doronshadmi
Penultimate Amazing
- Joined
- Mar 15, 2008
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If Ψ is a formula and x is a set, then ∃x Ψ is a formula.
EDIT:
∃x is the formula "There exits set x"
Ψ is the formula "such that it is empty"
If Ψ is ""such that it is empty AND non-empty" , it does not have any impact on ∃x since x existence is a tautology (x exists even if some property of it is not clearly defined).
Another example:
∃x is the formula "There exits car x"
Ψ is the formula "such that it is all-blue"
If Ψ is "such that it is all-blue AND not all-blue" , it does not have any impact on ∃x since x existence is a tautology (x exists even if some property of it is not clearly defined).
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Let's return to ZFC.
Within ZFC members do not have tautological existence, because at least one set has no members at all.
This is not the case about set's existence within ZFC (a set has a tautological existence within ZFC, no matter if it does not have any member, its members are not clearly defined (and within ZFC it is the same as no members at all), or it has members).
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