bill smith
Philosopher
- Joined
- Feb 14, 2009
- Messages
- 8,408
.
LoL.
As I said, "What proof?"
Please point at the proof that you are referring to.
It's as simple as copying a link from your post.
tk
Maybe later if you are a good boy.
.
LoL.
As I said, "What proof?"
Please point at the proof that you are referring to.
It's as simple as copying a link from your post.
tk
.I think they believe it was something like "gradually pouring powder or sand onto the lower section". Kinda like saying an avalanche is harmless because it's made of fluffy snow... I... don't... think... they've... seen... what... an avalanche... can do. When a couple hundred thousand cubic feet of snow hits a person like a brick wall at 60 miles an hour
.Maybe later if you are a good boy.
From my paper:
When 33 000 tons of mass above in WTC1 falls down 3.7 metres due to gravity during and crushes all the columns abt 340 kWh (1.22 GNm) of potential, PE, or kinetic energy, KE, is produced by gravity force and a fair part of that energy is consumed to crush the columns. Let's assume that this event by gravity takes 5-6 seconds based on video clips (it should only take 0.8-0.9 seconds near free fall) and that there is a certain velocity when the upper part impinges the lower structure. In reverse - to first stop and second pull the upper block back up again you need a very big engine with power 204 000 kW that pulls up the mass above. Let's assume this engine is very effective and that you require 120 grams of diesel oil to produce 1 kWh. It means that 40 800 grams or 40.8 kgs of diesel oil is required to stop and pull the mass up again! It takes 6 seconds! It can be done. It shows how much energy was released when the top fell. 40.8 kgs of diesel oil.
Answers to all your questions are in my papers. Read them!
If I was Tony I would not become too involved in posting in the run up to the Hardfire debate. Anything that can be misconstrued and used against him will be. I would be preparing some 'surprises' if it was me because this show will be all about viewer perception. The debunkers may be concentrating more on making their opponents look like fools than anything else. Most viewers will likely not understand too much about the technicalities and will think that the side who appears most confident has won the debate. Thus a few 'surprises' up the sleeve could help to destabilise the debunkers and put the boot on the other foot.
I could be wrong about their approach but on he other hand forewarned is forearmed.
So we know that the upper part C in WTC1 was in an advanced state of disintegration by the time it impacted the top of the lower 90% of the building as seen in the earlier proof.
Moving down the building to the impact zone as promised check this video out.
http://www.youtube.com/watch?v=dtx_GcFCs6c&feature=channel_page Video analysis WTC1
Let the video get to 7 seconds and freeze it. Let it run to 8 secs and freeze momentarily. Then to 10 secs and freeze mementrily again. One more time to 12 secs and freeze. Click again and at 13 seconds watch as ALL the rubble across the whole width of the building starts to go down together. Up till then only the debris on the right - which is seen to behave something like a thick liquid- is streaming off the still more or less intact top of part A.
If he had cleanly admitted that the upper part was in an advanced state of disontegration we could have gotten to that yesterday .As it is now we will have to deal with that when we get to it.
That upper part, the collapsing floors, hits THE FLOOR IMMEDIATELY BELOW, NOT THE "REST OF THE BUILDING."
That upper part, the collapsing floors, hits THE FLOOR IMMEDIATELY BELOW, NOT THE "REST OF THE BUILDING."
Even a non-engineer like me can understand this.
From my paper:
When 33 000 tons of mass above in WTC1 falls down 3.7 metres due to gravity during and crushes all the columns abt 340 kWh (1.22 GNm) of potential, PE, or kinetic energy, KE, is produced by gravity force and a fair part of that energy is consumed to crush the columns. Let's assume that this event by gravity takes 5-6 seconds based on video clips (it should only take 0.8-0.9 seconds near free fall) and that there is a certain velocity when the upper part impinges the lower structure. In reverse - to first stop and second pull the upper block back up again you need a very big engine with power 204 000 kW that pulls up the mass above. Let's assume this engine is very effective and that you require 120 grams of diesel oil to produce 1 kWh. It means that 40 800 grams or 40.8 kgs of diesel oil is required to stop and pull the mass up again! It takes 6 seconds! It can be done. It shows how much energy was released when the top fell. 40.8 kgs of diesel oil.
Answers to all your questions are in my papers. Read them!
Sure thing, billy. And after you're done with your proof, you're going to put on your jammies & cape & fly into space to push aside the asteroid that is approaching the earth. And then have a nice evening with Lois Lane... Don't forget to wear your glasses so that she doesn't recognize you ...
