halleyscomet
Penultimate Amazing
- Joined
- Dec 7, 2012
- Messages
- 10,259
I am developing a theory that there are more pink unicorns than blue ones. I’m finding Jabba’s argument style and mathematics are a perfect fit for advancing the claim. I am confident that I can reappropriate his tactics to argue my thesis even more convincingly that Jabba has argued his.
- IOW, I'm trying to re-evaluate the hypothesis that selves are mortal (H).
- Does anyone here accept the formula I'm using in trying to re-evaluate the probability of that hypothesis -- given my current existence?
- That formula is P(H|E)=P(E|H)P(H)/((P(E|H)P(H))+P(E|~H)P(~H)).
Now, let's apply that to unicorn color statistics.
The existence of unicorns is, like the soul in Jabba's use of this equation, a given. I'm not going to mince words with y'all, but the Bible is VERY clear on both points. Here are some citations regarding unicorns:
https://www.biblegateway.com/quicksearch/?quicksearch=unicorn&qs_version=KJV
Back to the equation:
k = all background knowledge,
P = the probability of,
NR = Non-Religious hypothesis,
| = given,
me = me (my existence),
R = Religious hypothesis.
The formula for this probability is
P(NR|me & k) = P(me|NR)P(NR|k) / (P(me|NR)P(NR|k) + P(me|R)P(R|k)).
Since we are adapting the equation for unicorn color analysis we can alter the key variables as follows:
k = all theoretical unicorn colors
NR = Pink Hypothesis
R = Blue Hypothesis
We will then relabel k as Color, NR as Pink and R as Blue.
The "me" from the equation that was used to refer to Jabba can be canceled out as an irrelevant flourish that adds unnecessary complication to the equation.
This gives us:
P(Pink|Color) =
P(Pink)P(Pink|Color) /
(P(Pink)P(Pink|Color) + P(Blue)P(Blue|Color))
The equation contains a few open intervals:
https://www.rapidtables.com/math/symbols/Basic_Math_Symbols.html#basic
(a,b) open interval (a,b) = {x | a < x < b}
This is silly, as there is no condition for which we are contemplating infinite unicorns of any color, unless one wants to invoke a multiverse in the analysis, which is just plain silly in this context. This allows us to further simplify the equation:
P(Pink / Color) =
P(Pink)P(Pink / Color) /
(P(Pink)P(Pink / Color) + P(Blue)P(Blue / Color))
Why am I converting open intervals into division? Because we want the percentages and not the open intervals of course! (What? If Jabba can ignore what actual statisticians say about how to do it, so can I.)
Have at it and plug in some numbers! You'll find that in every conceivable outcome the ONLY way for blue unicorns to outnumber pink ones is for the number of blue unicorns out outnumber ALL unicorns!
Don't like it? Then you're just in denial: