• Security incident: ISF was recently accessed by intruders. Please change your password, and change it anywhere else you used it. Read more

Split Thread The validity of classical physics (split from: DWFTTW)

Status
Not open for further replies.
greg:
humber:
The average human being can output about 0.1 horsepower continuous. 74 watts. Power = work done per second. Work = force * distance.
Yes, Greg, but not at all numerical values suggested by the product. There are limits to both maximum velocity and force. The HP is not an absolute value,

power = force * distance / time
Yes, power = force x velocity. Real machines have a power band, not a straight line on a plot of those values.

Say you put that into linear motion. A human being walking on level ground, pulling with some force on a rope. say he walks at 1 meters per second.
74 watts = force * 1 meter / 1 second
force = 74 newtons.
So, if our guy has the rope going to a simple pulley and a weight hanging on the other end, he could move about 7 kg vertically at 1 meter per second.
If he uses a 2-to-1 block and tackle, he could move 15 kg at about .5 m/s.
3-to-1 => 21kg at .3 m/s
4-to-1 => 30 kg at .25 m/s.
If the ratio of the block and tackle is reversed and is instead 1-to-2, then he could move 3.5 kg at 2 m/s.
1-to-3 => 2.5 kg at 3 m/s
1-to-4 => 1.8 kg at 4 m/s
At every stage, regardless of the ratio, the power from the human is 74 watts and the power being applied to the object being lifted is 74 watts.

I am sure your calculations are correct, but the premise is false.
Again. The limits of power transfer are not just technological. There are both practical and theoretical limits to power transfer and efficiency. They are permanent.

The yoyo takes the power from the wind, say its 74 watts, puts it through a transmission to gear it up, and allows the cart to go faster than the wind, as long as the force being exerted is reduced, so that the power remains the same.
No, the force against motion, is independent of the gearing itself, and you will not get to windspeed by direct means. There is an insurmountable barrier.
Why is direct windspeed not already commonplace?

Our human moved the rope 1 meter, and moved the object 2 meters. He did this by applying a 74 newton force on the rope, and this was able to move a 3.5 kg object at 2 m/s
The cart does exactly the same thing. THere is no magic increase of power. LIke a block and tackle the increase in speed is won by trading off and losing some of the force working on the cart.
No magic increase, just not all available. What you say could be true, but not on this planet. Second law of thermodynamics.
But it is not necessary to think about that. The losses in your cart as it travels, are simply there.

wait, what? If I have a windmill that generates a kilowatt of power in a 10 mph wind, I could put that same windmill indoors and mount it on a treadmill or moving track of some kind, and if I move that track at 10 mph, the windmill will generate a kilowatt of power.You don't agree?
It'll take power to move the treadmill or track, but the windmill generates the same amount of power in either situation, either outside in a 10 mph wind, or indoors on a track movign at 10 mph.
You could, but it would be less efficient. You need to build the generator to power the treadmill motor. So you need a 1kW wind-powered generator. There will be losses, both electrical and physical. The wind upon the generator, and the belt-wind upon that generator, and thermal losses of motors and generators. Sounds pointless to me.
This has nothing to do with frames, nor even their potential, but just a bizarrely constructed power system.
Surely you agree with that? Then why do you expect your chute and yo-yo to be 100% efficient? Efficiency is not measured by the % of the wind speed.

You need me to prove that?
I don't believe that I asked for that. I asked about the KE of the cart.
When something is actually moving with the belt, it is fixed to it, then that is different. Perhaps if you are overly-imaginative, then you could say it is in a frame, or if not, see it as an object driven by a belt through the air. I would get the same reading from your generator-on-a-belt, as you would.
 
Please start a donation drive to buy Humber a cart. I'd donate my treadmill but Christmas was "plentiful".

Conservation of momentum applies in closed systems. This is an open system.
While the mass is constant, there is an external force.

Hope this is helpful.
 
Clive, if you're point of reference is on the surface of a rotating cylinder, then your velocity is changing. Velocity is speed in a specific direction. Change the direction and you change the velocity.

You need more than one point to define the reference frame. By "Let's say I'm fixed to a rotating surface and my frame of reference is rotating with that plane. My velocity is zero, but I'm certainly not in an inertial frame.", Clive clearly meant that velocity is zero with respect to the frame in which no point on the plane is moving. There is nothing wrong with saying you have zero or constant velocity with respect to an accelerating reference frame.
 
