What I want to know: Have any of these so called solid surface features been seen in images taken at different times? If they're solid, they should persist, right?
Actually, GeeMack is quite correct, and you are way wrong. Helioseismology is extremely supportive of the standard model.
There is nothing at all in the paper you cite which supports your erroneous interpretation. This paper is fully consistent in all respects with open flowing convection.You mean *EXCEPT FOR* that "subsurface stratification" where your gas model "predicted" an open and flowing convection zone?
http://xxx.lanl.gov/abs/astro-ph/0510111
As for MOND, the primary reason you see lots of papers about MOND is because a lot of people just don't like the idea of dark matter. The issue at hand for them is gravity in the extremely weak field limit and whether or not Newtonian gravity is the correct weak field limit of general relativity.
Indeed so, I said that all wrong. I meant to say something more like ... "whether or not Newtonian gravity is the correct weak field limit of gravity". The point of studies like the one I cited is that they find no evidence in cosmological data that there is any deviation from general relativity, meaning no deviation from Newtonian gravity, as the weak field limit of physical gravity. This favors the dark matter hypothesis over the modified gravity hypothesis.That's not quite right. There is no question about whether Newtonian gravity is the weak-field limit of GR - it is.
Interesting question.
As for where to begin, I suggest you figure out the minimum thickness a sphere of iron would have to be, dependant on diameter. At some point, I imagine you'll either wind up with a solid sphere, or a limit, but it's just a guess. I'd have to look into the equations to be certain.
I probably won't get around to it though.
But it shouldn't be hard. If you can find the right equations...
Hogwash. Once again you just invent fake facts out of thin nothing. We have discussed this before, and you are being just as obstinately stupid now as you were then. The 2.223 Mev line observed by RHESSI is a well known signature of neutron capture and has nothing at all to do with discharge processes, which do not generate line emission, aside from the obvious fact the neutral neutrons do not take part in electrical discharge events. Likewise, the neutron capture has nothing at all to do with solar powering nuclear fusion events, which involve charged particles (e.g., the proton-proton & CNO cycles), require far higher energies to overcome the Coulomb barrier, and generate neutrinos with energies specific to the particular reaction. To the best of my knowledge, neutron capture reactions do not generate any neutrinos at all, so there is no way these gamma rays can have anything to do with the falsely claimed lack of fusion power in the sun.Not to mention visible gamma rays from the discharge process, and fusion processes as well.
http://svs.gsfc.nasa.gov/vis/a000000/a002700/a002750/
Yeah, I can imagine an iron shell which was too big to be stable might crush itself; the iron flowing rather like squashed clay.
What you cannot do is understand what you read.
Helioseismology
(emphasis added)
The web page is very careful to state that the Sun acts as a resonant cavity. In other words it can be modelled as if is was a a resonant cavity.
This is a symptom that we often see from cranks. Their ignorance leads them to think that a model is the thing itself. So you are just deluding yourself that using a resonant cavity model means that teh Sun is an actual resonant cavity as in electronic devices.
I also see that you are imitating Micheal Mozina's delusion about running difference images being actual picures.
I thought that you were smarter but obviously I was wrong![]()
Right. So you're not into REAL science. Got that.
Right. You don't do REAL science. Got that.
Aye, it's much easier when you can just SAY that your BS idiocy already fits, instead of actually doing the actual work.
Proving once again that you have absolutely NO understanding of the subject.
Pure fantasy.
The term "resonant cavity" in this usage doesn't mean the sun *has* a cavity within it, just the modes of oscillation follow similar principles.
Did you not catch the line:
"Acoustic waves become trapped in a region bounded on top by a large density drop near the surface, and bounded on the bottom by an increase in sound speed that refracts a downward propagating wave back toward the surface." ?
This is similar to the way acoustic waves can become channeled between layers of different acoustic refractive index in the body of the Earth, or between different water (temperature and salinity) layers in the ocean, or how fiber optics keep light waves confined with variable refractive indices of the material.
