Mike Helland
Philosopher
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- Nov 29, 2020
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Doh. Should have used frequency. (THz instead of nm)Wait, what? Red shift moves the spectrum to larger wavelengths, not smaller wavelength.
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Doh. Should have used frequency. (THz instead of nm)Wait, what? Red shift moves the spectrum to larger wavelengths, not smaller wavelength.
That often depends on the instrument. Instruments always have some limit to their resolution, so there's no point to binning much smaller than this resolution. In addition, the smaller the bin size, the fewer counts per bin. If the signal is low, then statistical noise in the number of counts for any one bin can be significant, and larger bins can help smooth out this statistical noise. You can always choose to reduce the number of bins by just combining existing bins.When we do that for the sun, or a nearby galaxy, how many bins are used?
It would definitely be smoother than a spectrum with, say, 4,000 bins. But even smoothed out, at 40 bins it would still noticeably deviate from a blackbody spectrum.If the sun's spectrum was measured using 40 bins, it'd probably smooth out a bunch.
It would be a discrete colletection of 40 energy bins, a discrete spectrum. Photons are already "energy bins", they are discrete packets (quanta) of energy.Suppose an instrument that counted incoming photons and put them into energy bins. And then graph the count of each bin. That would be a spectrum.
Who is even 'hyping' it, let alone over hyping it? It simply is what is observed. The basis of Planck's theory of blackbody radiation is the consideration of the source as a collection of quantized harmonic oscillators that can only emit or absorb energy in discrete packets.When we do that for the sun, or a nearby galaxy, how many bins are used?
And how many are used for the CMB? From this image it looks like 40:
If the sun's spectrum was measured using 40 bins, it'd probably smooth out a bunch.
I'm not saying the CMB is made of star light or galaxy light. And I'm not saying the CMB's near black body spectrum is unimportant or unremarkable.
It could be a little over-hyped though.
I think they rely on a thermal equilibrium to get there.
Would we still see the same line just as clearly in the compressed data when it's 0.45 nm?
It seems to be motivated by what conditions must have led to the high-redshift galaxies we're seeing in the state we observe them.
As an aisde, if ALMA has been operating for 10+ years, how come it didn't find those Little Red Dots? Not in its frequency range or something?
No, he's suggesting the CMB only looks like a black body because we're not taking a proper look.Wait, is Mike saying everything is actually a black body, if scientists actually take a proper look?
Well, yes to the second part. No to the first part.Photons are already "energy bins", they are discrete packets (quanta) of energy.
So the big bang predicted how many passive galaxies between z=3 and z=5 there were, and it's predictions were 20 times too high?The number density of those passive galaxies at z=3-5 is 20 times lower than assumed, even ignoring the huge difference in mass.
Do you have a beef with the authors or something?This is not motivated by observations, it's just a sad attempt to revive some silly MOND inspired and attack the CMB as a cosmological probe.
So the big bang predicted how many passive galaxies between z=3 and z=5 there were, and it's predictions were 20 times too high?
Ah, thanks. That makes more sense.No, this is Gjergo and Kroupa's model.
Fair enough. Since I'm skeptical the big bang even happened, it's not like I agree with their most basic premise, that z>10 galaxies had to form so rapidly.And yes, I have a problem with people publishing nonsense. The data to test their claims already existed, but no attempt to ask if what they propose was really physical. The data already exists to refute it. And basic questions were ignored. Kroupa has a strong bias. He claims in the paper that this model was validated by JWST, but actually it can predict anything. Because it's not coupled to any cosmological simulation it cannot predict number densities. The paper is one thing, but the comment in the article is just totally fallacious and deeply ignorant.
The first part is dictated by the second part.Well, yes to the second part. No to the first part.
You're missing the point. 100 nm would be an energy of 12,398 meV while 101 nm would be 12,276 meV. If you are measuring energy and your resolution > 122 meV they both end up in the same energy reading bin. Further if you are measuring energy you can only determine frequency (1/t) to ΔE * Δt ≥ ħ/4π. Photons are produced in discrete packets by physical processes and measured in discrete packets by often differing physical processes. They are produced in bins by said physical processes and received into likely different bins by different physical processes with resolution and uncertainty thrown in on top of that. So can you stack the receiving bins to say load the deck to get results more to one's liking? Sure, but it is meaningless as just the measurement process forces some such bias aspects on the data. The trick to try to control for and even move away from some particular bias and then see if the data still support the hypothesis.A photon's energy is E=hf or E=hc/w.
The wavelength could be 100 nm or 101 nm, or literally anywhere in between. Light comes in chunks, but those chunks can be of any energy level.
Ah, thanks. That makes more sense.
Fair enough. Since I'm skeptical the big bang even happened, it's not like I agree with their most basic premise, that z>10 galaxies had to form so rapidly.
Unless there was a boundary between bins at 12,300.100 nm would be an energy of 12,398 meV while 101 nm would be 12,276 meV. If you are measuring energy and your resolution > 122 meV they both end up in the same energy reading bin.
Doesn't a black body have a continuous spectrum?They are produced in bins...
I have no idea what sort of boundary you are imagining.Unless there was a boundary between bins at 12,300.
A perfect black body does, yes.Doesn't a black body have a continuous spectrum?
The observer defines their bins. They could between 1 and 2 and 3, etc, or 1.05 and 1.55. Nothing says they have to be nice round numbers.I have no idea what sort of boundary you are imagining.
A perfect black body does, yes.
Sure. But I'm not sure how that changes The Man's point in regards to instrumental resolution. If your instrument's resolution is larger than the difference between two photons, you cannot effectively put them in separate bins.The observer defines their bins. They could between 1 and 2 and 3, etc, or 1.05 and 1.55. Nothing says they have to be nice round numbers.
