jt512
Philosopher
- Joined
- Sep 24, 2011
- Messages
- 5,566
We agree that the probability of Jabba's existence is 1. That would be P(Me) = 1.
Again, briefly, you are confusing the term P(me) in Bayes' formula with P(me|me). To put it another way, the probability that you are saying is 1 is the probability of Jabba's existence given that we know he exists. But such a probability does not appear in Bayes' formula. Rather (and Toontown is basically correct on this), the term P(me) in Bayes' formula is the weighted average of the conditional probabilities that "me" would be observed under each hypothesis, where the weights are the prior probabilities of those hypotheses. If Jabba's model "A" is that "me" is a random event, then P(me|A) is not 1, but some small number. That, in turn, implies that P(me) is less than 1.
The problem with Jabba's analysis (well, one problem) is that neither P(me|A) nor P(me|~A) belongs in the analysis, because "me" is not what either A or ~A predicts. Rather, what A (to the extent that it has been defined) predicts is that the population of humans at any particular moment in human history will be a ragtag assortment produced by more-or-less random sperm–egg pairs, and what ~A (to the extent that it has been defined) predicts is that the population (the entire population, not just "me") had been somehow pre-selected.
In my view the data are in better agreement with A than ~A.
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