angular frequency of the electron, it doesn't match anything.

Classically the frequency of the emitter always exactly matches that of the wave that is emitted. This logic is how these equations were derived.

The emitted photon which is an electromagnetic wave that propagates away from the atom must match the frequency of the emitter and the emitter in this case is the transitional state itself not any of the static states. This is because a photon is only emitted by the state of transition.

The speed of transition in fact CAN be discovered from first principles. Quantum mechanics is a subset of classical physics. The frequency of the emitted photon does indeed match the frequency of the emitter(the transitional frequency)


All of this is correct because not only did it do the impossible by producing Planck's constant but it also produced a correct energy level of the photon. Einstein's Photo-Electric Equation and Planck's on a fluke? THAT'S what I'd be skeptical of

 

[JCM]

Unless you can come up with some better derivation of your Vt = 1.097MHz m than "of course", colour me unimpressed.

Would you believe an angel whispered it to me? Its actually 1.094 MHz m or 1,094,000 m/s which is the speed of the quantum transition. As I stated Planck's constant is meaningless its just a function of the speed of transition.

Fitting the equation on your thumb isn't that impressive, incidentally. With a relatively commonplace e-beam writing system, I could get the entire text of the Wikipedia article on Planck's constant on my thumb.

Who needs an e book reader when you have a thumb? Thumb thing was really just saying how small these equations are and how basic the math is but they have big ramifications.

 

[JCM]

Is this the guy who exactly "calculated Planck's constant" by studying the aforementioned purported phenomena?

He calculated the speed of the quantum transition of which Planck's constant is just a meaningless function of

 

[Dancing David]

Is there a site that does not require a download?

I notice that the top hits for his name are not exactly physics publications.

 

[Dancing David]

Um, could you use latex instead of the over large graphics?

It looks as though you have already just dismissed the first critique, and Monday is just startinge

 

[Dancing David]

Sorry dave but there is more to this

Planck's constant from a purely classical approach? But wait there is more my dears.

Planck's constant = h
[qimg]http://img337.imageshack.us/img337/3796/watcn.png[/qimg]

And you get Einsteins Photo-Electric Equation
[qimg]http://img210.imageshack.us/img210/7894/einstein.png[/qimg]

This means Planck's constant is completely irrelevant and is just a function of the speed of transition. Planck's constant doesn't mean anything. That's what Planck was looking for his whole life.

The Quantum divide has been bridged

The frequency of the emitted photon does not match the frequency of anything within the static atomic state. It doesn't match the Compton frequency of the electron angular frequency of the electron, it doesn't match anything.

Classically the frequency of the emitter always exactly matches that of the wave that is emitted. This logic is how these equations were derived.

The emitted photon which is an electromagnetic wave that propagates away from the atom must match the frequency of the emitter and the emitter in this case is the transitional state itself not any of the static states. This is because a photon is only emitted by the state of transition.

The speed of transition in fact CAN be discovered from first principles. Quantum mechanics is a subset of classical physics. The frequency of the emitted photon does indeed match the frequency of the emitter(the transitional frequency)

I see problems here.

 

[Dave Rogers]

Would you believe an angel whispered it to me?

Yes, I'd believe you believe that. But seriously, what is your source for the number?

Its actually 1.094 MHz m or 1,094,000 m/s which is the speed of the quantum transition.

It's actually the reciprocal of Planck's constant multiplied by the square of the electron charge and divided by four times the permittivity of free space. So it's dependent on Planck's constant. By quoting 1,094,000m/s you are, in effect, using Planck's constant in your calculation, unless you can show some alternative derivation of it.

So let's see this derivation, please. Remember, it has to use only the freuency of the transition, and no other information.

Dave

 

[Dave Rogers]

Sorry dave but there is more to this

No, there isn't. All you've done is derive a number that depends linearly on Planck's constant, then substituted it in. Nothing new to see here.

This means Planck's constant is completely irrelevant and is just a function of the speed of transition.

Or that the 'speed of transition' is completely irrelevant and is just a meaningless quantity derived from Planck's constant.

Dave

 

[TubbaBlubba]

Looking at his other thread, he seems to be basing this of a fringe physicist (I'd call him crackpot if I were merited) whom I recall from my brief day at physicsforums.com - I believed he claimed to be able to calculate the exact value of Planck's constant by studying anti-gravity and cold fusion.

 

[JCM]

Is there a site that does not require a download?

Yes here are direct view links

http://tinyurl.com/2g4gyv9

I notice that the top hits for his name are not exactly physics publications.

Yes which is why I wanted to share the papers directly

 

[MattusMaximus]

Sorry dave but there is more to this

Planck's constant from a purely classical approach? But wait there is more my dears.

Nope. As soon as you start talking about electron transitions (regarding your v_t number) between energy levels, you are no longer talking about classical (pre-20th century) physics. Try again.

The Quantum divide has been bridged

You know, you're about 100 years too late on this, right?

ETA: Plus, what Dave Rogers said. Your argument is essentially circular in nature *yawn*

 

[JCM]

What must be understood is the transition photon is a Three Dimensional Capacitor

Looking at his other thread, he seems to be basing this of a fringe physicist (I'd call him crackpot if I were merited) whom I recall from my brief day at physicsforums.com - I believed he claimed to be able to calculate the exact value of Planck's constant by studying anti-gravity and cold fusion.

You must be thinking of someone else or are building a strawman?
Frank spent 20 years getting this math down and pondering the implications of its findings. This is not some crackpot he has spoken at John Hopkins University.

But seriously, what is your source for the number?

Yup the crux of the matter, where did that number come from? Well it is also the speed of mechanical wave propagation in the nucleus. Frank Znidarsic himself explains where he derived the number from in this short youtube video here.

Your argument is essentially circular in nature *yawn*

It can seem that way but you are misunderstanding.