Hokulele
Deleterious Slab of Damnation
Well, it depends on the strength of the top glass element and the bowling ball - the two elements in contact only!
So the connections between the glass and supports don't come into play at all?
Strange.
Well, it depends on the strength of the top glass element and the bowling ball - the two elements in contact only!
So the connections between the glass and supports don't come into play at all?
Strange.
Let's assume that the bowling ball, C, is rigid and does not absorb any energy at impact, i.e. all kinetic energy, E, is applied to the top glass element, A80.
Let's now assume that A80 is broken and that exactly energy E is used for that!
So nothing is transferred to the connections between A80 and the supports?
Strange.
Not really ...
The videos with which you are not familiar describe a particular type of demolition, in which a single floor's worth of supports is suddenly destroyed through cables and hydraulics. This leaves an upper section to fall upon the lower portion, which is frequently much larger than the upper part. The entire structure is destroyed, despite no weakening at all being applied to the lower portion.
The path of least resistance, in regard to matter, is directly related to Newton's third law. The difference between the law and the principle here is; an object in motion will always stay in motion unless acted upon by an outside force, while an mass will only follow the path of least resistance unless it exerts work to do otherwise.
You need to think through your analogies better. If you start to roll down a hill and there is a bump in your path you will not magically go around it. What happens when you approach that bump will depend on your built-up momentum and the size and shape of the bump.For instance, find yourself a nice grassy hill, lay down, and let yourself roll down it. Doing so, you will follow the path of least resistance
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As I say, it is quite simple. Just do the analysis, step by step, and you'll find out what happens and the problem is solved.
Ah, yeah, they were mentioned to me in a PM by another member erlier as "the French demos", I simply wasn't familiar with the term "verinage". Anyway, the videos you posted do show an unsual form of controlled demolition, using cables to pull out supporting structure rather than explosives to blast it out. Furthermore, note how the velocity of the upper mass decreases after coming into contact with the lower mass, demonstrating the resistance provided by that lower mass. Also consider how much more the deceleration would have been had that lower structure been not simply concrete but rather also framed with steel.
Sure, like if you stack 80 glass coffee tables on top of each other and then drop a bowling ball on that; once it starts, it's all over, eh? Assuming 10mm glass with a 1 kg/mm/mm tensile strength spaced 500mm apart, and a 10 kg ball with a 200mm diameter given say 100m over the top of the structure just for fun, how close to free fall would expect that ball to get after connecting with the first sheet of glass?
Again, the path of lease resistance is a law in the physics of electricity, Ohm's law.
You were worried someone would take him seriously?His opinion should be set at naught.
You knew that going in, Ryan!Oh, my aching head.
...
In my last reply, somewhat in jest, I referred you to the "integral sign" in my derivation. Apparently you really don't know what that means. The division by 3 is not at all arbitrary; it is, in fact, a pretty good representation of the actual Tower. Anyway, what we learn from this is that you cannot follow even a simple potential energy calculation, even when all the work is shown for you and dumbed down to a high school sophomore level.
fixed that---From my experience, we don't define Structural integrity, except as a SF for worst case combined loads--then add 50% MUFNo. A Newton is a unit of force. Structural integrity is not equivalent to a force. As I said, the structural integrity is not awelldefined quantity. How well a structure will perform under load is not an intrinsic property of the structure. You have to specify the conditions in much more detail. For instance, two forces that arrive at different angles may have dramatically different effects on the structure.
This is why my calculation does not attempt to gauge "structural integrity." Can't be done. Instead, I looked at energy absorption. And that, again, is what you asked for, even though you've run far away from that discussion ever since.
To be fair, "I" is referred to as Moment of Inertia, and strength is a function of "I", as in P*L3/(48*E*I)I cannot emphasize enough how nonsensical the above is.
"Interia" is not "elements of structural strength." Inertia is, depending on how you're looking at it, either mass or momentum. It has units of kilograms or Newton seconds, respectively. The WTC Towers have the same inertia before and after the collapse, although clearly the structural integrity before versus after is radically changed.
The point which you keep missing, for reasons that are now only too obvious, is that the timing of the "crush-down" style collapse is primarily governed by the mass of the structure and its contents. It is momentum transfer that slows the descent. The strength of the lower block also slows the descent, but not much, practically a round-off error. You could double the strength of the WTC Towers without changing the mass and hardly notice the difference.....
I'm done with you unless you want to learn. In that case, we can help.
Now I’ve got coffee over the screen. I should’ve quit while I was ahead!!!
Woof!
Ohm's law:
E=IR is simply an equation that says "the voltage is equal to the current times the resistance". It does not mention paths or renting property.
snaking cable and running det-cord go hand in hand right? lol
Indeed, through several years of post secondary schooling and 30 years of experience in the feild of electronics I have never heard the term "path of least resistance" used by my peers.
I understand implicitly that current will be higher in circuits of less resistance(given the same voltage supply) and I suppose one could, if one had some reason to do so, describe that as the electrons shunting to the path of least resistance.
However the analogy quickly breaks down given that in a complex piece of equipment several ciruits fed from the same power supply will have different curents than others. If the electrons were required to flow in the path of least resistance then current would be flowing in only one of those circuits.
It would suck for any parallel circuitry![]()