Belz...
Fiend God
I'm so lost, here. Can anybody fill me in, seriously, or must I either give up or read 92 pages ?
(1) You agree that only a powered vehicle can make progress up the belt.
(2) The cart is a powered vehicle, that moves by power to the wheels. List the power source and draw the power flow for (a) a cart in the wind and (b) a cart on a belt
(3) It is not in principle possible for a belt to drive the wheels ( as in the unpowered car on the belt) unless the cart is between two masses, one acting on the wheels and one acting on the propeller, and having a relative velocity between those two masses.
(4) The power for the cart comes from the belt and is used to push against the air around the cart. Where does the power for the cart come from when it is outside?
(5) Connect the dots to (3) This should be saved until you correctly understand what is actually happening in #2, #3, and #4
(6) The cart is spinning its propellor and wheels, but not moving wrt to the air around it when it is at the same speed as the air around it.
(7) The spinning is due to the introduction of a third force (the air mass) that serves to keeps it in place on what little energy it can get from the belt if the energy is only enough to do so. If more energy is applied to the cart by increasing the relative speed difference between the two masses that the cart is transfering energy between, the cart moves forward wrt the air around it and either moves up the belt on the treadmill (see many videos) or moves faster than the wind when outside (see Jack Goodman's video). For the data gathered by testing the Goodman cart with a treadmill, see the article published (link provided if needed)
OK, think about this, humber:
I have a little car. It has elliptical wheels. It's sitting on the floor, at its lowest possible position (the contact point with the floor is at the end of the minor axis of each ellipse). I have a little motor connected to the axle, that will turn the axle. As it does so, and the wheels begin to rotate, the contact point of each wheel will move in front of its axle, due to the geometry of an ellipse.
I'm interested only in moving as far as a quarter-turn of the axle will take me. During that time, the contact patch of every wheel will be ahead of the axle. Can this car move?
For example your claim about reference frames. I already tried to explain that, you can look it up.
Give examples of opposites? Water is compressible (everything is actually compressible) but the change in density is usually so small so we can ignore it in many calculations. Air is compressible but the change in air density that happens in low speed aerodynamics is so small so the density change can be ignored in that application.
Take a look in any good aerodynamics book and you are going to find a lot about incompressible flows.
A propeller works because it speeds up some air and thus change the momentum of the air.
edit: I looked at some of your older posts. It would make a huge difference if you started to use the momentum in your explanations instead of the talk about change of mass which not make much sense, definitely is badly defined and not true by using some standard definitions. The change of mass times the velocity make sense for a rocket (because the you use up the mass of the fuel) but it doesn't make sense for propeller where new mass is entering the system the whole time and the mass in is equal to mass out at steady state (and we get a thrust force at steady state obviously).
Hey, my buddy Stan's square-wheeled bike! (Although I don't know why everybody keeps calling it a bicycle, since it's a tricycle.)
I'm not sure I understand. Are you suggesting that some part of the DDWFTTW could have an airspeed that is not waaaaay less than Mach 1?Yes. You will also find that most propeller thrust calculations that treat air as incompressible deal with speeds below Mach 1. That's fine, but I have made the claim that due to the tailwind and the extremely low speeds (compared to an airplane prop at cruising speed) this isn't necessarily a correct assumption. If I found reference to this would you agree?
And I clearly stated that using the cart as a reference frame was ridiculous. No one specied a co-ordinate system. That helps when picking an inertial refernce frame doesn't it? That's what I am familiar with. I've never in my life had someone say "Oh, you don't know inertial refernece frames blah blah blah" If I've made a mistake along the way, why not correct it? "No, not the cart wrt to the earth, the belt wrt the earth"
I'm not sure I understand. Are you suggesting that some part of the DDWFTTW could have an airspeed that is not waaaaay less than Mach 1?
"one bit must move faster than another bit" is the way I spoon-fed it it to Spork.
Of course the cart is not "a reference frame", but it can define one, or a set of them. It's a handy shorthand to talk about the "frame of reference of the cart": as long as people are clear about what reference frames are, there is no problem in doing this: the "frame of reference of the cart" defines any reference frame in which the cart remains stationary. For analysing the DDWFTTW cart, there are three sets of reference frames that are useful:
- The set of frames where the cart is stationary.
