doronshadmi
Penultimate Amazing
- Joined
- Mar 15, 2008
- Messages
- 13,320
Please give a detailed example.Yes, and right from page 1, those things that are there are wrong.
Thanks, Edited.What an interesting choice of words.
Please give a detailed example.Yes, and right from page 1, those things that are there are wrong.
Thanks, Edited.What an interesting choice of words.
Please give a detailed example.
It only demonstrated that Moshe's formula and ON's representation were a partial case of ONs. Nothing was demonstrated as wrong about the notion of parallel/serial observation or (a) < (b) < (c).It was demonstrated wrong.
It only demonstrated that Moshe's formula and ON's representation were a partial case of ONs. Nothing was demonstrated as wrong about the notion of parallel/serial observation or (a) < (b) < (c).
ONs were generalized at http://www.scribd.com/doc/21967511/...considerations-of-Some-Mathematical-Paradigms .
And yet again, your reading comprehension skills and ability to hold a thought beyond one post have abandoned you.
The subject at hand is that your recently reference spewage in PDF form has math errors beginning on page 1. These very same errors have been trotted out by you some time ago. The errors were discussed then and exposed for what they were. Yet, now, you again trot them out, still bearing the very same errors, and you see nothing wrong with them.
Your math, starting on page 1, is now and always has been in error. You can't even get your generator formula to work properly, and that bodes poorly for the rest of your spewage in PDF.
The generator formula deals with a partial case of ONs and the article explicitly says that. Actually you are the one that showed that my ONs representation was a partial case of ONs
...yet you were unable to understand that this article is not based on how many ONs forms are represented but about the notion of parallel/serial observation and Distinction as an additional property to Cardinality and Ordinality.
Furthermore, Moshe's generator formula is nothing but the serial case of ONs, but you can't get that because your reasoning is limited to a one-id reasoning ( http://www.internationalskeptics.com/forums/showpost.php?p=5927914&postcount=9791 ).
In other words, you have no meaningful thing to say about this subject, because all you get is its serial aspect by using only one-id reasoning.
You showed that it is a partial case on ON's, that's all.I showed more than that. I showed that your original presentation was completely bogus. Why have you returned to it?
It was a minor error that has no impact on the main subject of that article, which deals with more than one-id reasoning.You may assume, as I have stated, that your spewage begins with serious mathematical errors. Since your document makes such a bad start, the credibility of anything that follows is severely disadvantaged.
You completely miss the fact that this function generator is a partial case under one-id reasoning, and therefore has no meaningful impact on that article.Again, you presume to know what I do and to not understand, while completely missing the point. The generator function as published is junk. It has all the same errors you started with the first time you presented.
Moshe has another generator that defines the amount of ONs that is based on your correction, but again, this is nothing but a minor subject of this article, that, again, has a minor impact on that article. You can't change the fact that you get this article only from a one-id reasoning, which is nothing but a particular case of it that was corrected by Moshe. I'll ask Moshe to give his new version of the formula, but again, it is nothing but a minor case of this article, which is a fact that you can't get because of your inability to get things that are not based on one-id reasoning.Most of us here know you don't seem to get anything right. Buy could you at least make things less wrong when corrections are handed to you?
It is exactly the case that you get things only by one-id reasoning, and as a result can't get that article.It is more the case that you keep changing the subject because your lack of focus and comprehension denies you basic abilities needed to maintain a dialogue.
You showed that it is a partial case on ON's, that's all.
It was a minor error that has no impact on the main subject of that article, which deals with more than one-id reasoning.
You completely miss the fact that this function generator is a partial case under one-id reasoning, and therefore has no meaningful impact on that article.
Moshe has another generator that defines the amount of ONs that is based on your correction, but again, this is nothing but a minor subject of this article, that, again, has a minor impact on that article.
You can't change the fact that you get this article only from a one-id reasoning, which is nothing but a particular case of it that was corrected by Moshe.
I'll ask Moshe to give his new version of the formula, but again, it is nothing but a minor case of this article
...which is a fact that you can't get because of your inability to get things that are not based on one-id reasoning.