If your instrument's resolution is larger than the difference between two photons, you cannot effectively put them in separate bins.
Correct.Which bins you choose will affect your results. Of course, with enough data, statistically that all washes out.
It's possible, I don't specifically remember.In any case, the idea that quantum means the energy a photon can have comes from a discrete set of values is a mistake I've made in the past, and it's very possible you were the one that corrected me on that point back then.
In regards to the CMB, we have enough statistics to show it's an incredible fit to a black body spectrum, much better than any stellar body.
Huh. Well, that I'd like to see.No, it would be worse.
If it were easy to make something black in the long wavelength of the spectrum, stealth aircraft would be common. As it is, not only are they not common, they aren’t even black, only dark grey in those wavelengths. You don’t get anything even close to just 100 ppm reflectivity.Huh. Well, that I'd like to see.
COSMOS-Web Public Data Release 1
This page hosts the version 1.0 public data release for COSMOS-Web, including:
And look at all the weird noise between all those things. Is that all just noise?
Would it really be that much of a surprise if the next generation of telescopes, or even just super-extended exposures with JWST reveal that some, or even a lot of that noise is actually more galaxies?
Another way to put it is, if you simply had to guess, how many of the galaxies that are theoretically observable do you think have been observed?
We can simplify the question by saying not over the whole sky, but in the field depicted by COSMOS-Web DR1
Isn't that in the "we'll take your word for it" territory?The answer is probably dozens.
Most of the noise in the MIRI data for example is smaller than the point spread function, so cannot be real galaxies.
Most of the noise in the MIRI data for example is smaller than the point spread function, so cannot be real galaxies.
No. There is deeper data of many fields. COSMOSWeb is quite shallow in comparison. How many galaxies are detected is a statement about the current data, relative to the current noise.Isn't that in the "we'll take your word for it" territory?
Yes, that is what I said.Doesn't it seem possible we won't see just a little more with a better telescope, but a lot more? Like we always do?
Even a point source like a star shows up on the image with some minium size set by the limiting angular resolution of the telescope. Any real object cannot be smaller than that. Individual noisy pixels are not real sources.Can you explain why that is?
Ok. Does that require a constant stream of photons?Even a point source like a star shows up on the image with some minium size set by the limiting angular resolution of the telescope. Any real object cannot be smaller than that. Individual noisy pixels are not real sources.
What about ice?If it were easy to make something black in the long wavelength of the spectrum, stealth aircraft would be common. As it is, not only are they not common, they aren’t even black, only dark grey in those wavelengths. You don’t get anything even close to just 100 ppm reflectivity.
No. If you don't have enough photons to see the spatial extent, then it's probably not significantly detected above the noise anyway.Ok. Does that require a constant stream of photons?
That is not a good standard spectrum. Most of the very high redshift galaxies being observed are Lyman break galaxies, where NIRCam and NIRSpec cover the rest-frame UV. LBGs have steep blue UV spectra, unlike the rest spectrum of M31. Meaning they are brighter in bluer wavelengths. The LBGs are highly star-forming low-mass galaxies, compared to the massive almost-quenched M31.Then at z>12 the only stuff NIRCam would see is that <4000 Å range.
Compared to the strength and (relative) consistency of the visible spectrum, anything there would appear very noisy.
That's just me jumping to conclusions as a layman. Is that unreasonable / inaccurate?
If there was a wall of hydrogen around the solar system, that also happened to contain billions or trillions of ice crystals, and it's been heated to ~3 K based on starlight from the rest of the galaxy (as Eddington calculated in the early 1900's), what would that look like to us?
That would require something like a solid shell of ice around the solar system to block all of that out though, wouldn't it?If the source of the CMB was local (as in, around our solar system), then regardless of what it was made of, it would block microwave signals from beyond our solar system. That's the nature of blackbodies: in order to emit a blackbody spectrum, they also have to absorb everything.
But we see more distant microwave sources. They aren't being blocked. So the source of the CMB cannot be local.
Not solid, but optically opaque, yes. As in, no line of sight without going through whatever that is.That would require something like a solid shell of ice around the solar system to block all of that out though, wouldn't it?
Then it cannot produce a black body spectrum averaged over the sky even if each object is a perfect black body. The intensity would be too low. It would look like a grey body.Even with a trillion ice crystals surrounding the solar system, there would be plenty of room in between them for other light and microwaves to get through.
No. If you don't have enough photons to see the spatial extent, then it's probably not significantly detected above the noise anyway.
That is not a good standard spectrum. Most of the very high redshift galaxies being observed are Lyman break galaxies, where NIRCam and NIRSpec cover the rest-frame UV. LBGs have steep blue UV spectra, unlike the rest spectrum of M31. Meaning they are brighter in bluer wavelengths. The LBGs are highly star-forming low-mass galaxies, compared to the massive almost-quenched M31.
The CMB frequencies are no where near optical light, so that seems to be superfluous stipulation.Not solid, but optically opaque, yes. As in, no line of sight without going through whatever that is.
But that's required to produce a blackbody spectrum. If our solar system was surrounded by black body objects that only covered half the line of sight, then it would produce a spectrum only half the intensity of a black body. Because it's not just the shape of the curve, the height of the curve matters too.
Then it cannot produce a black body spectrum averaged over the sky even if each object is a perfect black body. The intensity would be too low. It would look like a grey body.
This is why we know that the CMB cannot be local, regardless of what it's made out of. Even a hypothetical material that's transparent in every wavelength except microwave, and it's a perfect blackbody in microwave, still wouldn't match observations.