But see, you DON'T know NEARLY as much as you imagine you do; you need to go back and cover all the basics before you will have any idea how far wrong you are.
Which, sadly for you, only emphasizes how pitifully out of your depth you have wandered.
Cheers,
Dave
Iron's quite ductile, isn't it? I was just wondering how large a hollow iron sphere could be before it ceased to be rigid enough and collapsed under its own gravity. Don't really know where to begin, though.
Making something up and tuning it to observations is real science.If making something up and tuning it to match observations is real science, then have at it.
I prefer science that makes predictions.
I have a question about that image. It appears to show a solid surface with ridges and other terrain elevation features. These features can be seen in the image because they have distinct highlights and shadows that make them appear to be strongly and directionally illuminated, from a source located to the upper right of the area (since the highlights face that direction and the shadows are opposite) and from an elevation considerably above the plane of the surface (because the shadows are short).
My question for the iron sun proponents is, what's the source of that directional illumination?
If we're going to interpret the image based on what it looks like, it sure looks like there's a directionally localized light source brighter than the sun's surface shining on the sun's surface. What and where is that light source?
Respectfully,
Myriad
.
!Do you mean by this that the sun could be either a hollow region surrounded by a rigid shell of solid iron or fully solid sphere of iron?My model is a fully iron shell or solid.
The melting point of iron is 1811 Kelvins, and its boiling point is 3134 Kelvins. The effective temperature of the photosphere of the sun is 5777 Kelvins, which significantly exceeds both of those temperatures. Exposed to a temperature that high the iron will not "thermalize" anything, certainly not by any physics that works in this universe. It will melt & boil & vaporize, and it will do so fairly quickly.
Sunspots are not "holes" in the photosphere. They are more analogous to "bubbles" of enclosed in a magnetic field than they are to "holes". Furthermore, helioseismology reveals the 3D structure of sunspots (e.g., Duvall, et al., 1996; Zhao, Kosovichev & Duvall, 2001; Gizon, et al., 2009 and citations thereto).In sunspots the lowest temp measured was 3180K Sunspots are holes in the photosphere.
The page you quoted talks about heat flowing back from the corona to the photosphere, which is totally irrelevant to the matter at hand. Coronal maximum particle densities range from about 109 e-/cm3 at the base (1.003 solar radii) to about 103.2 e-/cm3 at 20 solar radii. But at optical depth of 1.0 the particle density of the photosphere is about 7.7x1013 e-/cm3, 1.2x1017 H/cm3, a total mass density about 4 gm/cm3 for the photosphere, compared to about 10-20 gm/cm3 for the corona. So the actual energy density of the photosphere is many orders of magnitude greater than that of the corona, even if the temperature of the corona is orders of magnitude grater than the temperature of the photosphere.From Scientific American ...
By no wild stretch of the imagination is the photosphere a "thin" plasma. It is an optically thick plasma and we can clearly see that it emits easily recognized, Planck Law, blackbody radiation, with absorption lines superimposed on it. Only the very thin regions (chromosphere, corona & etc) exhibit line emission. If your solid & rigid iron shell is below the photosphere, then it will be directly impacted by bolometric thermal emission from the overlying photosphere. And remember my earlier post ...Only a small amount of energy (light) comes from the photosphere since its a thin plasma I would expect it to have lines.
So there is no getting around the key point: Your solid & rigid iron shell is staring at least 9400 Kelvins (probably more) right in the face. Under these circumstances, physics as we know it to be makes both "solid & rigid" physical impossibilities.Furthermore, one must remember that 5777 Kelvins is an effective temperature, a best fit blackbody to an actual thermal emission that is a superposition of blackbody emission curves that are generated at different depths in the photosphere. ... The temperature at the lowest level we can determine is 9400 Kelvins. We don't see much of that on Earth, because of the opacity of the overlying layers. But your iron surface is pretty much hugging the 9400 Kelvin base of the photosphere.
All I have to go on is helioseismology.
... which shows that there is nothing like a solid surface on the Sun.
