Calculate an Earth impact

[DangerousBeliefs]

Fun little site to help you plan the end of the world...

http://www.lpl.arizona.edu/impacteffects/

I did a calculation on a 150 ft wide asteroid impacting 15 miles away...

Final Crater Diameter: 2.57 km = 1.60 miles
Visible fireball radius: 0.8 km = 0.5 miles
Richter Scale Magnitude: 5.4
The air blast will arrive at approximately 80.5 seconds.
Max wind velocity: 29.6 m/s = 66.1 mph
Sound Intensity: 83 dB (Loud as heavy traffic)

Try one the size of Texas!

 

[Dymanic]

Yeah,I played with that too. It's fun, but what it really needs is some cool graphics.

 

[Yahweh]

Cool!

<blockquote>Your Inputs:
Distance from Impact: 0.16 km = 0.10 miles
Projectile Diameter: 804670.00 m = 2639317.60 ft = 499.70 miles
Projectile Density: 8000 kg/m³
Impact Velocity: 161.00 km/s = 99.98 miles/s

Impact Angle: 90 degrees
Target Density: 1500 kg/m³
Target Type: Competent Rock or saturated soil

Energy:
2.83 x 10³¹ Joules = 6.76 x 10¹⁵ MegaTons TNT
The average interval between impacts of this size somewhere on Earth is 1.7 x 10¹⁴years

Crater Size:
What does this mean?
Transient Crater Diameter:
9696.15 km = 6021.31 miles
Final Crater Diameter:
32164.28 km = 19974.02 miles The crater formed is a complex crater.

Ejecta:
What does this mean?
Your position was inside the transient crater and ejected upon impact</blockquote>
Perhaps I should have chosen more "realistic" parameters... oh well, good to know I'll be ejected upon impact...

 

[Hellbound]

Just for fun, figure a 100m diameter iron object impacting at 50% the speed of light.

This is why any sufficiently advanced technology is an immediate threat to any single planet civillization in their corner of a galaxy. It's called "R-bombing", for relativistic bombing, and the A-bomb is a pop gun next to this. The worst part is, because of the speed, it's never in the place you see it or detect it on radar. In the time it takes the signal to reach you, the thing has moved. Makes em hard to stop or divert.

Anyway, just something to keep you all up at night

 

[Archangel]

Just for fun, figure a 100m diameter iron object impacting at 50% the speed of light.

This is why any sufficiently advanced technology is an immediate threat to any single planet civillization in their corner of a galaxy. It's called "R-bombing", for relativistic bombing, and the A-bomb is a pop gun next to this. The worst part is, because of the speed, it's never in the place you see it or detect it on radar. In the time it takes the signal to reach you, the thing has moved. Makes em hard to stop or divert.

Anyway, just something to keep you all up at night

You might enjoy a series called "The Heritage Trilogy" (Starts with Semper Mars).

In the second book (Luna Marine) the UN decide to send an asteroid to wipe out the USA.

 

[Yahweh]

I keep trying to set my distance away from the impact site equal to the radius of the crater, it keeps telling me my distance from the impact site cannot be more than half the circumference of the Earth...

 

[jj]

Well, in the old Lensman series, there was the time that they dropped an antimatter planet into another planet at 'C'.

Would that be bad?

 

[Hellbound]

Well, in the old Lensman series, there was the time that they dropped an antimatter planet into another planet at 'C'.

Would that be bad?

Actually, at that speed, it really wouldn't make a difference; matter, anti-matter, due to the speed of impact you'll get an almost complete matter-to-energy conversion anyway.

In either case, I just have one thing to say about it...when's that ship to Mars leaving?

 

[jj]

Actually, at that speed, it really wouldn't make a difference; matter, anti-matter, due to the speed of impact you'll get an almost complete matter-to-energy conversion anyway.

In either case, I just have one thing to say about it...when's that ship to Mars leaving?

Would Mars be even remotely far enough?

 

[Cecil]

Would Mars be even remotely far enough?

Short answer, no.

Long answer, well...

An anti-Earth colliding with our planet, assuming total conversion to energy, would release (1.2x10^25)*(9x10^16) = approximately 1.1 x 10^42 J = 2.6 x 10^26 Megatons of TNT. This is equivalent to 3 times the Sun's total energy output over its lifetime.

I'm not sure enough of the physics to calculate how far away you'd have to be to avoid being incinerated.

 

[Skeptoid]

Short answer, no.

Long answer, well...

An anti-Earth colliding with our planet, assuming total conversion to energy, would release (1.2x10^25)*(9x10^16) = approximately 1.1 x 10^42 J = 2.6 x 10^26 Megatons of TNT. This is equivalent to 3 times the Sun's total energy output over its lifetime.

I'm not sure enough of the physics to calculate how far away you'd have to be to avoid being incinerated.

Just to add to this, the complete annhilation of an anti-Saturn and Saturn would release ~ 10⁴⁴ Joules; the energy released by a typical supernova.

 

[Hellbound]

Distance from Impact: 5000.00 km = 3105.00 miles
Projectile Diameter: 12756000.00 m = 41839680.00 ft = 7921.48 miles
Projectile Density: 1500 kg/m3
Impact Velocity: 300000.00 km/s = 186300.00 miles/s
Impact Angle: 90 degrees
Target Density: 1500 kg/m3
Target Type: Competent Rock or saturated soil

7.34 x 10^40 Joules = 1.75 x 10^25 MegaTons TNT

Transient Crater Diameter: 1316048.75 km = 817266.27 miles
Final Crater Diameter: 8265967.56 km = 5133165.86 miles

Your position was inside the transient crater and ejected upon impact.

Heh.

That's just the kinetic component, if the applet can even handle numbers of this size. I have a feeling that when the crater diameter is 900 times the diameter of the target body, the calculations break down somewhat.