Checkmite
Skepticifimisticalationist
This is a massive achievement.
Sheesh, tough crowd...
This is a massive achievement.
Wouldn't a black hole be a singularity if it were all those particles together in the smallest volume possible?... are you referring to simply forgoing the intervening space and putting all those particles together into the smallest volume possible? If so, then I have to agree with the statement above that you're likely moving towards something akin to either a neutron star or black hole.
Are neutron stars the same density as black holes? (I know the BH has more mass unless it evaporates or whatever they do.)
Black holes = infinitely dense?
We tend to view solid things as taking up the amount of space that their visible mass occupies. But there's a lot space between the molecules, and a lot of space between the protons and electrons within the molecules and a lot of space between the particles that make up the protons and neutrons and so on. I was just wondering what you'd have left if you squeezed all the proverbial air out of the molecule balloons.
Very large black holes have effectively infinite volumes. A completely classical (nonevaporating) black hole has infinite spatial volume.If you define density for a black hole as mass divided by volume enclosed by the event horizon then black holes have finite density. And they can come in a very wide variety of densities, including as low density as hydrogen gas here on Earth if they are very large black holes.
You're not applying the definition of volume that would most commonly be used to determine a black holes density, are you?Very large black holes have effectively infinite volumes. A completely classical (nonevaporating) black hole has infinite spatial volume.
I am. There is an ambiguity for black holes because we're taking the volume of a spatial region at some instant in time, and the 'instant in time' is frame-dependent, but allowing for some small caveats my statement was correct.You're not applying the definition of volume that would most commonly be used to determine a black holes density, are you?
If you're applying the most common definition of volume used to compute black hole density then why aren't black hole density citations a lot closer to zero?I am. There is an ambiguity for black holes because we're taking the volume of a spatial region at some instant in time, and the 'instant in time' is frame-dependent, but allowing for some small caveats my statement was correct.
At a guess, they have a specialized definition of density disconnected from physical volume of a spatial region. Why?Neither of those density citations appear to be using a nearly infinite volume for Sagittarius A*.
Sheesh, tough crowd...
The "specialized version" they appear to be applying would be the mass divided by the volume of a sphere using the formula taught in elementary school (such school's typically located outside of black holes).At a guess, they have a specialized definition of density disconnected from physical volume of a spatial region. Why?
Alright. That's rather specialized because, as I've said, that formula has absolutely nothing to do with the spatial volume of the region enclosed by the horizon. It may give an empirically interesting measurement (in fact it's just a rescaling of surface area), but it is not the volume in any physically meaningful sense.The "specialized version" they appear to be applying would be the mass divided by the volume of a sphere using the formula taught in elementary school (such school's typically located outside of black holes).
In fact, it leads to a perfectly good answer to the question that was asked by Skeptic Ginger.Alright. That's rather specialized because, as I've said, that formula has absolutely nothing to do with the spatial volume of the region enclosed by the horizon. It may give an empirically interesting measurement (in fact it's just a rescaling of surface area), but it is not the volume in any physically meaningful sense.
I'm not in any way contradicting that large black holes can be reasonably said to have low density, since they're actually defined by the horizon and not the singularity. I'm simply saying your conclusion was even more true than you suggested.In fact, it leads to a perfectly good answer to the question that was asked by Skeptic Ginger.
Incidentally my jaw nearly fell off this morning when the BBC posted an article online that got it spot on - it's such a common error it's honestly astounding when the media gets it right!
They claimed that by combining two data sets, they had attained a confidence level just at the "five-sigma" point - about a one-in-3.5 million chance that the signal they see would appear if there were no Higgs particle.
However, a full combination of the CMS data brings that number just back to 4.9 sigma - a one-in-two million chance.
Prof Joe Incandela, spokesman for the CMS, was unequivocal: "The results are preliminary but the five-sigma signal at around 125 GeV we're seeing is dramatic. This is indeed a new particle," he told the Geneva meeting.
Okay, sorry. I think in the context of the original question we're having an "I think our minds may be too highly trained Majikthise" moment.
The Higgs boson is an unstable (something like 10^-25 seconds) particle whose interactions are, in the context of the Standard Model, 100% known.