Notice that when these clowns are asked to deal with the FACT that the collapsing floors crushed one floor at a time, they have absolutely nothing to say. Heiwa can't get away with chanting about his worthless paper, and Bill can't bray his usual off-the-wall idiocy.
There is no Big Part A, dolts. The floors were crushed in succession. A child could get the idea. Why can't you?

1st of all, I can't understand why an engineer wouldn't stick to basic units. You've got tons, kWh, meters, and kg. So the first thing I've done is convert to mks.
Using your numbers,
33,000 tons = 3x10^7 kg
340 kWh = 1.224x10^9 J
PE converted to KE=mgh=3x10^7 x 9.8 x 3.7= 1.0878x10^9 J
So already, your math is off.
Then you say this process takes 5-6 seconds, according to video analysis. Which 5-6 seconds of which video are you referring to?
Finally, you are presumably figuring out how much of the KE was dissipated into heat by calculating how much diesel fuel it would take to lift the mass back into place. Assuming this is a legitimate method (a point I'm far from willing to grant), where did you get the figure of 204,000 kW?
Maybe later if you are a good boy.
So we know that the upper part C in WTC1 was in an advanced state of disintegration by the time it impacted the top of the lower 90% of the building as seen in the earlier proof.
.There's also no crane in the world capable of lifting this amount of weight. There's also no plant capable of generating 204,000KW. The two nuclear reactors on a Nimitz class carrier can generate this much power, but just barely, they'd both have to be at almost 100% capacity.
Of course, Heiwa says it can be "done". Just not by anything ever created.
I sure can.
I claim that, dropped from the same height, a complex, 3 dimensional structure, like multiple stories of a building, (i.e., something that is not a solid block) will generate a HIGHER peak force in the components of whatever structure on which they fall AFTER the dropped parts have been broken up & compacted than they would generate in their original, "pre-broken" state. As compacted rubble, it will also deliver a higher pressure, resulting in a higher stress and more damage in the impacted part.
That's the bet.
Note: the argument that "the pressure & stress will be the same when the impacted part breaks" is not an out. This relates to the peak force & pressure that the two components are capable of delivering.
In the case of the towers, the above applies to the tower debris compacted into the mass at the bottom of the descending block (i.e., Part B as defined by Bazant), after the debris has been crushed down to, say, 10 - 20% of the components' original height.
Note also that I am specifically excluding the vertical columns (<10% of the debris by weight, according to Ulrich) from the second part (i.e., higher pressure) of this assertion. Due to their initially vertical position, they are quite effective as spears, delivering high pressures. But, in the case of the towers collapse, the assertion above stands for the 90+% of the rubble that is NOT the vertical columns. For the columns, the FORCE will be greater, per my assertion, but not the pressure.
Obviously this does not apply to any debris that is thrown clear of the towers' footprint.
And this effect is true regardless of impact velocity. That is, in the case of the towers, this effect does not leverage the increased velocity of descending upper mass.
And it does not depend on the fact that there is a bigger hammer (i.e., more debris & more weight) behind the debris as the tower descends.
Even tho both of the above conditions ALSO increase the force generated by any given block of debris as time goes by.
The simple matter is that you have been claiming all along that "once the upper structure gets turned into debris, then it cannot deliver a significant impact force to the lower mass. This is obviously true for any piece that gets thrown clear of the towers.
But for all the compacted debris that stays within the footprint of the towers, your assertion is false.
Would you care to make a wager.
We'll proceed like any published paper. I'll make my case. You get to make a rebuttal. I'll answer your rebuttal. We'll submit it to the judges.
The judges of the wager will be any of the mechanical engineers, structural engineers or physicists posting here. Excluding you & me.
The wager:
When you lose this wager (and you will), you will promise to answer ALL the questions that anyone puts to you for two weeks. Honestly & in detail. Without resorting to evasion OR "read my paper".
You know, you will be honor bound to behave for 14 FULL DAYS the way that all the Non-truthers behave every day...
What a risk...
Tom
1st of all, I can't understand why an engineer wouldn't stick to basic units. You've got tons, kWh, meters, and kg. So the first thing I've done is convert to mks.
Using your numbers,
33,000 tons = 3x10^7 kg
340 kWh = 1.224x10^9 J
PE converted to KE=mgh=3x10^7 x 9.8 x 3.7= 1.0878x10^9 J
So already, your math is off.
Then you say this process takes 5-6 seconds, according to video analysis. Which 5-6 seconds of which video are you referring to?
Finally, you are presumably figuring out how much of the KE was dissipated into heat by calculating how much diesel fuel it would take to lift the mass back into place. Assuming this is a legitimate method (a point I'm far from willing to grant), where did you get the figure of 204,000 kW?