Ziggurat
Penultimate Amazing
- Joined
- Jun 19, 2003
- Messages
- 61,829
It does exactly that.
If every place in GR where there is a "c" gets replaced by "c - H * D", and H * D = 0 everywhere its been tested (Mercury's orbit is not affected by the Hubble flow), then everything still works.
This doesn't actually even make sense. There are a lot of equations for which there is no obvious choice of what D should be. What do you do in those cases?
All physics where an object in motion continues at its current rate to infinity.
My theory breaks inertia fundamentally, and thus anything on it, when we're talking about hundreds of millions of light years.
You clearly don't understand Noether's theorem. You CANNOT break momentum conservation without also breaking translation symmetry. There is no rule that says translation symmetry cannot be broken, but you can't keep it and break momentum conservation at the same time. No theory can. If you think your theory does, then either you don't understand your own theory, or your theory isn't even self-consistent.
I don't know much about black body's, but is the CMB an absolutely perfect black body?
It is perfect within our measurement ability, which is considerable. It is never possible to show that deviations are identically zero, since no measurement process has zero margin of error.
Well, this says there are black body stars:
https://aasnova.org/2018/10/31/perfect-blackbodies-in-the-sky/
https://iopscience.iop.org/article/10.3847/1538-3881/aac88b
They aren't. They're much closer to ideal black body radiators than most starts, but the deviation is still observable.
I think so.
The black body spectrum refers to receiving photons from all parts of the continuous spectrum in quantities that form a smooth curve.
Right?
Wrong. A black body is a body that absorbs all light that touches it, regardless of the spectrum of that light. Light that is incident upon a black body need not have a smooth curve.
It's the light produced by the black body which will be smooth.
But that would imply to me, the CMB isn't one black body, but many black bodies and they are around 2.8K but not exactly. And there are fewer of them in the direction of the cold spot.
No. There aren't fewer of them. If you just have less emitters but those emitters are at the same temperature, then the spectrum will have a peak in the same place but just a lower intensity. That isn't what's observed. Which brings up an important point that I think you may be missing. It isn't that we see a spectrum indicating that something far away is a black body. We see a spectrum that indicates that EVERYTHING far away is a black body.