Clive, if you're point of reference is on the surface of a rotating cylinder, then your velocity is changing. Velocity is speed in a specific direction. Change the direction and you change the velocity.
What frame of reference are you using to measure my velocity on the rotating surface? I specified that I was using a reference frame that is rotating with the surface. So, by definition my displacement from the origin is not changing, hence my velocity is zero (in that frame of reference). You seem to be trying to use two different frame of reference at the same time.

Let me try to be more specific. I am on a flat plane (not a cylinder). The plane is rotating (like a frisbee). I'm using a frame of reference with the traditional x/y/z cartesian coordinates to measure position and the x/y plane coincides with the surface I am standing on, and also rotates with it so that the z-axis coincides with the axis of rotation. I know this system must be rotating because I detect an apparent force ("centrifugal force") that can't be explained in terms of any of usual and accepted causes of "real forces" (such as gravity and so on). When I toss some object in some direction parallel to the x/y surface I observe that it moves in a curved path (again, relative to my chosen reference frame) rather than a straight line because of "coriolis force". In other words its velocity in my reference frame is not constant even though there is no net "real force" acting on it.

So, in my chosen frame of reference, I measure my velocity as being fixed (at zero meters per second in this case). Your earlier statement seems to imply that is enough for me to say I'm in an inertial reference frame.

The definition you gave in your PDF for an inertial frame of reference seems more accurate. From memory, I think it was something like "an inertial frame of reference is one where Newton's Laws are observed to be valid". There's clearly an circular aspect to this but as far as I can see you can't completely get around that. I've also read other explanations that say you can think of Newton's first law as effectively defining an inertial frame of reference, within which you can then expect the other two laws to hold.
 
Modified, I think I munged a sentence while editing it. change this:

"Inertial frames are nothing more than a frame of reference moving at a fixed velocity"

to

"Inertial frames are nothing more than a point in a frame of reference moving at a fixed velocity"

which still isn't good english because "moving at a fixed velocity" was supposed to be attached to "a point", not "frame of reference". i.e.

"Inertial frames are nothing more than a point moving at a fixed velocity in a frame of reference"

Ugh. never mind.

my point was more that kinetic energy has nothing to do with the cart, and I ended up not paying attention to how sloppy I was getting.
 
The kinetic energy is irrelevant. the only thing that matters is the resistance from friction on teh cart, its wheels, axles, bearings, and from the wind. This is some force measured in newtons. You could measure it by simply dragging a cart around (take the prop off so it doesn't push the cart forward) and measuring the tension it takes to pull the cart at a certain speed.
Then you are simply measuring another machine. But that is not the point.
To be at windspeed, the cart must have the KE of the vehicle at that speed. That is said to be relative to the belt. I say that is not true. It has zero KE, because it is not moving. I do not care if there is KE relative to the Sun or whatever, because that also applies to a cart 30cm away, but on the floor.

(1) If you take the prop off, you have eliminated its drag!
(2) The force you measure will perhaps a small rolling resistance.
(3) When driven by the wind, the wheels drive the cart, so the friction will be higher, so your readings will be way too low. Gear losses are ignored..
(4) You have a power demand (velocity x force) but way too low, and you have assumed the friction is the entire drag loss, and that to be linear and coulombic.
There are a few more...

Say its. a newton at 12 meters per second. That's probably too high, but its easy to work with. and if you want an exact number, you can measure soem specific cart.
Good idea.

So, the only thign that matters is that you need to exert a newton of force to keep the cart moving at 12 m/s.
Say the wind is moving at 10 m/s relative to the ground. The cart is moving at 12 m/s relative to the ground, so the cart has a 2 m/s relative wind that it can convert into 1 newton of force.
It just arrives at 12m/S? Make it 40m/S

So, all you need to do is select a prop big enough that a 2 m/s wind can create 1 newton of force at 12 m/s.

1 newton at 12 m/s is 12 watts. So, you would need a prop big enough to extract 12 watts of power from a 2 mph wind. That's it.
Find that prop.

The kinetic energy of the cart is irrelavent. ALl you need to do is figure out the force needed to overcome the friction in the cart at the speed you want, and that gives you the power the prop needs to pull out of the wind. That's it. KE is irrelvant.
To get to any speed, you need to accelerate. That means gaining KE. It also means that if you have no KE, then you have not been accelerated.
It does not matter as to where else you have KE, because if it is not zero, w.r.t the ground, it will already be traveling.
So, to take an object that is currently stationary w.r.t the ground, to a velocity w.r.t that ground, requires (additional) KE relative to that ground. That must apply w.r.t the belt.
(1) I will be zero w.r.t the belt.
(2) It will be zero w.r.t the ground.
(ignoring the tiny motion)

There is no wind on the treadmill. If I want to speculate on the cart, and its ability in wind, then I will use Drela''s paper. It is a more elaborate version of what you have just done.

KE is 0.5 * mass * velocity^2, and it doesn't matter how much teh cart weighs. If it weighs a thousand pounds, but somehow manages to only require 1 newton of force to move it at 12 m/s, then it needs the same size prop as above.

No, the KE given by that equation. Small force is longer time accelerating to that same KE.
 
Please start a donation drive to buy Humber a cart. I'd donate my treadmill but Christmas was "plentiful".

Conservation of momentum applies in closed systems. This is an open system.
While the mass is constant, there is an external force.

Hope this is helpful.

It is closed for all the purposes of measurement. Why not?
 
Last edited:
The wind propels the parachute, but the parachute moves though the air, and must overcome drag. It is therefore a case of diminishing returns. From the perspective of the observer in the seat, the yoyo has zero KE, and therefore cannot move. If you put the yoyo on a treadmill, the parachute will have no KE, and the boundary layer will be flowing in the wrong direction. It will remain in place by a simple force balance. It cannot do so on the road, because the friction is insufficient for it to hover.

You're getting disturbingly good at this Humb.
 
And the cart extracts power from the difference between teh air and ground, like a windmill on a treadmill.

The windmill only generates power when moving relative to the air. That is also relative to the ground.
The cart only sees wind when moving back with the belt and so the same relative to the ground.
(1) Tell me when you see that in the videos.
(2) There is no motion with the belt at windspeed, so no wind, and so no power.
(3) The KE is at a maximum when going back with the belt, to be zero at windspeed, from belt or ground.
 
This stuff is not really correct Greg. If an inertial frame is "nothing more than a frame of reference moving at a fixed velocity", then what frame are you using to measure that velocity against. Can it be any old frame? I think not! And "if you're moving at a fixed velocity, you're in an inertial frame and that's all there is to it" is also incorrect. Let's say I'm fixed to a rotating surface and my frame of reference is rotating with that plane. My velocity is zero, but I'm certainly not in an inertial frame.

An inertial frame of reference by definition is not accelerating, so it cannot be rotating.

As a side note I am now offering insurance against 0 KE collisions ala humber combine with an antidefragmentation device for hang gliders:D Handy dandy little paddle device that somehow tells if you are in a real wind or not extra.
 
All quantities are near zero too. KE, velocity, acceleration, displacement, work.
No.

You have zero KE when in your chair, too.
Depends on who you ask.

Math as obfuscation is not the same as math as education, H'ethetheth
OK, please post your analysis of the treadmill. I will address it then.
Math cannot repair a false model, but if you insist.
That's why I asked for assumptions too.

Please explain why it is said, and how it is like the fish tank you said was equivalent. You argued for the belt as evidence of motion. I say it is not needed, so you have now contradicted yourself. All relative quantities are not preserved on the treadmill.
Which interactions are not preserved, humber? Name them.

Please explain how the system can be said to be isolated from the ground ( eg treadmill side) when the system that provides the energy (the motor) is common to ground. The KE of the cart would be from this source, and so measurable from the same ground. To deny that would be to deny the conservation of energy between frames. The KE should therefore appear to all observers.
First of all, KE never appears to all observers.
Secondly, it is not relevant what powers the interaction between air and ground. The interaction is defined only by a difference in velocity.

I say there is a palpable difference between those making motion over the ground, and those buried in it.
Yes. Quite beside the point, however.

They perhaps both experience that same remote force, so that can be ignored as a common factor. How many times are you going to exhume pre-modern ideas? It seems to me that absolutism must be raised so that it can be shot down with what is obvious. Motion is relative. A big discovery apparently missed by all wind-tunnel engineers.
Staggering. Who is raising absolutism here? You can imply that you understand that motion is relative, but this does little to change that most things you say show that you do not.

Have you considered that you may be wrong, H'ethetheth? Your support and replies seem weak and selective.
Yes, for a few seconds, as I was figuring out what to make of spork's demonstration.

Like the cart, the fish has no KE. You agree.
No. Who are you asking?