You seem to be under the impression that only objects with rigid boundaries can resonate. That is quite wrong. Anything that exists can resonate. It is easy for the sun, with, no rigid surface at all, to act as a resonator. I have already referenced the appropriate sources of knowledge ...How could the sun be a resonant cavity with harmonics unless it was???? Not a decreasing density ball of plasma.
The kind of boundary you are thinking of is not at all required by helioseismology, so there is no positive reason to assume such a boundary exists. Furthermore, other areas of physics, such as thermodynamics, argue very convincingly that such a rigid boundary cannot exist. Remember, one cannot pick & choose the bits & pieces of physics we like and then discard & ignore the rest. Physics is an all or nothing affair. If helioseismology says yes, but thermodynamics says no, then clearly our interpretation of one or the other must be wrong. I choose my (correct) interpretation of thermodynamics over your (erroneous) interpretation of helioseismology every time.Actually, GeeMack is quite correct, and you are way wrong. Helioseismology is extremely supportive of the standard model. This is extensively documented in the literature; e.g., Helioseismology, Jorgen Christensen-Dalsgaard, Reviews of Modern Physics 74(4): 1073-1129, November 2002; The Internal Rotation of the Sun, M.J. Thompson, et al., (not me & no relation that I know of), Annual Review of Astronomy and Astrophysics 41: 599-643 (2003), and the many citations to both. More recently, see M.J. Thompson, 2010; Gizon, Birch & Spriut, 2010; Solar Interior Rotation and its Variation, Rachel Howe, Living Reviews in Solar Physics 6(1), February 2009 (free access online); Zhao, et al., 2009; Chaplin & Basu, 2008; Christensen-Dalsgaard, 2007; Gough, 2006 & etc. Finally, see the book Stellar Astrophysical Fluid Dynamics, edited by M.J. Thompson & Jorgen Christensen-Dalsgaard, Cambridge University Press 2003.
The idea that a bounded sphere is implied by helioseismological data is unacceptable, and very much contradicted by the weight of scientific study of the topic.
was answered byNuclear fusion reactions generate both neutrinos and gamma rays. However, from the sun we see only neutrinos, but none of the gamma rays. If, as you say, "neutrino emission is from fusion activity on the surface of the sun", then the obvious question is ... Where are all the gamma rays that we should see but don't see?
That actually ties into the question about the Aether. Its not that neutrinos are from the fusion activity, its that they are from reactions that are aether based. In other words the reaction that emits a neutrino(that unit of energy) is actually an aether reaction that emits a particle that we term a neutrino. This particle also occurs in other aether transactions that we term nuclear reactions, in which a neutrino is emitted. They dont have to be fusion events to produce neutrinos although they are both the result of the same mechanism, the pinch(reconnection).
...some more gibberish...
All you guy have done is show me your model and said "Your wrong" when your model does no better(actually worse) then what I have offered.
Only because you think that gravity is right.
And fusion is in the center of the sun.
Here is a talk that will show the state of "physics" and why it is permissible from me to speculate a new model of gravity.
Plugging in some routine values, the compressive load on the shell is ~38,000 times the compressive yield strength for a decent steel at room temperature. Now, there are some improvements possible; if it was a huge single crystal, you might be able to triple the compressive strength. And if the temperature is above the Austenite conversion temp, you'll pick up a little more. So maybe the an idealized shell would have 0.0001 (0.01%) of the needed compressive strength.
Thanks dasmiller. Thanks Ziggurat. I love this forum....it isn't the force itself which limits us, but the pressure. And the pressure is P = F/A = F/Lz. That gives us
P = gpR/8
Now let's plug in some numbers:
g = 274.0 m/s2p = 7.874 g/cm3 = 7874 kg/m3R = 6.96x108 m
P = 1.87x1014 Pascals = 1.87x105 GPa
Which is about 10,000 times the pressure needed to form diamond. Iron, and basically any other material, will indeed flow under that kind of non-isotropic pressure.