JayUtah
Penultimate Amazing
Actually, I think that my prior probability of ~H (1%) accounts for that.
Why would you think that? Your wonky pseudo-Bayesian nonsense has nothing to do with the problem I laid out.
Let a be a non-negative real number such that 0 ≤ a ≤ 1. Find b, 0 ≤ b ≤ 1, such that a ⋅ b > a.
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