doronshadmi
Penultimate Amazing
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- Mar 15, 2008
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No epix, you have the joy to be against no matter what, why and how.
Here are the relevant part, taken from http://www.math.toronto.edu/mathnet/questionCorner/geomsum.html
It is this limit which we call the "value" of the infinite sum.
How do we find this value?
If we assume it exists and just want to find what it is, let's call it S. Now
S = 1 + 1/2 + 1/4 + 1/8 + · · ·
so, if we multiply it by 1/2, we get
(1/2) S = 1/2 + 1/4 + 1/8 + 1/16 + · · ·
Now, if we subtract the second equation from the first, the 1/2, 1/4, 1/8, etc. all cancel, and we get S - (1/2)S = 1 which means S/2 = 1 and so S = 2.
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In your example, the finite sums were
1 = 2 - 1/1
3/2 = 2 - 1/2
7/4 = 2 - 1/4
15/8 = 2 - 1/8
and so on; the nth finite sum is 2 - 1/2^n. This converges to 2 as n goes to infinity, so 2 is the value of the infinite sum.
1) Traditional Math explicitly uses = , such that S - (1/2)S = 1 which means S/2 = 1 and so S = 2
2) The term value is explicitly used at the end of the answer.
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