You clearly make things up just for effect. I don't think humb would even say this to make fun of you.
Then tell him not to say it.
Of course, your entire claim of wind speed and the means by which things gets there, resulting in zero force, is based entirely upon the notion that the force derived from the wind, falls with the velocity of that object. If fact, a parachute has been given many times in support of that claim. The treadmill
disparately requires that this be limear with velocity. You do have a short memory.
I will get back to it, but it's more fun getting at you.
John, if we model the Earth as a true sphere we can think of it as an infinite number of infinitely thin shells. When we are outside the Earth we can model the whole thing as being the total mass of the shells at the very center. When we are inside the Earth something whacky happens... When you are inside a homogeneous spherical shell you feel no gravitational pull from that shell - no matter where in the shell you are.
Not for a body of any size. There is a gradient, a consequence of those "shells." This also applies for macroscopic objects is an electrical potential field. Same thing.
So, whatever your depth beneath the ground, you have to ignore the contribution of all of the shells whose radius is greater than your distance from the center of the Earth. As you get closer to the center there is therefore less Earth mass effectively acting on you. And this reduction in mass happens more rapidly (cubed law) than the increase in gravity due to your closer proximity to the center (squared law).
Gravity is not local to that extent. All that could possibly mean, it that the force upon the object is equal on each direction.
Also, what Sol said about gravity and acceleration is on the money (of course). Basically, you can consider yourself to be in an inertial frame if:
A) You're free-falling in a gravitational field (and therefore accelerating!) - in which case you will ignore the effect of gravity entirely.
Absurd. There is a distinction between gravitational force, and acceleration due to that force.
OR
B) if you are not accelerating - and then you must consider the force of gravity as an external force.
Oh goody, there's a choice.
No, you must wonder why you are not accelerating and then look for the culprit. Perhaps air resistance.
Gravity and acceleration are wierd that way. Of course as Sol points out, the only distinction that can be made between gravity and linear acceleration are the gradient effects (lines of gravity are not parallel, but converge toward a point - and gravity is stronger toward the source).
wierd* A standard scientific term.
No, I am afraid not. The Earth's gravitational field is not homogeneous. There is a gradient of course, because force is related to the square of the distance. For objects close to the surface, their altitude is likely to be small compared to the diameter of the Earth, so the change is small.
There are local differences and g varies across the planet. (Some weighing scales must be calibrated to account for this. It is not enough to use a known mass, because that is also effected.)
Seems much ado about nothing. If the gravitational force is uniform, then it will look like a constant force, and so accelerate the object accordingly.