Do you realize that is 4,940 F?
4,040 F? Why would you think the temps were this high?
2,240 F, again how do you get this temperature?
I posted about it earlier. The formula to calculate the total energy emitted by an object due to its temperature is:
W/A = e * o * T^4
Where
W is the work
A is surface area
e is the emissivity factor (Steel is around 0.5 depending on composition, aluminium is 0.1)
o is the Boltzmann constant, and
T is the temperature in kelvin.
Read more about it at the
Wikipedia Article on the Boltzmann Law.
This is the total amount of work released by a surface's temperature, as such it is a relatively accurate representation of an item's "brightness"
However if you want to calculate the actual color by yourself, it gets a whole lot more complicated - which is why you'd use a simple blackbody spectrum cheat sheet.
What I ended up with is that iron would emit about as much energy at 1600K as aluminium would at 2500K.
but it'd also have a different color (much whiter, less yellow) and it wouldn't become orange as quickly as the observed object - in fact, at 'orange' temperatures, aluminium probably wouldn't even be noticeable at this distance.
Oh, and about the 3000K figure - I simply figured the flame would have to be at least a good 500K hotter than whatever you're trying to heat to 2500K to make it happen with some speed.
P.S. Are you telling me you've been arguing about the whole thermate story without understanding how blackbody radiation works? I guess, only someone not familiar with the basics of blackbody radiation would!