joobz
Tergiversator
- Joined
- Aug 31, 2006
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Here's Dr. Kleinman, M.D. Ph.D. and master of mathematics more advanced than anything Dr. Schneider has done, lecturing me on probability theory:
(emphasis addedd)kleinman said:Perhaps it would be helpful to review the theorems of probabilities in question. The following is the multiplicative rule.
• If E are independent events in a sample space S and the probabilities of events E are not equal to zero, then the total probability of events E occurring is the product of their individual probabilities.
• PTotal= (E)^n where E is the event and n is the number of independent events.
The addition rule for mutually exclusive events in a sample space S states that the probability of that event occurring is the sum of individual probabilities of each of the exclusive events.
If we apply these rules to the mutation and population case, the mutation is the event “E” and the population is the sample space. The probability of the event “E” must be 0>=P(E)>=1. You are confusing the probability of a particular event occurring which must have a value between 0 and 1 with probability that a particular event may occur by a series of mutually exclusive events which can have probabilities greater than 1.
The probability of throwing a 1 in either of two rolls of a die is 1/6 + 1/6 = 1/3. The probability of throwing two 1’s in two rolls of a die is (1/6)*(1/6) = 1/36. Random mutations are mutually exclusive events. The probability of having a particular mutation at a particular locus in two creatures is 1/G + 1/G = 2/G. The probability of having the same mutation in two creatures is (1/G)* (1/G) = (1/G^2)myriad said:An example of the correct use of the additive rule is: the probability of rolling any specific number on a die is 1/6. Therefore the probability of rolling a number that's 4 or less -- that is, rolling a 1, rolling a 2, rolling a 3, or rolling a 4 -- is 1/6+1/6+1/6+1/6 = 2/3. It works correctly in this case because on a single die, rolling a 1 is obviously mutually exclusive with rolling a 2, rolling a 3, etc.
If I believed that Kleinman could possibly be telling the truth about being licensed to practice engineering or medicine, I'd be frightened to enter a doctor's office or cross a bridge.
Respectfully,
Myriad
Yes, the world that kleinman lives in uses some very strange rules.
BTW, kleinman, in case you were wondering. In our world, the odds of rolling a 1 in a number of throws is equal to 1 minus the odds of not rolling a one in either throw. (1-(5/6)^n) n=number of throws.
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