Yet another false analogy. The runner does the work of moving the limbs and generating muscle force. The object is cardio-muscular exercise, not to emulate motion. The belt passes under the runner's feet, to accommodate human ambulation. ( Essentially we walk by a sequence of free-falls and re-stabilization). This is a fact.
If you like, I could point you to some papers where the researchers did emulate motion with a treadmill. See for instance here:

You agree. The belt is not necessary, so there can be no frame for the said observer, but wind is, and some of the conditions of travel can be emulated by the motion of a medium. One is enough, and for F1 cars and wind carts, it is the wind. This is contrary to your earlier statement that the wind was not necessary because of the belt. This is essentially the claim of the treadmill. How do you reconcile the lack of wind on the treadmill?
I agree if all interactions are preserved. That is, the wheels should experience a force like that while running over a road, and the air should behave as if it's moving over a road. This can in principle be contrived without a road, or a treadmill, but it is ludicrously difficult, and will never produce better results than a treadmill. So why bother?

No, it is not. They are quite different. The force of the real wind is not self limiting in this way. That is demonstrable. The real wind is not limited by the object that is blown by it. This is not a small difference, but one that the treadmill depends upon. I see no refutation of the self-regulatory mechansim I described. This is a critical difference, that demands more of an answer than the repetition that all is relative.
How is it different? Be specific. Are the propeller blades experiencing different angles of attack? Is the force exerted by the air on the road different? Is the force exerted on the tires by the road different? Name it, and quantify it.

The force of the wind itself does not depend upon gravity, whereas on the treadmill it does.
Wrong. In both cases the force of the wind has nothing to do with gravity. Only the force on the tires depends on gravity.

It is not possible for the force of the wind upon the cart to exceed the demand (load) presented by the cart. One is a reaction to the other. That is not like real wind.
Of course it is, because a gust of wind means an increase in the speed between air and surface. The treadmill equivalent is therefore an increase in treadmill speed.

The real cart's dynamics depend upon the friction to the road, and the dynamic response of the system to perturbation. Without the correct level of KE, or real wind to account for that influence, the dynamics are false. This is why F1 use wind, and you agree that is necessary.
Yes, because 300 kph tailwinds are rare. It is unlikely that Ferrari will want to model this.

No, my analysis stands. The trolley model is equivalent.
What? I agree that it is equivalent. Now tell me how a trolley in still air differs from a treadmill.

This suggests that all KE is that of the observer, and there is none in the cart. No measurement can demonstrate KE for the cart, and that is flat.
This doesn't mean anything. For all observers that report zero KE for the cart, there is an infinite number of observers that will report that the cart is moving. Motion is relative!!! KE depends only on motion, and is therefore also relative! You can keep repeating that I don't know what relative motion means, but it weakens your credibility a bit if you keep saying things like this.

Similarly, to make progress down the belt, the axle must also move w.r.t the belt. When pushed to be seen as going backwards, the wheels should rotate in the opposite direction, but clearly they do not. The wheels spin much as before, in direct opposition to the normal motion of the belt. Motion of a wheeled vehicle in either direction along the belt is NOT possible unless there is contact patch forward of, or to the rear of the axle. On the belt, this contact point is directly in line with the axle because of the fixed relation of belt and wheel. No motion as found on the road, is possible.
I'm sorry, this is gibberish. Give me some numbers, will you?

I believe no such thing, and you know it, whereas you are denying that it can be. It is the equal of all others, and I need not be biased or absolutist to use it. This you also know.
I believe you when you say this. You clearly believe that you don't believe that there is a preferential frame. The thing is, you keep implying there is one. If you wonder where you implied this, go back and find every time someone said to you that motion is relative.

You may believe reiteration to be refutation. In any case, I do not need to assume that the ground is absolute to find fault. I have my trolley equivalent, that allows me to make all claims from that, so the absolutist lament is no longer going to work.
There are enough errors without resort to that claim. anyway.
I'm very happy about your trolley, I honestly am. However, I'm very curious as to the differences between a trolly moving through still air and a conveyor belt moving through still air.

Also in the real world, there are no known examples of objects traveling w.r.t the ground that do not have KE, w.r.t the ground. The treadmill flatly contradicts nature and that is the reference.
The cart has no KE w.r.t. the belt's surface? Tell me, what is the speed of the belt's surface relative to the cart? Oh, that's right, not zero. What does that tell you about the Kinetic energy?

Put that first point to Steven Hawking. I imagine he can know nothing about anything to do with motion.