- The set of frames where the road is stationary.
- The set of frames where the air is stationary.
Hey, my buddy Stan's square-wheeled bike!
I was saying that perhaps treating the air as incompressible at standard atmospheric pressure and temperature and the relatively slow speed of the cart isn't the best way to do it.
Completely ludicrous, but admittedly not at all surprising coming from you.
I think that to even begin to thin about this canard, whether I should ask how the cart on the treadmill may deal with square wheels. Given that I said to John, that wheels need not be round, it seems odd to offer such an underwhelming example.OK, think about this, humber:
I have a little car. It has elliptical wheels. It's sitting on the floor, at its lowest possible position (the contact point with the floor is at the end of the minor axis of each ellipse). I have a little motor connected to the axle, that will turn the axle. As it does so, and the wheels begin to rotate, the contact point of each wheel will move in front of its axle, due to the geometry of an ellipse.
I'm interested only in moving as far as a quarter-turn of the axle will take me. During that time, the contact patch of every wheel will be ahead of the axle. Can this car move?
You are a glutton for punishment. The KE that you;
(1) Lost when running up the belt
(2) Avoided gaining by simply arriving at "beltspeed".
As you can see, there is no KE in the runner when stationary w.r.t the ground.
This is true of the cart. The model is built upon false premises.
Basically this started pretty much as a result of humber not understanding the idea of frame of reference equivalence. Since then he has been making one physics blunder after another along with more and more outrageous explanations and claims. Some of his claims are on the order of "a boat moving the speed of a current in a river will still have a bow wave".
You have not denied me one of the many claims that you say are physics blunders.

I think that to even begin to thin about this canard, whether I should ask how the cart on the treadmill may deal with square wheels. Given that I said to John, that wheels need not be round, it seems odd to offer such an underwhelming example.
Completely wrong analogy, as usual....
You have not denied me one of the many claims that you say are physics blunders.
Done a long time ago, and more than once, and much more.Thank you, humber, for taking time out from your very busy heckling schedule to respond. Let's have a look and see how you did on your summary, shall we?
(1) You agree that only a powered vehicle can make progress up the belt.
(2) The cart is a powered vehicle, that moves by power to the wheels. List the power source and draw the power flow for (a) a cart in the wind and (b) a cart on a belt
No, it is only necessary for that force to be equal to the frictional losses induced by the belt and internal mechanism. The cart does not move, so there is little work done.(3) It is not in principle possible for a belt to drive the wheels ( as in the unpowered car on the belt) unless the cart is between two masses, one acting on the wheels and one acting on the propeller, and having a relative velocity between those two masses.
It needs only a small amount of power, and that comes from the belt, but in the real world, from the propeller. They may not be casually transposed.(4) The power for the cart comes from the belt and is used to push against the air around the cart.
Where does the power for the cart come from when it is outside?
So you say.(5) Connect the dots to (3) This should be saved until you correctly understand what is actually happening in #2, #3, and #4
Also the case for still air. Only the name has been changed to "windspeed".(6) The cart is spinning its propellor and wheels, but not moving wrt to the air around it when it is at the same speed as the air around it.
Good luck to it, but it can't do that on the belt. The propellor simply cannot drive the wheel at an angular velocity such that the wheel rim moves faster than the belt. They are synchronised.(7) The spinning is due to the introduction of a third force (the air mass) that serves to keeps it in place on what little energy it can get from the belt if the energy is only enough to do so. If more energy is applied to the cart by increasing the relative speed difference between the two masses that the cart is transfering energy between, the cart moves forward wrt the air around it and either moves up the belt on the treadmill (see many videos) or moves faster than the wind when outside (see Jack Goodman's video). For the data gathered by testing the Goodman cart with a treadmill, see the article published (link provided if needed)
Please note the corrections and do some research on those items pertaining to your misconceptions (you are wasting a lot of valuable time with your excursions). You'll never progress unless you acknowledge your mistakes and take the time to understand why you are wrong.