It is exactly the case that you get things only by one-id reasoning, and as a result can't get that article.
Again, Moshe truly did his best in order to find ways to communicate with other one-id reasoning's scholars in order to open their mind to OM in a step-by-step fusion.
But it simply can't be done, because form a one-id reasoning you can't get OM and you jsfisher unable to see things beyond one-id reasoning, exactly as Moshe can't.
The limitation of one-id reasoning is shown in http://www.internationalskeptics.com/forums/showpost.php?p=5927914&postcount=9791.
You still do not understand that you are using a one-id reasoning, where A has simultaneously one and only one id, called True, False or whatever.
A non-one-id reasoning deals with the simultaneity of being more than a one id, which is a contradiction only if it is understood in terms of a one-id reasoning.
Both one-id and non-one-id reasonings are derived form that has no id, which is the "transparent" base ground that enables the full expression of any given "color", where a "color" can be a one-id reasoning or a non-one-id reasoning, in this case.
You may claim: one-id reasoning AND non-one-id reasoning, is a contradiction (always False in your language).
By doing that you are simply using a one-id reasoning in order to conclude something about
one-id reasoning AND non-one-id reasoning, and get a contradiction (always False in your language), which is a must have result of a one-id reasoning, where A has simultaneously one and only one id, called True, False or whatever.
By taking a one-id reasoning as the one and only one valid reasoning, you simply miss the non-one-id reasoning and the base ground of any reasoning that has no id.
2x2
(AB,AB) (AB,A) (AB,B) (AB) (A,A) (B,B) (A,B) (A) (B) ()
A * * A * * A * . A * . A * * A . . A * . A * . A . . A . .
| | | | | | | | | | | | | | | | | | | |
B *_* B *_. B *_* B *_. B ._. B *_* B ._* B ._. B *_. B ._.
(2,2) = (AB,AB)
(2,1) = (AB,A),(AB,B)
(2,0) = (AB)
(1,1) = (A,A),(B,B),(A,B)
(1,0) = (A),(B)
(0,0) = ()
0x0
(0)=()
1x1
A * .
(1) = (A)
(0) = ()
2X2
(AB,AB) (AB,A) (AB,B) (AB) (A,A) (B,B) (A,B) (A) (B) ()
A * * A * * A * . A * . A * * A . . A * . A * . A . . A . .
| | | | | | | | | | | | | | | | | | | |
B *_* B *_. B *_* B *_. B ._. B *_* B ._* B ._. B *_. B ._.
(2,2) = (AB,AB)
(2,1) = (AB,A),(AB,B)
(2,0) = (AB)
(1,1) = (A,A),(B,B),(A,B)
(1,0) = (A),(B)
(0,0) = ()
3X3
A . . .
| | |
B . . .
| | |
C ._._.
(3,3,3) = (ABC,ABC,ABC)
(3,3,2) = (ABC,ABC,AB),(ABC,ABC,AC),(ABC,ABC,BC)
(3,3,1) = (ABC,ABC,A),(ABC,ABC,B),(ABC,ABC,C)
(3,3,0) = (ABC,ABC)
(3,2,2) =
(ABC,AB,AB),(ABC,AB,AC),(ABC,AB,BC)
(ABC,AC,AC),(ABC,BC,BC)
(3,2,1) =
(ABC,AB,A),(ABC,AB,B),(ABC,AB,C)
(ABC,AC,A),(ABC,AC,B),(ABC,AC,C)
(ABC,BC,A),(ABC,BC,B),(ABC,BC,C)
(3,2,0) = (ABC,AB),(ABC,AC),(ABC,BC)
(2,2,2) =
(AB,AB,AB),(AB,AC,AB),(AB,BC,AB)
(AC,AC,AC),(AC,AB,AC),(AC,BC,AC)
(BC,BC,BC),(BC,AB,BC),(BC,AC,BC)
(2,2,1) =
(AB,AB,A),(AB,AB,B),(AB,AB,C)
(AB,AC,A),(AB,AC,B),(AB,AC,C)
(AB,BC,A),(AB,BC,B),(AB,BC,C)
