doronshadmi
Penultimate Amazing
- Joined
- Mar 15, 2008
- Messages
- 13,320
oppsss..
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It is better than your imagination, which according to it totally local and different distinct 0-dim spaces completely cover a 1-dim space.
It must be so "clear" that the writer who contributed to the unrelated topic in Wiki didn't bother to support your assertion. The truth of the matter is though that the writer didn't get infected by OM, and so the concurrence is missing from the text. Obviously, you don't have the slightest idea what the text is all about, otherwise you wouldn't use it as a supporting argument for one of your declaration of independence.Wrong.
Let us take, for example 3() and 2():
You can’t comprehend that 3() exists independently of any 2() spaces w.r.t it, as clearly seen in the following diagram:![]()
http://en.wikipedia.org/wiki/Euclidean_subspace
It has to be stressed that this diagram is a piece of 3() space, which has a form of a cube, where a cube is a complex w.r.t 3() exactly as a line segment is a complex w.r.t 1().
Unfortunately Geometric algebra is often introduced using many terms and symbols that are foreign to most people, the result being that it remains inaccessible to many without a sufficient background in Mathematics.
Your reference is a poor excuse bag staffed with irrelevancy and it can't avert the disaster OM is heading for, e.g. it is becoming obvious that OM cannot manipulate very small but finite numbers, coz it doesn't have the means to express them.So now your smoke prevents from you to get what have been written in http://www.internationalskeptics.com/forums/showpost.php?p=6499689&postcount=12164.
There are two finite positive numbers a and b such as a < 1 and b < 1. Number a has twenty thousand zeroes after the decimal point and ends with 1318; number b has twenty-five thousand zeroes after the decimal point and ends with 666. How does OM express the multiplication of both numbers and its result; how does a*b = c look like in OM?
If you had used other letters than x and y, which are letters reserved for points that lie on the x and y coordinates, I wouldn't have to be that descriptive. You put anything that you call 1() object into one bag and make far-reaching conclusions . . .Do you understand that a point is totally local where immobility is one of its essentials?
You are right epix, because he\she and you suffering of the same misunderstanding that does not comprehend the independence of different things w.r.t each other.epix said:It must be so "clear" that the writer who contributed to the unrelated topic in Wiki didn't bother to support your assertion.
epix said:Btw, the description of a point "moving" ...
Of course it is. Doron's imagination by far excels over everyone else's.
Let's consider a cube with axis U, S and A that has volume 1776 units. Independence is rendered with those 2-dim spaces OUTSIDE the cube, NOT INSIDE. as you demonstrate, coz the modification of a 2-dim subspace affects the property of a 3-dim space, coz both differently dimensioned spaces share the same coordinates 'x' and 'y'. Independence is about apart and not together. You need to quote from any related text so the quote would directly address the issue of independency between an n-dim object and its subspace.You can’t comprehend that 3() exists independently of any 2() spaces w.r.t it, as clearly seen in the following diagram:
[qimg]http://upload.wikimedia.org/wikipedia/commons/thumb/c/cd/Secretsharing-3-point.png/220px-Secretsharing-3-point.png[/qimg]
http://en.wikipedia.org/wiki/Euclidean_subspace
Do you understand that a point is totally local where immobility is one of its essentials?
coz the modification of a 2-dim subspace affects the property of a 3-dim space
0.000...1[base 10], for example, is not a finite number, but it is the irreducibility of 1() to 0() upon infinitely many scales.You shouldn't worry about that anyway, coz you still need to demonstrate that OM is capable of multiplying very small but finite numbers.
there was once a local point
that decided to smoke a joint
as its lungs got really busy
the point became really dizzy
with no value, with no sign
it fell quickly off the line
that's what happened, now you prove
that the point just couldn't move.
No The Man.
1-dim space exists independently of any sub-space like 0-dim space along it.
Your 0-only reasoning simply can't get anything without using 0-dim space.
If only non-local number 0.999...[base 10] and local number 1 are considered, then there is 0.000...1[base 10] between them , such that ...1 is a line (with no points along it) between 0.999...[base 10] and 1.
Your limited 0-only reasoning is exactly the framework that its users\developers have to apologize in front of the the people around the world, because they are deliberately forcing their ignorance for the past 3000 years on our civilization and block any improvement of the understanding of Complexity and its essential building-blocks.
Next time try to understand that your 0-only reasoning can't comprehend the independence of the existence of spaces w.r.t each other.
http://en.wikipedia.org/wiki/Euclidean_subspace
No The Man, a space is not a collection, and you simply can't get it because your reasoning is limited to 0-only elements.
The Man, you still do not get that your R members are exactly distinct 0() spaces, and each distinct 0() space is different from another distinct 0() space only if there is 1() space between them, where only 1() can be at AND beyond the location of any given distinct 0() (which is a property that no 0() space has.)
It is better than your imagination, which according to it totally local and different distinct 0-dim spaces completely cover a 1-dim space.
They can't comprehend the independence of different things w.r.t each other, such that no thing is defined by any other thing, accept itself.
sympathic it simply avoids the contradiction that is derived from the imagination which claims that distinct and different 0-dim spaces completely cover 1-dim space.
The claim that 0-dim spaces completely cover 1-dim space is equivalent to the claim that
an arbitrary pair of different and distinct 0-space are = AND ≠ w.r.t each other.
0.000...1[base 10], for example, is not a finite number, but it is the irreducibility of 1() to 0() upon infinitely many scales.
Of course there are cases where the independency holds. Suppose that the pic you've presented as a "proof"Wrong, any given space is essentially independent of any other space.
To one called epix.Whom do you reply to?
Which once again makes your “1()” dependent on there being more than one “distinct 0()”. That they depend upon each other ( your “1()” and your “another distinct 0()”) does not make them independent but mutually dependent.
And I bet that you don't type that. That's a copy/paste job START -> MY DOCUMENTS -> DORON_REPLIES.Again, stop simply trying to posit aspects of your own failed reasoning onto others.
Again, stop simply trying to posit aspects of your own failed reasoning onto others.
Again, stop simply trying to posit aspects of your own failed reasoning onto others.
epix, your transparent box is another collection of 2() spaces that there existence is independent of each other, and so is the 3() space that is used as their common environment, the 3() space exists whether it is used as a common environment of infinity many independent 2() spaces, or not.Of course there are cases where the independency holds. Suppose that the pic you've presented as a "proof"
http://en.wikipedia.org/wiki/File:Secretsharing-3-point.png
shows a plastic box with three sheets of cardboard paper as the 2-dim subspaces. You can rearrange the sheets any way you wish but that shuffling around wouldn't affect the size and the shape of the plastic box, the same way stirring goulash will not affect the size and shape of the cooking pot. This is an observation that may intrigue a one-year old baby, but can we like move along ahead on the timeline?
If only non-local number 0.999...[base 10] and local number 1 are considered, then there is 0.000...1[base 10] between them , such that ...1 is a line (with no points along it) between 0.999...[base 10] and 1.