No, let's not. However, today is "be conciliatory day", in my native villageBack to the kites for a moment: to help clarify whether there is an actual difference in the two scenarios that you proposed, let's extend the length of the kite string, raise the height of the kites as they are flying, and add a cloud layer between the kites and the ground. To observe and record the behavior of the kites, a helicopter with a camera crew is hovering nearby.
The first kite is launched into a 10 m/s wind and the holder of the string is standing on the ground and not moving. The kite goes up over the clouds. When the camera crew reports that they are in position and filming, the kite string is severed right next to the kite and the result is filmed.
The second kite is launched on a day with no wind and the holder of the string is standing on a very long treadmill moving at 10 m/s (or the holder is standing in the back of a truck that is driving along a road at 10 m/s, your choice). The kite goes up over the clouds. When the camera crew reports that they are in position and filming, the kite string is severed right next to the kite and the result is filmed.
Would there be any way that the film crew and/or anyone watching the videos afterward could tell the difference between the first kite and the second kite by what happened after the string was severed?
That's pretty close: at best, it will model what the cart does outside in a perfect wind. Fortunately, modeling what the cart does outside in a perfect wind (no gusts or direction changes) allows a much more precise way of comparing the cart's speed to the speed of the wind to determine if/when the cart matches the speed of the wind (which it sees as still air at that point). In both cases (outside case and treadmill case), the KE change in the air surrounding the cart is the same.Yes. Countless ways.
There are no helicopters in my drawings.Bonus question: before the kite string is severed, what is the air speed of the helicopter if it stays exactly in position wrt the kite in scenario#1 and in scenario #2? The same in both cases, different, or opposite?
That's how the cart is powered, by the change in KE of the air surrounding the cart. If you have been playing the many-leveled game that RP thinks you are, you should be able to say, "Well done, mender, my work here is finished". If you still insist that the cart would have to be magic to achieve DDWFTTW, well, I'm not sure that anything anyone can say will ever change your mind.
What say you, humber?
Null point. Way too many new variables and unnecessary complication. Keep it simple.
On the Treadmill.
Anubis drags the kite through the air by the string, otherwise there is no air motion over the kite at all.
Upon release, the kite will still be carried forward, but powered by the KE stored in its mass. During this time, the kite (or any other wind borne object) will decelerate, meaning that its average velocity is less than that of the belt during that period, finally terminating at zero (w.r.t the ground or windspeed w.r.t the belt) when all available KE is dissipated.
During this same period, Anubis has moved further to the left while the balloon is decelerating, lending the impression that the balloon is moving away from him, though it is still actually moving towards him.
This must be true, as the balloon's average velocity is less than that of the belt, yet not zero, or in the opposite direction.
When all KE is exhausted, the kite will fall to the belt, and remain a fixed distance from Anubis.
(1) Upon release, the treadmill (windspeed) observer sees the balloon move a little the left, then quickly drop.
(2) A ground observer sees the same.
(3) Belt observer sees the balloon still coming towards him, but slower, then drop.
Conclusion: Ground and windspeed observers are the same. The cart is motionless for both observers. A quorum that says it is not moving.
In Wind
If a stable kite is released in wind, it will be carried away for as long as the wind may drive it. It can fly away to be out of sight. Hence "lost kites".
The motion as the kite is released, is not apparent, but real and time continuous, and the same for all observers. Also, there is no motion towards the kite handler upon release.
As I have said, the only time the treadmill is even close to a model of the real wind, is if and only if, the object is fixed to the belt.
The cart is never seen to do this of course, but could not make progress up the belt if released. ( If the cart can spin-up to get to balance, then it may reach that state before becoming unstable, but that is not real progress up the belt)
The quotable humber:
If actually moving with the belt, (motion w.r.t the ground) the cart cannot move w.r.t the belt, so as to be seen making real displacement along that belt. That is impossible for any vehicle without energy storage, that is driven by the wheels.
So, Mender, what do you say?
ETA:
You Tube video delayed due to time, but definitely in production.