No, H'ethetheth. That is not the case. Is there anything that I have written in this post alone that does not fully indicate that I understand that? It is the most basic of ideas. What is there not to understand? I think that I can safely say that I understand that, and its consequences better than you.
Ah, a challenge!

All quantities are near zero too. KE, velocity, acceleration, displacement, work.
You have zero KE when in your chair, too.
All relative quantities are not preserved on the treadmill.
The KE should therefore appear to all observers.
Like the cart, the fish has no KE.
The object is cardio-muscular exercise, not to emulate motion. The belt passes under the runner's feet, to accommodate human ambulation.
The belt is not necessary, so there can be no frame for the said observer, but wind is, and some of the conditions of travel can be emulated by the motion of a medium. One is enough, and for F1 cars and wind carts, it is the wind. This is contrary to your earlier statement that the wind was not necessary because of the belt. This is essentially the claim of the treadmill. How do you reconcile the lack of wind on the treadmill?
The force of the real wind is not self limiting in this way. That is demonstrable. The real wind is not limited by the object that is blown by it. This is not a small difference, but one that the treadmill depends upon.
It is not possible for the force of the wind upon the cart to exceed the demand (load) presented by the cart. One is a reaction to the other. That is not like real wind.
The latter appears in all frames, meaning that it is displacement and not velocity increase. It has essentially no motion.
If an observer stands on the belt, he will move relative to the cart, but that is because he is being accelerated by the trolley, but the cart is not.
Though this one is getting close to being correct. Perhaps a short hint about observers: they're not usually thought of as being massive. They don't do kinetic energy; they represent a vantage point, no more.

Moving on:
No measurement can demonstrate KE for the cart, and that is flat.
Similarly, to make progress down the belt, the axle must also move w.r.t the belt. When pushed to be seen as going backwards, the wheels should rotate in the opposite direction, but clearly they do not.
A runner's treadmill is not the treadmill, nor your fish tank. There is work done, but no linear motion.
"Velocity is relative" is only one aspect of the fact that "All motion is relative".

There, 15 things that you could not possibly have said if you understood that motion is relative.
And I've left out the instances where you flatly stated that the treadmill is not equivalent to a road in wind, because that is the matter at hand. It would be silly to count those.

But, there is light at the end of the tunnel. I can honestly say that I am glad we agree on this:
The trolley model is equivalent. I can easily do more measurements than on the current treadmill. The cart will remain essentially stationary w.r.t the ground. The trolley will pass under the cart so to speak, as its wheels turn.
 
To get to any speed, you need to accelerate. That means gaining KE. It also means that if you have no KE, then you have not been accelerated.

and the prop/wheel or chute/yoyowheel extract energy from the air/ground difference and translate it into a force to accelerate the cart, adding KE to the cart.

At some point, the energy being extracted from the air/ground is equal to the energy being lost to friction and you reach steady state. But nowhere does it say that steady state must be less than the speed of the wind.

If I have a prop/wheel that extracts 1 watt of power from the air/ground, I have 1 watt to work with however I want and the only limit on how fast I go is the friction of the cart, not the windspeed.

I pull on a rope at 1 m/s. Is there any intrinsic limit to how fast I can lift an object attached to a block and tackle connected to that rope? Can I say that if I pull the rope at 1 m/s, the fastest any block and tackle can move an object is 10 m/s? No. The limit is only a function of how much power is absorbed by friction. as long as I can put more power in than friction uses, I can keep going faster.

You're acting as if the windspeed is some inherent limit to power multiplication. it isn't. THe cart extracts power from the difference between the wind and the ground, and that difference is ALWAYS THE SAME NO MATTER THE VELOCITY OF THE CART.

Read that again. The POWER IS ALWAYS THE SAME, no matter how fast the cart is moving. As the cart speeds up, the wind it feels slows down, but the ground speeds up an equal amount. so the difference between air and ground remains the same, so the power the cart has to work with remains the same.

Say the cart can extract 1 watt from a 10 mph wind. It can extract 1 watt no matter how fast the cart is moving.

So what limits the speed of teh cart? Not teh speed of teh wind, because the power is the same no matter the speed. What limits the cart speed is when the power being extracted finally matches the power dissappated by friction.

And if you design your cart well enough, that friction can be low enough that a tiny prop/cart can push it faster than the wind.

If the wind is too slow, the cart can't extract enough power to make it move. The wind has to be moving above some minimum. Above that minimum, the cart can extract enough power to move itself. Any power left over after friction is used to accelerate the cart.

