Let's reconsider just one example of evidence that has already been mentioned repeatedly within this thread.
Observations of type 1a supernovae tell us that, at the time corresponding to z=1.5, the value of the Hubble parameter was approximately 2.7 times as large as H0 (which is, by definition, the current value of the Hubble parameter).
That observed fact that the Hubble parameter has been decreasing counts as strong evidence for the concordance ΛCDM model.
Thanks for the reference.
You "derived" your redshift-distance equation by a combination of (1) equivocating (defining b to be one thing, but later pretending b is "equivalent" to something quite different)...
That's not the derivation. The derivation has nothing to do with "b".
It's in post #896. Came up with it a few days after I submitted the paper.
Here it is:
Both the traditional and alternative redshift-distance equations can be derived from Hubble's law and the traditional redshift equations.
For the traditional redshift-distance equation, start with the definition of redshift in terms of wavelength:
1+z = w_o / w_e
Now multiply both sides by f_e / f_e:
1+z = w_o / w_e * f_e / f_e
The product of w_e and f_e will be c, and the product of w_o and f_e will be a velocity greater than c.
1+z = w_o * f_e / c
To reason what w_o * f_e might be, consider as a toy model, a Newtonian analog of a photon, its source, and an observer. The source will be stationary, and the observer will be moving away from the source at velocity v = H_0 * D, as per Hubble's law.
The photon is emitted at a velocity of c, however, due to the expansion of space, the photon moves with the Hubble flow, giving it a velocity relative to its source c + H_0 * d. Any observer it encounters will also be moving at H_0 * d, so the photon's speed will be c relative to the observer.
This increased velocity of the photon in the toy model represents an elongation of the wavelength combined with its original frequency, and this velocity can be substituted in for w_o * f_e, making:
1+z = (c + H_0 * d) / c
1+z = c/c + H_0 * d / c
z = H_0 * d / c
d = cz / H_0
To derive the alternative redshift-distance equation start with the definition of redshift in terms of frequency:
1+z = f_e / f_o
And this time multiply both sides by w_e / w_e.
1+z = c / (f_o * w_e)
Once again, f_e * w_e = c, but now there is the term f_o * w_e, which is a velocity less than c.
Consider another toy model similar to the previous one, with both the source and the observer stationary. This time, the photon has a velocity of v = c - H_0 * d. Due to the deceleration of the photon, the light travel time of the photon increases equal to the light travel time of a photon in the toy expanding universe. (See Appendix A.)
If the photon's drop in velocity corresponds to a reduction of its frequency, while maintaining its original wavelength, then we can say f_o * w_e = c - H_0 * d, therefore:
1+z = c / (c - H_0 * d)
1/(1+z) = (c - H_0 * d) / c
1/(1+z) = c/c - H_0 * d / c
1/(1+z) - 1 = - H_0 * d / c
-z/(1+z) = - H_0 * d / c
d = c/H_0 * z/(1+z)