(2,2,0) = (AB,AB),(AB,AC),(BC,BC)
(1,1,3) =
(A,A,ABC),(B,B,ABC),(A,B,ABC)
(A,C,ABC),(B,C,ABC)
(3,1,0) = (ABC,A),(ABC,B),(ABC,C)
(3,0,0) = (ABC)
(1,1,2) =
(A,A,AB),(A,A,AC),(A,A,BC)
(B,B,AB),(B,B,AC),(B,B,BC)
(A,B,AB),(A,B,AC),(A,B,BC)
(A,C,AB),(A,C,AC),(A,C,BC)
(B,C,AB),(B,C,AC),(B,C,BC)
(2,1,0) = (AB,A),(AB,B),(AB,C),(AC,A),(AC,B),(AC,C),(BC,A),(BC,B),(BC,C)
(2,0,0) = (AB),(AC),(BC)
(1,1,1) =
(A,A,A),(B,B,B),(C,C,C)
(A,A,B),(A,A,C),(B,B,A)
(B,B,C),(C,C,A),(C,C,B),(A,B,C)
(1,1,0) = (A,A),(B,B),(C,C),(A,B),(A,C),(C,B)
(1,0,0) = (A),(B),(C)
(0,0,0) = ()
Let us try to change the attitude of this discussion.
Jsfisher, The Man, ddt and Skeptic I need your help in order to define the general formula which returns the number of the elements of the following mathematical structure:
First, some definitions:
x is an element.
Definition 1: Identity is a property of x, which allows its recognition.
Definition 2: Copy is a duplication of a single identity.
Definition 3: If x has more than one single identity, then x is called Uncertain.
Definition 4: If x has more than one single copy, then x is called Redundant.
k = 0 to n, where n is a natural number.
Let us try to change the attitude of this discussion.
Jsfisher, The Man, ddt and Skeptic I need your help in order to define the general formula which returns the number of the elements of the following mathematical structure:
First, some definitions:
x is an element.
Definition 1: Identity is a property of x, which allows its recognition.
Definition 2: Copy is a duplication of a single identity.
Definition 3: If x has more than one single identity, then x is called Uncertain.
Definition 4: If x has more than one single copy, then x is called Redundant.
k = 0 to n, where n is a natural number.
----------------------------------------------
Definition 1: Identity is a property of x, which allows its recognition.
Definition 2: Copy is a duplication of a single identity.
Definition 3: If x has more than one single identity, then x is called Uncertain.
Definition 4: If x has more than one single copy, then x is called Redundant.
x=A is different “Identity” than x=B, correct?
Would x=AB be a different “Identity” than x=A or x=B? Would it be a union of those two 'identities'?
Would x=AA be different than x=A?
2X2
(AB,AB) (AB,A) (AB,B) (AB) (A,A) (B,B) (A,B) (A) (B) ()
A * * A * * A * . A * . A * * A . . A * . A * . A . . A . .
| | | | | | | | | | | | | | | | | | | |
B *_* B *_. B *_* B *_. B ._. B *_* B ._* B ._. B *_. B ._.
(2,2) = (AB,AB)
(2,1) = (AB,A),(AB,B)
(2,0) = (AB)
(1,1) = (A,A),(B,B),(A,B)
(1,0) = (A),(B)
(0,0) = ()
0x0
(0)=()
1x1
A * .
(1) = (A)
(0) = ()
2X2
(AB,AB) (AB,A) (AB,B) (AB) (A,A) (B,B) (A,B) (A) (B) ()
A * * A * * A * . A * . A * * A . . A * . A * . A . . A . .
| | | | | | | | | | | | | | | | | | | |
B *_* B *_. B *_* B *_. B ._. B *_* B ._* B ._. B *_. B ._.
(2,2) = (AB,AB)
(2,1) = (AB,A),(AB,B)
(2,0) = (AB)
(1,1) = (A,A),(B,B),(A,B)
(1,0) = (A),(B)
(0,0) = ()
3X3
A . . .
| | |
B . . .
| | |
C ._._.