Friction, on the other hand, keeps going up as velocity increases. (I think its a linear funciton of velocity, if I remmber.) So as the cart goes faster, the friction increases. At some point, the power from the prop/wheel equals the power disappated by friction, and the cart stops accelerating.

That may or may not be below the speed of teh wind. If your cart has low enough friction, it may be able to go faster than the wind. If you're cart is poorly designed, it may not be able to go faster than the wind. and if it's really bad, (maybe the prop is simply way too small), it wont be able to move at all for any reasonable windspeed.

The point is that the power available to the cart is a function of the difference between teh wind speed and ground. You can then use that power to move the cart. As you move the cart, the difference between air and ground remain teh same, so the power available remaisn the same. What stops the cart from accelerating is that friction increases linearly with velocity, and at some point the power from the air/ground equals the power burned up by friction, and you stop accelarting.

And that steady state condition may be faster than the speed of teh wind.

There is no magical power generation going on. Yes, the kinetic energy of the cart increases. And it does so because the cart is extracting energy from the air/ground difference. And it will keep doing so until the power from the prop/wheel or chute/wheel is equal to the power dissappated from friction. And nothing requires this to be below the speed of teh wind.

I can pedal my bike with my feet moving at 3 mph and move my bike at 10 mph. There is no velocity limit that is strictly a function of velocity. The velocity limit of a man pedaling a bike is a function of the power the man can put into the pedals and the friction of the bike and wind.


No, the KE given by that equation. Small force is longer time accelerating to that same KE.

So what if it takes longer to get there, it will still get there. And "there" may be faster than the wind.
 
(1) If you take the prop off, you have eliminated its drag!
Y'know, props are funny. What's the drag (in the forward direction) of a spinning prop? That is, how much harder is it to pull a cart forward if it has a spinning prop on it, compared to having no prop at all (or a spinning stick, or a rag, or whatever)? It's weird, you don't have to pull harder on the cart when you add a spinning prop. In fact, you have to restrain it from moving forward. What a strange thing, it seems to have negative drag, at least over some limited speed range. So how is it that removing the prop eliminates the drag of the cart?
 
Y'know, props are funny. What's the drag (in the forward direction) of a spinning prop? That is, how much harder is it to pull a cart forward if it has a spinning prop on it, compared to having no prop at all (or a spinning stick, or a rag, or whatever)? It's weird, you don't have to pull harder on the cart when you add a spinning prop. In fact, you have to restrain it from moving forward. What a strange thing, it seems to have negative drag, at least over some limited speed range. So how is it that removing the prop eliminates the drag of the cart?
Negative drag you say? By God, I think I'm having an idea!
 
Last edited:
greg:
And the cart extracts power from the difference between teh air and ground, like a windmill on a treadmill.

humber:
The windmill only generates power when moving relative to the air. That is also relative to the ground. The cart only sees wind when moving back with the belt and so the same relative to the ground.

This right here is the problem in a nutshell. The cart generates power based on teh difference between wind and ground. That difference is always the same, no matter how fast the cart is going.

If the cart only generated power based on teh wind, like it used a simple sail and the wheels were freely rolling, then you'd be correct: It would only extract power as long as it was going slower than teh wind.

But the cart doesn't work that way. It extracts power based on teh difference between air and ground and that difference is always the same. So the power available is independent of teh cart velocity.

As long as you think the power is a function of teh wind only, rather than a function of the difference between wind and ground, you will struggle with this.
 
Last edited:

100% Evasion. .

You have not manged to demonstrate how your fisg tank is like the treadmill.
you saud you could.
(1) You claim 15 mistakes in my understanding of relative motion. Please justify one of them where your conclusion contradicts mine.
(2) Why a human runner on a belt is like a cart.
(3) You also failed to address the matter of how wind and a belt are needed to generate the correct boundary layer.
 
Part of the fun here is in watching humber, and part of it is in watching newcomers to this discussion who naively think that they can talk some sense into him. I've been there myself, and we seem to have an ample supply of people who have not yet learned that he's hopeless, and that the real sport is not to try and educate him, but rather to bait him into saying ever more preposterous things.

And part of the fun, of course, is humb. I think he's really probably Homsar.
 
Status
Not open for further replies.

ISF - Join now!

Every member here is approved by hand. No bots, no spam, just people who care about evidence and honest debate.

Membership is free!

Create your free account

Back
Top Bottom