(3,3,3) = (ABC,ABC,ABC)
(3,3,2) = (ABC,ABC,AB),(ABC,ABC,AC),(ABC,ABC,BC)
(3,3,1) = (ABC,ABC,A),(ABC,ABC,B),(ABC,ABC,C)
(3,3,0) = (ABC,ABC)
(3,2,2) =
(ABC,AB,AB),(ABC,AB,AC),(ABC,AB,BC)
(ABC,AC,AC),(ABC,BC,BC)
(3,2,1) =
(ABC,AB,A),(ABC,AB,B),(ABC,AB,C)
(ABC,AC,A),(ABC,AC,B),(ABC,AC,C)
(ABC,BC,A),(ABC,BC,B),(ABC,BC,C)
(3,2,0) = (ABC,AB),(ABC,AC),(ABC,BC)
(2,2,2) =
(AB,AB,AB),(AB,AC,AB),(AB,BC,AB)
(AC,AC,AC),(AC,AB,AC),(AC,BC,AC)
(BC,BC,BC),(BC,AB,BC),(BC,AC,BC)
(2,2,1) =
(AB,AB,A),(AB,AB,B),(AB,AB,C)
(AB,AC,A),(AB,AC,B),(AB,AC,C)
(AB,BC,A),(AB,BC,B),(AB,BC,C)
(2,2,0) = (AB,AB),(AB,AC),(BC,BC)
(1,1,3) =
(A,A,ABC),(B,B,ABC),(A,B,ABC)
(A,C,ABC),(B,C,ABC)
(3,1,0) = (ABC,A),(ABC,B),(ABC,C)
(3,0,0) = (ABC)
(1,1,2) =
(A,A,AB),(A,A,AC),(A,A,BC)
(B,B,AB),(B,B,AC),(B,B,BC)
(A,B,AB),(A,B,AC),(A,B,BC)
(A,C,AB),(A,C,AC),(A,C,BC)
(B,C,AB),(B,C,AC),(B,C,BC)
(2,1,0) = (AB,A),(AB,B),(AB,C),(AC,A),(AC,B),(AC,C),(BC,A),(BC,B),(BC,C)
(2,0,0) = (AB),(AC),(BC)
(1,1,1) =
(A,A,A),(B,B,B),(C,C,C)
(A,A,B),(A,A,C),(B,B,A)
(B,B,C),(C,C,A),(C,C,B),(A,B,C)
(1,1,0) = (A,A),(B,B),(C,C),(A,B),(A,C),(C,B)
(1,0,0) = (A),(B),(C)
(0,0,0) = ()
Jsfisher, The Man, ddt and Skeptic I need your help in order to define the general formula which returns the number of the elements of the following mathematical structure:
First, some definitions:
x is an element.
Definition 1: Identity is a property of x, which allows its recognition.
Definition 2: Copy is a duplication of a single identity.
Definition 3: If x has more than one single identity, then x is called Uncertain.
Definition 4: If x has more than one single copy, then x is called Redundant.
As you see Uncertainty is at the level of the element, where Redundancy is at the level of the collection.
In what way is the term, property, different from your invented term, identity? The "which allows its recognition" is superfluous. Are you just continuing a practice of new terms for old without adding any new content?
What are you trying to accomplish with this definition? Cardinality, for example, is a property of any set. Given two sets, both of which must have a cardinality property. Is one of them a copy of the other?
What are you trying to accomplish with this definition. Everything has more than one property. How is the set {1,3} "uncertain" just because it has both cardinality and members?
I think you are focused more on creating names than meaning.
Items in "Parallel" have cardinality is we deal with finite size, but the identity of each element is uncertain.Apathia said:Items in "Parallel" are not yet counted in quantity. With bridging there is "Seriality" and a quantity.
Not at all. {a,b}={b,a} and it is accepted by mathematicians.Apathia said:But then you make the point that "order doesn't matter."
This, of course, smashes the definition of ordinality to pieces. Not that that bothers you any, but it smashes communication with others as well.
Especially mathematicians.
I get that.
How do you indicate in a formula when a number is at the element level or when it is at the collection level?